RC Example 2 Simple Step Response
9:01
RC Example 1 Simple Natural Response
6:34
Welcome Video
5:28
4 жыл бұрын
Example State Space Analysis
16:58
5 жыл бұрын
E10 1Load Power Calculations
16:12
7 жыл бұрын
E8 2 3Initial Conditions
11:06
7 жыл бұрын
E6 4 2Example 6 11 DC 2 Stage
13:13
8 жыл бұрын
L10109 1 Astable Multivibrator
18:23
8 жыл бұрын
L10108 1 Transistors
19:42
8 жыл бұрын
L10106 1Operational Amplifiers
13:50
8 жыл бұрын
L10101 3Parallel and Series
9:31
8 жыл бұрын
L10101 4Metric Prefixes
4:44
8 жыл бұрын
L10101 2Ohms Law
9:22
8 жыл бұрын
L10105 1Semiconductor PN Junction
20:59
L10105 2Analyzing Diode Circuits
11:48
EulersFormula
7:08
8 жыл бұрын
L10104 2jCapacitors and Non Periodic
19:24
L10104 3Hi and Low Pass Filters
4:34
L10104 1Periodic Signals
7:21
8 жыл бұрын
L10103 2
15:27
8 жыл бұрын
L10102 3Variable Resistors
2:58
8 жыл бұрын
Пікірлер
@jeremiahhill5168
@jeremiahhill5168 22 сағат бұрын
hi hi
@Awakened_Pot
@Awakened_Pot 21 күн бұрын
Only If I had come across this video last week :(
@schoolgirl2712
@schoolgirl2712 3 ай бұрын
Thanks
@DejanCvijetic-sq1hz
@DejanCvijetic-sq1hz 3 ай бұрын
Great explanations! I try to calculate power losses on diode during time but I did not make it. Current passing through the diode increasing temperature which has impact on voltage. Voltage is not constant as usualy predict.
@ogginger
@ogginger 4 ай бұрын
The audio is very painful.
@asmaazugari806
@asmaazugari806 5 ай бұрын
it's 1st order stop band filter ??
@Doorfingers101
@Doorfingers101 7 ай бұрын
Thanks for the homework help Lee!!!!!!!!
@follenlearning4431
@follenlearning4431 7 ай бұрын
but why do we want such a big input resistance??
@edvargas3105
@edvargas3105 7 ай бұрын
Great video and excellent explanation. The background ruins it.
@winim01
@winim01 8 ай бұрын
If I tell u that my lecturer did not teach us this but only told us to memorize them would u believe me? Like he did not explain how it became like that.
@nityanandadas5575
@nityanandadas5575 10 ай бұрын
Nice . You have assumed the current flowing into the op amp to be zero. That means the opamp is ideal. For such a case , I think , the open loop gain Ao is infinite. Am I right ?
@nityanandadas5575
@nityanandadas5575 9 ай бұрын
@@chitretanaymilind3178 Thanks for your reply.
@bhaiyajismile
@bhaiyajismile 10 ай бұрын
How can you say like no amount current is entering in to the opamp, in this case!!
@steveshu5817
@steveshu5817 Жыл бұрын
Thanks a lot, I can be fully prepare to the exam in tomorrow
@rul1175
@rul1175 Жыл бұрын
The amplification would be (AC - 0.6v + Vcc)??? Wouldn't the current flow to ground when AC activates the NPN??? or is that the reason why the gain is inverted?
@panthopothik6338
@panthopothik6338 Жыл бұрын
what a simple explanation! You sir are a great explainer! Thanks
@AlanCanon2222
@AlanCanon2222 Жыл бұрын
Note that, under "active low" logic, the same circuits described above still work, but with the sense of AND and OR reversed. (Consequence of De Morgan's laws).
@prasadchabbi6065
@prasadchabbi6065 Жыл бұрын
Hi, Please take 0.7 V into consideration to turn on the Diode.
@SarvanandHariPrabodham
@SarvanandHariPrabodham Жыл бұрын
18Id^2 -24Id +8 >> Id should have only one root, which should be Id = 0.667. Please correct me if I am wrong.
@nithin1729s
@nithin1729s Жыл бұрын
Thanks Cleared all my doubts
@marknesselhaus4376
@marknesselhaus4376 Жыл бұрын
Good standard explanation for DDL but in the past few years I have been creating all Boolean logic gates using Led's and CdS photo resistors so the gate is still DDL but also Inverts and the logic levels do not degrade. Light Logic
@QaziTalhaShorts
@QaziTalhaShorts Жыл бұрын
thanks man
@zongshenghe8027
@zongshenghe8027 Жыл бұрын
牛逼
@numansiddique9483
@numansiddique9483 Жыл бұрын
thanku
@KingHassanGaming
@KingHassanGaming Жыл бұрын
thank you
@aliaatarek7106
@aliaatarek7106 Жыл бұрын
Clear To the point Well done
@theexecutioner8181
@theexecutioner8181 Жыл бұрын
Best video ever on this topic...thanks a lot sirrr
@remzialtparmak9070
@remzialtparmak9070 Жыл бұрын
Thank you !
