1:41 😂

A duet with Vi Hart would simply be too much power to be contained within the known universe

where is his chinese chanel ?

19:36 i think homework with solution shoukd be included in the list

Excuse me, Grant sir, In the book 'Solving mathematical problems. A personal perspective from Terence Tao' In exercise 2.2 of that book, Find the largest positive integer n such that (n³ + 100) is divisible by n + 10. (Hint: use (mod n + 10). Get rid of the n by using the fact that n = −10 (mod n + 10).) Don't you think that this question must ask find the largest a-digit number instead of asking find the largest, because I got answers to that question which are, 90, 990, 9990, 99990 , and so on How can one tell the largest which is 999999............90 ?? Or am I wrong with my answer??

Great material. Congratulations it exceeded my expectations and spent a good moment listebing !

Standupmaths, 3blue1brown, acapellascience in one video? Music and math? This is my favourite video in KZfaq 😭

GRANT CAN SING TOO?

Now I know where your name comes from :)

You mentioned that it would be great if there were emojis in the margins of textbooks to help with understanding. In the Park City Math Institute (PCMI) problem sets used in their math teacher seminars, there are those sorts of comments (sadly, no emojis) in the margins. Sometimes they’re there for humor, but other comments are informative. I really like them!

Can we get a studio version please!!?!

Pretty sure this constitutes a rigorous mathematical proof of the twin primes theorem.

2:39 tim's singing here is killer and i refuse to let it go under yall's radars

So clever!

Hey Grant. I'm a Caltech grad with a similar Erdös number as you, I would assume, You don't need me, and I don't need you, but I like music and humor similar to yours... I don't know why or what we would discuss, but I feel like we should mesh.... If you are ever in Phoenix, especially if you want to see the MIM....

Finally, something to top "finite simple group of order 2"!

Hey Grant, this is my first time seeing you on camera haha. I took my first calculus class this last semester. After studying for my final, my KZfaq algorithm was filled with calculus. I started to watch it for entertainment, even after my final. The videos that helped make that click for me was your videos. You have truly helped rekindle my love for math, and even made me consider changing my major to math. So thank you so much, never stop makeing videos!!

Well, this was fun.

Infinity twin primes is easier to prove than many other things. Basically, each prime has its own pattern, and no 2 primes can ever resemble eachother, so you can't consistently have certain things not line up. Not having infinitely many twim primes means having infinitely many different patterns all line up to the same frequency, which is impossible.

fabulous, grant!

Something. black background. Or Pi creatures

I have a truly marvelous proof of the twin primes conjecture which this youtube comment box is too narrow to contain...

so inspiring!!!!

Love you guys, I really do

That was FUCKING AWESOME!!!!!!

Is that stand up maths in the back

I am quite jealous that I can't do such amazing things😢

I had a very elegant notation for this song but I think I lost it when my old hard drive died 😢

Oh, too cool! I love blues, and I'm a bit of a maths nerd, so when YT offered this up for me to watch, I was intrigued. It did NOT disappoint! 😂 Love it, now I'm going to go look for more of the same!

654321 happy new year!😂🎉

Here is Lawrence Abas' (2024 Aurora Ontario Canada) simple proof of infinite twin primes previously published on Linked-In with no current disputes. This negative proof considers that a largest-twin-prime pair can only exist if there are a finite number of primes, which creates a paradox. Trying to prove that there is a finite number of twin primes leads to this paradox. If there were a finite number of primes, the maximum twin prime would be easy to calculate the result of multiplying that set of primes (I call it a prime factorial) plus one or minus one. This this would produce two new numbers that cannot be in that set or have factors that are in that set. Since this makes new prime numbers that are not in the set or composite numbers that have factors that are not in that set a paradox exists. Consider a finite set a set of unique sequential prime numbers where each element is multiplied together. The result minus one, and result plus one cannot be an element in that set. Example: (2,3,5, 7) 2 x 3 x 5 x 7 = 210 210-1=209, 210+1=211. 209 is 11x19 and 211 is prime. 11, 19, and 211 are primes that are not in the set (2,3,5,7). This creates a contradiction as in Euclid's proof of infinite primes, that any finite set of prime numbers can be used to find more prime numbers. When sequential primes are used this ensure the factors found are greater any prime in the set. Note that the set of numbers described by n x 210 +/- 1 where n is a natural number from 1 to infinity, are twin prime candidates and guarantees that it cannot have the factors 2,3,5, and 7, not that any pair is a twin prime. Since we know from Euclid that an infinite number of primes exist, the maximum twin primes is on n x (the result of all prime numbers multiplied, which is infinity) plus one and minus one. Where n is a natural number from 1 to infinity. Any natural number multiplied by infinity is infinity, and infinity plus or minus one is still infinity. Therefore, the largest twin prime is infinite. This negative proof is essentially identical to Euclid's proof of infinite primes except that +1 is changed to +1 and -1 below: Consider any finite list of prime numbers p1, p2, ..., pn. It will be shown that at least one additional prime number not in this list exists. Let P be the product of all the prime numbers in the list: P = p1p2...pn. Let q = P + 1 and Let r = P - 1: Then q or r is either prime or not: · If q or r is prime, then there is at least one more prime that is not in the list, namely, q itself. · If q or r is not prime, then some prime factor p divides q. If this factor p were in our list, then it would divide P (since P is the product of every number in the list); but p also divides P + 1 = q, as just stated. If p divides P and also q, then p must also divide the difference of the two numbers, which is (P + 1) − P or just 1. Since no prime number divides 1, p cannot be in the list. This means that at least one more prime number exists beyond those in the list. · If q and r are primes then there then there is at least two more primes that are not in the list, namely, q and r itself being a twin prime. This proves that for every finite list of prime numbers there is a prime number not in the list. Quite simply, a maximum twin prime cannot exist with an infinite set of prime numbers.

Love that there was something to (slant) rhyme with Eratosthenes!

The voice 😂

Didn't know Bill Withers was a fan of binary...1010101010 😂

Great voices, nice playing but the lyrics were a bit off :) Some parts fit really well (or course the 10 10 10 part was spot on) but others were a bit clunky. Though this is not meant as critique. I know it's insanely hard to retrofit lyrics to an existing song, especially with technical math lang :) Overall I really enjoyed the performance +1 ps: "How They Fool Ya" was also brilliant.

This is the cringiest nerdiest shit I’ve ever seen in my life. Keep posting! ❤

But why is his leg shaking?

🔥🔥🔥

Everytime I come back to this video I catch myself trying to like it again lol 😆

I miss her ❤

What can't this guy do?

is this math rock?

I swear ive watched this video waaay too many times… and i will continue to do so!

Exactly

Legitimately incredible.

wow, so cool

The best since Tom Lehrer

You guys just casually drastically raised the standard for videos to show in high school math classes

Wow!

Brilliant!