Look at the balanced chemical equation. In the case that you mention, there would only be products, and no leftover reactants. In this case you would have a solution of NaCl. Sodium ion and chloride ion don't have acidic or basic properties, so the pH would be that of water.

Hooray for chemistry success! Glad that you found it helpful. Good luck with the remainder of your term.

Good show! Glad you got past it. Just in time for finals! Happy you found it helpful.

Good show! I hope the rest of the term goes well for you.

If you're talking about MgI2, it is because magnesium forms a +2 ion, and iodine forms the -1 iodide ion. Therefore, the formula requires a ratio of two iodide ions to one magnesium ion.

Hooray for chemistry! Glad you found it helpful.

@@JeffLehmanJL omg you here

Good show!

You are very welcome!

Abou lt this

pH=5???

Hooray for chemistry!

My how time flies! You're welcome. Glad you found it helpful.

You are correct, shortcuts abound! However, these videos are geared toward those learning the topic for the first time. I've found that skipping steps, and applying short-cuts can often confuse first time students. Once the concept has been learned, learning short-cuts can be very helpful.

You are welcome!

Still here....Chemistry just gets better with age.

Hooray for Chem Life!

What does it mean when the equation says: with an excess of _______

You are welcome

@@claretershy3491 It means that you have more than enough of whatever is in excess. If it didn't say excess, but gave a quantity, then you would have to figure out which is the limiting reactant.

Glad it helped! Hope the rest of your semester goes well.

It's all about practice for these sorts of things...

@@JeffLehmanJL Cool!

Hoooray! You're welcome!

Hooray! Same chemistry, so it still works. Glad you found it helpful.

@@JeffLehmanJL You're actually replying to comments 12 years later!?! Awesome! I can agree, this helped me more than my textbook as well!

You are very welcome. Glad you found it helpful, and I hope that your class worked out well.

You are very welcome. Glad you found it helpful.

Chemistry is timeless!

Thank you very much for the kind words. I'm glad that you found it helpful.

I've found "easy" to be a relative term. I am not sure of the definition of your variables, but it is probably the same thing. However, I like to leverage previous expertise with dimensional analysis.

@@JeffLehmanJL It is the same thing and I meant easier by which it consumes much less time. For the variables small n= Moles m= Mass And Ar or Mr Ar= atomic mass and Mr is the relative molecular mass. I believe this is called the mole triangle formula

The factor of 2 comes from the balanced equation. The stoichiometric coefficients.

@@JeffLehmanJL oh.....thank you

Ah, good question. There is a difference between "dilute to" and "dilute with". "Dilute to" means that the diluted volume is the new volume. "Dilute with" means that the two volumes are additive.

Thank you so much

Yes it is. I am glad that you found it helpful. Let's hope school is back to "normal" in the fall.

im doing this in school you doing the same thing in college?!

Saksham Sharma took intro to chem

@@applesthecat okie

@@sakshamsharma5824 ikr how do they expect us to do this in highschool we're just kids 😭😭

That is very kind of you to say. I am glad that you found this helpful. Take care.

Well I need help how many grams of O2 is needed to react with 7.50g of ethanol how do I set that up

That is correct. I did not account for leap years. However, the problem is good to two significant figures, so those seconds from the leap years don't change the answer expressed to that precision.

Yep. Good eye.

Yep, there is additional work. NaCN will dissociate into Na+ and CN-. Then CN-, being a weak base (the conjugate base of a weak acid HCN) will react with the water to form HCN. This will tie up some of the CN- as HCN, and the remaining CN- will be in solution. You'll need the Ka of HCN to solve this. Ka = [CN-] [H3O+] /[HCN]. The problem gives you the H3O+ concentration, so with that you should be able to calculate the CN- concentration. Think about the H3O+/CN- ratio in the balanced equation.

Yep! I missed the zero when I wrote down the molar mass of Ca.