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Пікірлер
@thanatos6921
@thanatos6921 6 күн бұрын
Great 🎉
@pritampandit570
@pritampandit570 Ай бұрын
Awesome explanation
@gauravm8152
@gauravm8152 Ай бұрын
Hello Sir. If we consider a square with X and Y axis along its diagonals, the Ix will be a^4/12, and if we rotate by 45 degrees, we still have Ix' equal to a^4/12. How to explain this on the Mohr's circle?
@rafaelghielmini4298
@rafaelghielmini4298 2 ай бұрын
blinks counted: 0.5
@quanganhkat
@quanganhkat 4 ай бұрын
Thank you!
@0mar.ali.khorshed12
@0mar.ali.khorshed12 5 ай бұрын
Great but the question is how F=EAi(∆L) = N.m which it is just N
@MuhammadQasim-th3ed
@MuhammadQasim-th3ed 5 ай бұрын
Sir brilliantly explain ...💛
@christabelgraham2816
@christabelgraham2816 6 ай бұрын
I don't mean this in an airy fairy way but I think this puts students who struggle with ADHD and other learning difficulties at a great disadvantage. One of the issues with ADHD is that students often can't get down to work until the last moment. Working through the solutions on a mock exam is a quickfire way for students to learn the content at speed. It provides you with a strict framework of required knowledge and forces you to learn how to do something in order to memorise it. You HAVE to understand the inner workings of the question in order to apply it to a similar but different question, rather than combing through hours of lecture content, a third of which has never come up in an exam nor ever will/ is completely off topic. I have learnt more by working through exam papers with solutions than going through an entire module's worth of lecture slides.
@DrRans
@DrRans 28 күн бұрын
There are a few things in your response that I would like to comment on, but first, let me preface that in my video, I am not justifying a position where professors provide no solutions for practice problems. I always provide multiple practice exams, but only solutions for a select number of those practice exams, so that enables students with various learning needs to study those solutions and learn some things from it. I do provide solutions for some questions, just not all as this promotes simply studying/memorizing past solutions. The remark that concerns me in your response is that you state "...a third of [lecture content] which has never come up in an exam nor ever will is completely off topic." This comment makes it seem that you feel the goal of a course is to pass an exam. This is the wrong perspective. All things taught in a course lecture should be relevant to the deep understanding of the content that is being strived for in the learning objectives of the course. Thus studying it is in line with the learning objectives of the course and is a worthwhile endevour. Thus, what you are identifying as being completely off topic is likely connected to the deep understanding that is necessary to apply the concepts to new problems.
@Tre_ransom
@Tre_ransom 7 ай бұрын
Thabkyou
@mhchow1727
@mhchow1727 8 ай бұрын
great video !
@nashalmeida563
@nashalmeida563 8 ай бұрын
me one night before exam
@user-ez8hf5se7k
@user-ez8hf5se7k 9 ай бұрын
❤❤
@fawazkhaled6541
@fawazkhaled6541 9 ай бұрын
Thanks, I appreciate your effort
@prabhatpaswan232
@prabhatpaswan232 10 ай бұрын
I am very glad to say that you are making awesome videos. I need these types of videos to understand Aerostructure behaviour. Please make such which will help many people.
@bobguarnieri280
@bobguarnieri280 11 ай бұрын
How is the overall strength of an adhesive joint distributed over the chemical bond and the mechanical interlocking aspects?
@ravindushiwanka5662
@ravindushiwanka5662 11 ай бұрын
Good👍
@vwaudiwelder
@vwaudiwelder Жыл бұрын
Lotus are glued together as well with structural adhesives. PLENTY of safety critical components in aviation and many other industries use and rely upon these chemical/mechanical bond joining methods. For this TITAN craft that dived to this depth numerous times before it will be interesting for me as a materials joining engineer to see whether it was a cohesion or adhesion failure in the cirumferential joint bond. RIP to all those that died...
@ahmadzamanifar4987
@ahmadzamanifar4987 Жыл бұрын
Dear Calvin thanks we know about what vertical shear force may do with the web of the beams but what may do the shear force in flange? we design flanges for flexural actions and we only consider tension or compression in them??
@arunal5726
@arunal5726 Жыл бұрын
Thank you
@jordankortlandt5494
@jordankortlandt5494 Жыл бұрын
Thanks for the video--very helpful. As I think through this equation, I am struck by the fact that the moment of intertia is not impacted by the material mass or properties. For some reason, I would have thought that intuitively the higher modulus of elasticity for metal would compound relative to wood. E.g. a metal and wooden bar of the same dimension will have the same moment of intertia (all else being equal). When I combine that with a beam deflection formula for a simply supported beam { D = [(W * L^3) / (48*E*I)] }, it means a percentage increase in the size of both material types will have an equal percentage impact on the beam deflection. Bedankt!
@mahrezaitm.5162
@mahrezaitm.5162 Жыл бұрын
Thanks Calvin !
@zaiden5660
@zaiden5660 Жыл бұрын
'promosm' ❤️
@ChefsPalette7
@ChefsPalette7 Жыл бұрын
Very helpful video❤
@muhammadsadiq273
@muhammadsadiq273 Жыл бұрын
Sir i am very very impress you l like your video
@SaintAngerFTW
@SaintAngerFTW Жыл бұрын
Whats up with your man boobs.... there's a surgery to remove it
@asbjornlaursen
@asbjornlaursen Жыл бұрын
Hi Calvin I love your video and I find it very educating. I was doing at general calculation of a combined open and closed section and used your video as a control check and may have stumbled upon a false assumption you are making. It concerns the final relation that if "a" is 25 times larger than "t" then the stress will be equal in the two different sections. Because you forget to calculate a new deflection relation between the the open and closed section for a = 25t, which from my calculation is no longer 4/75 T but is now 16/1875 T. Therefore the stress relation for a = 25t is now 4/25 and even smaller in the open section than for a = 10t which is 10/25. To get the same stress in the open at closed section you will need to decrease the length a = 4t and it is now no longer a thin walled section. Therefore it can be assumed in my opinion that the maximum stress will always be in the closed section as long as it is still thin walled for the structure you present in the video. I have not found any other errors in the video but hope this clears out any confusions that others might have had.
