VCAA 2023 Methods Exam 1 Solutions
47:42
Complex Analysis: A Cute Integral
27:51
Manifolds #6: Tangent Space (part 2)
29:04
Algebra #9: Principal Ideals
13:15
11 ай бұрын
Algebra #8: Ideals
10:59
11 ай бұрын
Algebra #6: Ring Isomorphisms
9:04
Algebra #4: Ring Adjunctions
10:28
11 ай бұрын
Algebra #2: Basic Ring Properties
11:21
Algebra #0: A New Series!
5:05
11 ай бұрын
Пікірлер
@rmal751
@rmal751 16 сағат бұрын
great video series, understandable explanations ! :)
@HadisMalekpour-zm6xy
@HadisMalekpour-zm6xy 3 күн бұрын
You explain everything really well, even better than my teacher. 😁 Thanks 🙏
@nuclearrambo3167
@nuclearrambo3167 4 күн бұрын
I would use fourier transform
@individual1st648
@individual1st648 5 күн бұрын
ive been trying for a few weeks to blindly get a line segment rotating at one endpoint, but i just couldn't figure it out (i knew it had to do with y=tan(a) but i didn't know what bounds i should insert) then i figured, maybe i just look up how to make a clock! and there we have it (thanks!)
@Halleluyah83
@Halleluyah83 13 күн бұрын
Wow😮
@KSM94K
@KSM94K 13 күн бұрын
Maybe I didn't understand it very well, why the Psi 1 and Psi 2 don't they cancel here? In the residue theorem proof something like that used to be cancelled
@Saqouro
@Saqouro 15 күн бұрын
This is really helpful. Thanks
@KSM94K
@KSM94K 15 күн бұрын
You're seriously underrated, nice explanation
@rashmipandey9201
@rashmipandey9201 17 күн бұрын
Nice
@physicstube8124
@physicstube8124 17 күн бұрын
I never thought the job could be done this easier 🎉
@marrom6808
@marrom6808 17 күн бұрын
If i want to reflect relative to what a is, i.e. if y = x then a = 1 and then we have ((1, 0), (0, -1)), does this mean ((1,0),(0,-a)), so i.e. a = 2 means ((1,0), (0, -2)) ?
@txikitofandango
@txikitofandango 19 күн бұрын
This is so wholesome
@luaiderar6600
@luaiderar6600 26 күн бұрын
I think I saw you outside melbourne central. Apparently you're my friends calc 1 tutor at unimelb lmaoo.
@qncubed3
@qncubed3 25 күн бұрын
:O
@kianheus2487
@kianheus2487 26 күн бұрын
Hi, loving the videos so far! I also have a question: at 15:08 you say to simply assume the existence of a C^k atlast, but how does that work in practice? Surely you can't just assume one to exist out of the blue.
@weselise2489
@weselise2489 29 күн бұрын
you saved me thank you
@nicholasnick6499
@nicholasnick6499 Ай бұрын
Great video
@meruem6022
@meruem6022 Ай бұрын
Hello @qncubed3 , I wanted to know if you have any bibliographical reference on solving the Basel problem using that method
@user-wu8yq1rb9t
@user-wu8yq1rb9t Ай бұрын
I missed you..... Just tell me where are you??!!
@buddychumpalfriendhomiebud9242
@buddychumpalfriendhomiebud9242 Ай бұрын
For a simpler method, substitute u=1/x , move around some things and replace u with x and you'll see that the integral is equal to its negative
@nizogos
@nizogos Ай бұрын
Can't you say that 1/abs(z^4+1) <1/abs(z^4) ? Simply because the right fraction has a smaller denominator, without going into triangle inequality stuff
@qncubed3
@qncubed3 Ай бұрын
This only works if z^4 is positive. If z^4=-2 for example then you would get 1<1/2
@natnaelayele8388
@natnaelayele8388 Ай бұрын
The most helpful video on the topic in the entire KZfaq
@anshuagrawal7364
@anshuagrawal7364 Ай бұрын
Amazing!!! Could you please continue posting more videos on Manifolds? 🙏🙏🙏
@MatvejPetrovicBronstein
@MatvejPetrovicBronstein Ай бұрын
Great work!Ad maiora semper...
@smftrsddvjiou6443
@smftrsddvjiou6443 Ай бұрын
funny, but useless.
@iphilip1
@iphilip1 Ай бұрын
Can you still show the analyse program that you have in your CAS link in you description or comments section
@mai1906
@mai1906 Ай бұрын
what a loser
@xxux1
@xxux1 Ай бұрын
Seems the link is not working😅
@iphilip1
@iphilip1 Ай бұрын
yeah
@itisajem8645
@itisajem8645 Ай бұрын
Interesting the result looks like the reflection formula for the gamma function but with 1/n
@ayandas8299
@ayandas8299 Ай бұрын
Bro you are the goat
@nuclearrambo3167
@nuclearrambo3167 Ай бұрын
cOnSeRvAtIvE vEcToR fIElD
@user-qk5ce5rr7u
@user-qk5ce5rr7u Ай бұрын
thank you, I ask you one more series expansion of tan(z) 31:17 I want to learn principle of this series of tan(z).
@Mouse-qm8wn
@Mouse-qm8wn Ай бұрын
Thanks a lot for great videos ❤😊. Can you please give examples of when to use this in real life or is it only relevant in general relativity?
@Caller8194
@Caller8194 Ай бұрын
good video
@user-qk5ce5rr7u
@user-qk5ce5rr7u Ай бұрын
Great!,thank you for your lecture, would you explain series of tan(z)(31:17)? I don't know result of this series.
@LatifaEssa
@LatifaEssa Ай бұрын
Vraiment c est super Je sais pas comment je peux remercier
@hyeonsseungsseungi
@hyeonsseungsseungi Ай бұрын
5:34 It's easier not to reduse (s+i) or (s-i) because (i+i)^4 or (-i-i)^4 is 16, so thier denominator becomes rational.
@williammartin4416
@williammartin4416 Ай бұрын
Thanks!
@Sarmadness
@Sarmadness Ай бұрын
Great explanation, thanks!
@Neptoid
@Neptoid Ай бұрын
The Jacob Collier of Physics
@GingerMath
@GingerMath Ай бұрын
After two years I found this video and it makes sense!! Thank you <3
@anandarunakumar6819
@anandarunakumar6819 Ай бұрын
Great explanation. Nice teaser to conformal technique.
@matejcataric2259
@matejcataric2259 Ай бұрын
This channel rocks!! Greetings from Croatia.
@Playingcivilization
@Playingcivilization Ай бұрын
Much easier with double integration I = \int_0^\infty \int_a^b sin(tx)/x dt dx = [using Foubini] = \int_a^b \int_0^\infty sin(tx) / x dx dt = \int_a^b pi/2 dt = pi/2 * (b - a)
@MuhammadYogavas
@MuhammadYogavas Ай бұрын
Is it possible to prové it with only gamma function ? Because our Professor didnt teach us the Beta function yet
@richard_larrain
@richard_larrain Ай бұрын
0 is not a pole of logarithm
@Playingcivilization
@Playingcivilization Ай бұрын
Hi Could you please do a video about integral from 0 to infty of ln(x)/((x+1)*x^{3/4}). I was trying to solve it using complex integration but failed to find proper contour:(
@devanshgupta3935
@devanshgupta3935 2 ай бұрын
My final today had this exact integral. I did kind of figure out that we need to take a Gaussian integral to come to the result but used some QUESTIONABLE mathematics. Wish I'd watched this vid earlier. Anyways this channel is absolutely amazing! Please keep it up.