Thank you for this video. You are an amazing teacher. Your explanations are very clear and easy to understand.
@joiseuplier18 күн бұрын
Part 1 test data: 1:23 Mg(s)|Mg^2+(aq) 2:49 Cu(s)|Cu^2+(aq) 3:15 Al(s)|Al^3+(aq) 3:43 Sn(s)|Sn^2+(aq) 4:02 Fe(s)|Fe^3+(aq) 4:25 Ag(s)|Ag^+(aq) 4:43 Zn(s)|Zn^2+(aq) Part 2 test data: 5:22 connecting Aluminium and Tin half-cells. This is a reference for the experiment data so I don't have to scroll through the video to see the values again.
@joiseuplier18 күн бұрын
At 3:57 the anode was written as Ni(s) while the cathode was written as Mg(s) when at the beginning of the video at 2:26 it was the other way around. I'm assuming this is a mistake? It confused me for a minute there.
@climatechange-explained440722 күн бұрын
How is the answer to example 3 253 meters when the substitution is 27 - 11 / 2x1.2, which when put into a calculator and given brackets (to adhere to bedmas) equals 6.66666. . . repeating? I probably made a mistake but I can't see where.
@user-if7tq7bh6v26 күн бұрын
thnx msr 💘💘
@sulekamurdock328Ай бұрын
Okay what about sight what is it for you body to touch like for feeling
@sulekamurdock328Ай бұрын
Okay then it to hard to now
@dalewiebe4522Ай бұрын
he lived in his mom and dad's basement until he was 50 🤣
@nerdified1016Ай бұрын
Thanks, this helped a lot! Could not figure it out on my own lol
@AliDeriliАй бұрын
And also thanks for ur great videos sir!
@AliDeriliАй бұрын
If it is heptanoic acid, shouldn't it have more hydrogen atoms than 6? 1:10
@JasonFahyАй бұрын
You're right. Heptanoic acid would be (pause for mental math) C6H13COOH. With five hydrogens this is probably *benzoic* acid, where you start with benzene (C6H6), remove one hydrogen and attach a carboxyl group in its place. Good catch - sorry for the mistake.
@BenNoma-cq6snАй бұрын
Thanks much
@ngozichukwu04102 ай бұрын
Thanks ☺️
@oubelquemouad41932 ай бұрын
Sound issues
@baconworld35552 ай бұрын
Whoever this guy is, he may in fact be sparking the greatest academic comeback of my entire high school career.. God bless 🙏🙏
@NorQuestCollegeOnlineAnytimeАй бұрын
It's basement bob!
@user-sj1eu3hu1g2 ай бұрын
thank you
@climatechange-explained44073 ай бұрын
I just wanna point out that this video is the exact same as Physics 20 - Math skills for Physics. However, it is titled Relationships and Formulas. You might want to fix that.
@NorQuestCollegeOnlineAnytime3 ай бұрын
Thanks for catching that!
@theprogame13 ай бұрын
For all the heads that r too cool for school, this guy thought me more than I learned in 2 months in one vid wrda like it up
@user-qt9sq1lb3g3 ай бұрын
Thank you! I now get it. I will add it at my poetry analysis assignment for 'Vigil I Kept on the field one Night' by W. Whitman,which an apostrophe itself and I had not paid attetion to it up to now!
@NeonEchos3 ай бұрын
This is a bit confusing because the book's solution says "This should be left as an exact value unless a decimal approximation is specifically requested or required". Also the books solution is: (125/400π)cm/s simplified to (5/16π)cm/s. Also it seems that (5/16π)cm/s would be roughly 0.9817cm/s but the video approximation is rounding to 0.1cm/s? @NorQuestCollegeOnlineAnytime can you help clear this up please.
@nicolesalario8983 ай бұрын
im from philippines
@nistahahussein55063 ай бұрын
Thanks for the video
@ektapattani66384 ай бұрын
Thank you for making such informative vedio
@sol.slmnez4 ай бұрын
awesome
@savitatripathi89564 ай бұрын
Watching from india ,we used to do such questions in our inter level chemistry examinations
@chrismarr42344 ай бұрын
I looked it up and couldn't find it
@steevesibi18104 ай бұрын
This was really helpful ❤
@user-wj9md7jz9i5 ай бұрын
thanks Queen 😋
@COOPER7585 ай бұрын
thanks queen 🙏 🙏🙏
@NorQuestCollegeOnlineAnytime5 ай бұрын
Please note for Example 3, the answer is 40.0 m/s!
@Lily-ow5wm5 ай бұрын
I need physics to be ultrasound technician, and have at least a 75% but I’m finding physics very challenging and hard to understand. I don’t know what I should do
@NorQuestCollegeOnlineAnytime5 ай бұрын
Are you self-studying? If you're at a school, see what kind of tutorial support they have. Sitting down with a tutor periodically could help you fix any weak spots you're developing...
@Lily-ow5wm5 ай бұрын
@@NorQuestCollegeOnlineAnytimeyes I’m self studying I’m going to try to get help
@NorQuestCollegeOnlineAnytime5 ай бұрын
and the teachers at norquest are happy to help
@_4ybak_4896 ай бұрын
useless asf
@gauravimehra66946 ай бұрын
Ncert : Pea plant Tt gives tall plant (no mixing of traits) Ncert examplar: Rr gives pink flower
@user-ut8ur8ve7j6 ай бұрын
can't u explain why are they round, yellow, green smth?