@gkdresden
@gkdresden Жыл бұрын
Usually the voltage at the base of transistors will not go lower than -6 to -8 V. Lower voltages will exceed the typical avalanche breakdown voltage of the base to emitter diode. This is also the reason why the time periods of such astable multivibrators tend to get shorter or the frequencies tend to get higher, the higher the operating voltage is. It is therefore not recommented to exceed 5 V operating voltage, especially in the case of larger capacitors (muliple 100 µF). The energy of the charge can evtl damage the base emitter diode.
@TheVeemon
@TheVeemon Жыл бұрын
Thanks for the help, understood how diodes works in less than 10 minutes
@muazzimmokhtar3585
@muazzimmokhtar3585 2 жыл бұрын
why 0.25 ?
@peatmoss4415
@peatmoss4415 2 жыл бұрын
Thanks, this helped me take a nap!
@electronic10
@electronic10 2 жыл бұрын
Thanks a lot ! Your videos are awesome!
@marwaatta9186
@marwaatta9186 2 жыл бұрын
Nice
@alzmanyasahib
@alzmanyasahib 2 жыл бұрын
Can I have the name of source please
@skm2
@skm2 2 жыл бұрын
I have an exam tomorrow in this sup and i don't understand 2022 Tue ,May 17
@OnerousEthic
@OnerousEthic 2 жыл бұрын
That is just brilliant! I first saw that over 35 years ago, and it still impresses me today… 0:34 “…but the source is in parallel with that 6 ohm…”. Shouldn’t that be “in series”?
@champ2133
@champ2133 2 жыл бұрын
Thank you sir
@mryourselife4210
@mryourselife4210 2 жыл бұрын
12
@ambushtunes
@ambushtunes 2 жыл бұрын
I finally got it
@joeb.fromsydneyaustralia5313
@joeb.fromsydneyaustralia5313 2 жыл бұрын
Excellent explaination - I checked out a few other KZfaq videos and only yours made any sense to me - and it did so by 1:20....Thanks so much!
@tassaneekeatjan9759
@tassaneekeatjan9759 2 жыл бұрын
Very good and funny videos bring a great sense of entertainment!
@victoraugusto2721
@victoraugusto2721 2 жыл бұрын
Thank you so much bro, you help me a lot to understand this subject, finally a understood how works and get the Vt on this calculus, thanks again!!!!
@dinosakic455
@dinosakic455 2 жыл бұрын
i got du2/dt = -1/C2(1/Rg + 1/R1)u2 + (1/R1C2)u1 + (1/RgC2)ug - (1/C2)il
@sridharchitta7321
@sridharchitta7321 2 жыл бұрын
What is meant by steady-state in a capacitive circuit subject to a sinusoidal voltage input? A sinewave depicts movements in the form of waves. It has a datum, rapid, slowing and steady growth in one direction for a quarter cycle with reference to a datum (a reference), and then slow and faster decay in one direction for the next quarter cycle, and all these elements again in the opposite direction (reversal) of the forward movement for the next half-cycle. It has peaks and valleys. In essence, the sinewave is a perfect embodiment of oscillatory movements like springs and quantities like voltage. It retains its waveshape when added to another sinewave of the same frequency and arbitrary phase and is the only periodic waveform which has this property. Imagine that you and your friend are playing a game of “swing”. When your friend sits on a stationary swing and you begin pushing it, it will take a few hard pushes initially to overcome inertia when the swing moves with a small displacement. You then synchronize your pushes by progressively moving slightly away from the stationary position of the swing, initially, pushing gently, and then pushing harder as you move away from the central stationary position of the swing. The point of pushing the swing is usually at the top of the swing cycle at one end. It takes a while of pushing before you are able to establish a rhythmic swing. The period before the rhythmic swing is established is the “transient”, and the rhythmic swing that is established after the few transient cycles elapse is the “steady-state”. This is analogous to establishing the steady-state in a capacitive circuit subject to a sinusoidal input. The capacitor being initially uncharged, will cause the current during the transient period to assume a value that will be quite different from that at the same voltage angle after steady-state is established. Electrostatics and circuits belong to one science, not two. These are discussed usually separately in textbooks and science and engineering courses. It is not possible to discuss the circuit processes which produce a sinusoidal current when a sinusoidal voltage is applied to a capacitor….the changing rates of change of the applied voltage ….the surface charge set up changing at every instant….the applied field changing in the wires ….and the current at each and every instant in time. Watch the two videos listed below to learn about current and the conduction process and surface charges (using a unified approach to electrostatics and circuits at a fundamental level). 1. kzfaq.info/get/bejne/iKujiseVnJzVqJc.html 2. kzfaq.info/get/bejne/bqiBgMKp3Ji2lqM.html The last frame of video #1 lists textbook 4 which discusses the sinusoidal steady-state in capacitors and inductors with the help of sequential diagrams and animated power-point presentations of the varying field components in the circuit elements in more detail.
@pk_star7862
@pk_star7862 2 жыл бұрын
Nice explained
@kjh98zzang
@kjh98zzang 2 жыл бұрын
this helped a lot thanks!
@honestman276
@honestman276 2 жыл бұрын
Thanks. From Bangladesh.
@emre-uc1zh
@emre-uc1zh 2 жыл бұрын
hello, on a 11/0.4 KV three-phase transformer; 11000V coming to the high voltage coil? because there is resistance inside each coil. Then I can't get 11000 output? then 400V cannot be induced. Can you explain how
@improvisationalcommenting9752
@improvisationalcommenting9752 2 жыл бұрын
It sounds like someone is writing on a pad in the background through the whole video