Great explanations! I try to calculate power losses on diode during time but I did not make it. Current passing through the diode increasing temperature which has impact on voltage. Voltage is not constant as usualy predict.
@ogginger4 ай бұрын
The audio is very painful.
@asmaazugari8065 ай бұрын
it's 1st order stop band filter ??
@Doorfingers1017 ай бұрын
Thanks for the homework help Lee!!!!!!!!
@follenlearning44317 ай бұрын
but why do we want such a big input resistance??
@edvargas31057 ай бұрын
Great video and excellent explanation. The background ruins it.
@winim018 ай бұрын
If I tell u that my lecturer did not teach us this but only told us to memorize them would u believe me? Like he did not explain how it became like that.
@nityanandadas557510 ай бұрын
Nice . You have assumed the current flowing into the op amp to be zero. That means the opamp is ideal. For such a case , I think , the open loop gain Ao is infinite. Am I right ?
@nityanandadas55759 ай бұрын
@@chitretanaymilind3178 Thanks for your reply.
@bhaiyajismile10 ай бұрын
How can you say like no amount current is entering in to the opamp, in this case!!
@steveshu5817 Жыл бұрын
Thanks a lot, I can be fully prepare to the exam in tomorrow
@rul1175 Жыл бұрын
The amplification would be (AC - 0.6v + Vcc)??? Wouldn't the current flow to ground when AC activates the NPN??? or is that the reason why the gain is inverted?
@panthopothik6338 Жыл бұрын
what a simple explanation! You sir are a great explainer! Thanks
@AlanCanon2222 Жыл бұрын
Note that, under "active low" logic, the same circuits described above still work, but with the sense of AND and OR reversed. (Consequence of De Morgan's laws).
@prasadchabbi6065 Жыл бұрын
Hi, Please take 0.7 V into consideration to turn on the Diode.
@SarvanandHariPrabodham Жыл бұрын
18Id^2 -24Id +8 >> Id should have only one root, which should be Id = 0.667. Please correct me if I am wrong.
@nithin1729s Жыл бұрын
Thanks Cleared all my doubts
@marknesselhaus4376 Жыл бұрын
Good standard explanation for DDL but in the past few years I have been creating all Boolean logic gates using Led's and CdS photo resistors so the gate is still DDL but also Inverts and the logic levels do not degrade. Light Logic
@QaziTalhaShorts Жыл бұрын
thanks man
@zongshenghe8027 Жыл бұрын
牛逼
@numansiddique9483 Жыл бұрын
thanku
@KingHassanGaming Жыл бұрын
thank you
@aliaatarek7106 Жыл бұрын
Clear To the point Well done
@theexecutioner8181 Жыл бұрын
Best video ever on this topic...thanks a lot sirrr
@remzialtparmak9070 Жыл бұрын
Thank you !
@gkdresden Жыл бұрын
Usually the voltage at the base of transistors will not go lower than -6 to -8 V. Lower voltages will exceed the typical avalanche breakdown voltage of the base to emitter diode. This is also the reason why the time periods of such astable multivibrators tend to get shorter or the frequencies tend to get higher, the higher the operating voltage is. It is therefore not recommented to exceed 5 V operating voltage, especially in the case of larger capacitors (muliple 100 µF). The energy of the charge can evtl damage the base emitter diode.
@TheVeemon Жыл бұрын
Thanks for the help, understood how diodes works in less than 10 minutes
@muazzimmokhtar35852 жыл бұрын
why 0.25 ?
@peatmoss44152 жыл бұрын
Thanks, this helped me take a nap!
@electronic102 жыл бұрын
Thanks a lot ! Your videos are awesome!
@marwaatta91862 жыл бұрын
Nice
@alzmanyasahib2 жыл бұрын
Can I have the name of source please
@skm22 жыл бұрын
I have an exam tomorrow in this sup and i don't understand 2022 Tue ,May 17
@OnerousEthic2 жыл бұрын
That is just brilliant! I first saw that over 35 years ago, and it still impresses me today… 0:34 “…but the source is in parallel with that 6 ohm…”. Shouldn’t that be “in series”?
@champ21332 жыл бұрын
Thank you sir
@mryourselife42102 жыл бұрын
12
@ambushtunes2 жыл бұрын
I finally got it
@joeb.fromsydneyaustralia53132 жыл бұрын
Excellent explaination - I checked out a few other KZfaq videos and only yours made any sense to me - and it did so by 1:20....Thanks so much!
@tassaneekeatjan97592 жыл бұрын
Very good and funny videos bring a great sense of entertainment!
@victoraugusto27212 жыл бұрын
Thank you so much bro, you help me a lot to understand this subject, finally a understood how works and get the Vt on this calculus, thanks again!!!!
What is meant by steady-state in a capacitive circuit subject to a sinusoidal voltage input? A sinewave depicts movements in the form of waves. It has a datum, rapid, slowing and steady growth in one direction for a quarter cycle with reference to a datum (a reference), and then slow and faster decay in one direction for the next quarter cycle, and all these elements again in the opposite direction (reversal) of the forward movement for the next half-cycle. It has peaks and valleys. In essence, the sinewave is a perfect embodiment of oscillatory movements like springs and quantities like voltage. It retains its waveshape when added to another sinewave of the same frequency and arbitrary phase and is the only periodic waveform which has this property. Imagine that you and your friend are playing a game of “swing”. When your friend sits on a stationary swing and you begin pushing it, it will take a few hard pushes initially to overcome inertia when the swing moves with a small displacement. You then synchronize your pushes by progressively moving slightly away from the stationary position of the swing, initially, pushing gently, and then pushing harder as you move away from the central stationary position of the swing. The point of pushing the swing is usually at the top of the swing cycle at one end. It takes a while of pushing before you are able to establish a rhythmic swing. The period before the rhythmic swing is established is the “transient”, and the rhythmic swing that is established after the few transient cycles elapse is the “steady-state”. This is analogous to establishing the steady-state in a capacitive circuit subject to a sinusoidal input. The capacitor being initially uncharged, will cause the current during the transient period to assume a value that will be quite different from that at the same voltage angle after steady-state is established. Electrostatics and circuits belong to one science, not two. These are discussed usually separately in textbooks and science and engineering courses. It is not possible to discuss the circuit processes which produce a sinusoidal current when a sinusoidal voltage is applied to a capacitor….the changing rates of change of the applied voltage ….the surface charge set up changing at every instant….the applied field changing in the wires ….and the current at each and every instant in time. Watch the two videos listed below to learn about current and the conduction process and surface charges (using a unified approach to electrostatics and circuits at a fundamental level). 1. kzfaq.info/get/bejne/iKujiseVnJzVqJc.html 2. kzfaq.info/get/bejne/bqiBgMKp3Ji2lqM.html The last frame of video #1 lists textbook 4 which discusses the sinusoidal steady-state in capacitors and inductors with the help of sequential diagrams and animated power-point presentations of the varying field components in the circuit elements in more detail.
@pk_star78622 жыл бұрын
Nice explained
@kjh98zzang2 жыл бұрын
this helped a lot thanks!
@honestman2762 жыл бұрын
Thanks. From Bangladesh.
@emre-uc1zh2 жыл бұрын
hello, on a 11/0.4 KV three-phase transformer; 11000V coming to the high voltage coil? because there is resistance inside each coil. Then I can't get 11000 output? then 400V cannot be induced. Can you explain how
@improvisationalcommenting97522 жыл бұрын
It sounds like someone is writing on a pad in the background through the whole video