@qdswais6 ай бұрын
Very helpful theres a video for each part of the diploma it helps alot seeing what we are asked to do and how we can approch the concept
@fathimarifa94637 ай бұрын
This poem is written using several stanzas. Not only 4 stanzas
@PrismEnvy7 ай бұрын
crazy this playlist doesnt have more watchs, super helpful man, thank you.
@JasonFahy7 ай бұрын
You're welcome! Hope it helped.
@islamicvideos91357 ай бұрын
PKU is a homozygous recessive condition.suppose if one out of 10000 live birts are effected with PKU that what is the percentage of carriers in that population?
@Stegojono8 ай бұрын
How come you did not solve for D on the last equation?
@Stegojono8 ай бұрын
Nevermind Its the same method as solving for a.
@ektapattani66388 ай бұрын
I am loving these I calculated whole and thank you for making these video its really helping me
@JasonFahy9 ай бұрын
Note: on page 4 when we're asked to find the enthalpy changes for the reactions...we do want to do that, but what we're really going to need (to do Hess's law) is the MOLAR enthalpy changes, i.e. total enthalpy ÷ number of moles of reactant. Both of those numbers are between 100 and 500 kJ/mol, so if you're not landing in that range, check your math and get help if you need it! <3
@sansthedrummer8 ай бұрын
How do we get the specific heat capacity for the reactants? I remember reading somewhere that since they're aq solutions, it's the same as water.
@JasonFahy8 ай бұрын
@@sansthedrummer That's right. Aqueous solutions are usually like 99% water by mass, so 4.19J/gC is usually close enough. :) n x delta-H is the energy in the chemical reaction, m x c x delta-T is the heating energy, and unless we have unusually bad experimental design, those amounts are equal.
@sansthedrummer8 ай бұрын
@@JasonFahy thank you!! That was a sticking point for me.
@NorQuestCollegeOnlineAnytime9 ай бұрын
Yes, BEDMAS still applies
@aaronju3479 ай бұрын
does bedmas apply to this? when would we do the add/subracting first and when would we do the mul/dividing first?
@garethdyck79710 ай бұрын
I watched the whole video looking for how to manipulate d=vft-1/2a(t^2) for t, but then you did it with vf=0. This does not help me a bit because I'm trying to figure out how to manipulate it when it still has two variables of t.
@NorQuestCollegeOnlineAnytime9 ай бұрын
If you have a 't' term AND a 't^2' term, the the equation is quadratic and that makes the math a bit more painful - probably too painful for Physics 20. There are two scenarios. Scenario 1: d is zero. That helps a lot; we have 0 = v_ft - 1/2at^2, we can factor t out of it to obtain 0 = t(v_f - 1/2at) and that has two straightforward solutions, t=0 and t=2v_f/a. Scenario 2: d is NOT zero. Now the equation is a trinomial quadratic. If you're incredibly lucky it will be factorable, but generally we'd have to use the quadratic formula to find the value(s) of t. The formatting here is so limited, I don't think I can demonstrate the steps so I'll hope you know what I mean.
@garethdyck7979 ай бұрын
@@NorQuestCollegeOnlineAnytime I didn't realize at first, but most of the questions with d=vft-1/2a(t^2) that my teacher gives either have vf or vi = 0, or when that is not the case and I have to solve for t, I can use a different kinematic equation to find a new piece of information using my known variables. Then I can find an equation with the original variables plus the new one and solve it for t. I think I understand better now and thanks for taking the time to help.
@alexandrorodriguez528910 ай бұрын
I2 and II1 can be (CC)
@JasonFahy10 ай бұрын
I-2 definitely could be CC, but Cc is also possible. I generally won't put a genotype on there unless I'm sure about it, and two Cc children isn't very strong evidence. II-1 same thing, but even moreso because they only had one child. If I absolutely had to guess I'd say they're CC, but am I sure? Not at all.
@AdrianWoodUK10 ай бұрын
...I have no idea why KZfaq suggested this to me. :D
@chrisoneill399910 ай бұрын
Are there grammatical mistakes in all of your teaching materials?
@prayingonyourdownfall10 ай бұрын
Thanks this helped me a lot!! 😭 had a very similar example in my textbook but I was unsure how to do it
@dalejr18310 ай бұрын
Looks like tv from 1985 I know I was 5. Awesome good memories on the old dial tube.
@ksubswithnoVideos-ze5fc10 ай бұрын
Thanks
@samd801610 ай бұрын
what test do i request to know if i am homozygos or hetereozygos for a blood group A?
@bio20norquest429 ай бұрын
That's a question for a genetic counsellor or a medical geneticist. You would (probably!) ask your doctor for a referral to these specialists for testing. I don't know if that's possible or likely because they usually screen for harmful genetic conditions, but I think you'd have to ask to know for sure! Non-serious response below: The Bio 30 response would be to have a million kids with someone who has blood type O (a known homozygote) and see what blood types your children have. If even one has a blood type of O, you can stop having kids and you know you're a heterozygote for blood type (AO). If you only have kids with blood type A, then you can be pretty sure (but not certain!) that you are a homozygote, too (AA). Your degree of certainty will increase with the number of children you have, but will never be 100%. Unless you're talking about AA vs AB, in which case a regular blood typing kit will tell you that in just a few minutes