@KhaoticDeterminism
@KhaoticDeterminism Жыл бұрын
Thanks!
@michaelbarr3819
@michaelbarr3819 Жыл бұрын
the moon only orbits the earth about 12 times each year. Not over 100 as you are showing.
@DrRans
@DrRans Жыл бұрын
You are correct. I wasn’t attempting to show an accurate number of orbits with the illustration, only illustrate that there is a wobble.
@angenietkam8752
@angenietkam8752 Жыл бұрын
This is great, Calvin. Thanks for this creative use of the program, it was a joy to look at (and has some great pieces of advice as well).
@DavidHauber
@DavidHauber Жыл бұрын
AI will not replace you, a person using AI will. Students are in a world different from the one we were educated in. I could not have excelled if I didn't use the tools available to me, should we ban calculators or internet searches? AI certainly seems different but is it really? To succeed we need to use the tools available to us.
@DrRans
@DrRans Жыл бұрын
I am certainly not afraid of AI replacing humans. But I think a lot of the fear of AI in education hinges around the fact that education will have to evolve to properly include/leverage AI as a tool, but there is resistance to this as t will require a lot of time and effort. Particulalry in the area of assessment where we rely on assignments with well defined and expected answers (the type of thing AI tends to be good at finding).
@roelschipper3105
@roelschipper3105 Жыл бұрын
Very insightful interview. The answers of ChatGPT are uncannily similar in realism to those of the robot R. Daneel Olivaw. Also in their honesty on limitations and origin. Hopefully, the Asimov laws were implemented as well in ChatGPT.
@maudvandijke8553
@maudvandijke8553 Жыл бұрын
Did the ChatGPT just mention 'learning styles'? OMG
@rocketman99
@rocketman99 Жыл бұрын
Explained the what is is pretty well but you haven't explained why it is at all . Why does the excess kinetic energy means (excess cuz its r2 so if you mass sits further you have more) more resistance? why does it make it harder to transition from potential Energy to kinetic ?
@DrRans
@DrRans Жыл бұрын
It’s not that there is excess kinetic energy, but that more kinetic energy is needed for the same movement. So in the experiment, both objects had the same potential energy, and that potential energy is converted to kinetic energy, but due to the distribution of mass in the hollow cylinder a lower velocity of the cylinder is obtained. So both cylinders have the same kinetic energy at the end, but the velocities are different due to the mass distribution. So equate the kinetic energies of two rolling cylinders with different mass distributions, and you will see that the linear velocity of the cylinder with a more mass away from the centroid will have a smaller linear velocity for the same amount of energy.
@rocketman99
@rocketman99 Жыл бұрын
@@DrRans Thank you for your answer :) I see what you mean especially in a equation manner E= 1/2 (int(r^2)dm) .w^2 aka if you increase the r^2 you reduce w but velocity is w.r therefore velocity should be constant since mass is the same . Also forgetting about what we talked what is not intiutive about this concept ( I am not denying it or saying its wrong I am just trying to reaally understand it ). How exactly does at the t=0 moment the first rotation has more interia against the movement since ( again I know the formula and the basic linear logic from that but lets do it verbally) the partical at top sits very high and also since it sits high r is high , okey we say w is low but why exactly , what kind of nature forces cause this. Like it is the same mass there fore same total energy at t=0
@DrRans
@DrRans Жыл бұрын
@@rocketman99 At t = 0, both of the cylindars are at the same height, so they have the same potential energy (because their total mass is the same). Potential energy would be mass times height. Actually, there is a smal error here as the hollow sylindar has a higher centre of mass, so it actually has a little more potential energy than the solid cyinder, but even with this little extra energy, it has more resistance to rolling and thus rolls slower as a result of its resistance. To try an understand it verbally, it can be useful to think about the distance each bit of mass on the cylinder travels. In the hollow cylinder, in addition to the displacement in the direction of the ramp, mass is moving perpendicular as it is rolling. So the hollow cylinder, due to its larger radius, requires the mass to move perpendicular (lets call this up and down) relative to the ramp, and thus this added motion consumes some of the energy. So less energy is available for imparting velocity in the direction of the ramp.
@rocketman99
@rocketman99 Жыл бұрын
@@DrRans thank you soo much that was really helpfull
@najibalruzziah2625
@najibalruzziah2625 Жыл бұрын
that was super helpful thank you very much
@nasirkabir7112
@nasirkabir7112 Жыл бұрын
This really helped me to understand the concept better from your lecture. despite it is already something i have knowledge of. thanks very much prof.
@sathishkumarm8434
@sathishkumarm8434 Жыл бұрын
I am studying aerospace engineering ..it's easy to understand by seeing your video sir!
@defendermodsandtravels
@defendermodsandtravels Жыл бұрын
This derivation is for a state of constant stress. If the stresses are non-constant one ends up with the differential equations of stress equilibrium (e.g. Timoshenko and Goodier 2nd ed p22). I haven't seen a general solution to these equations to show that tau_xy = tau_yz so I conclude that complementary shear stresses only apply in a constant stress field, a fairly trivial result. Anyhow, at least I understand that now.
@DrRans
@DrRans Жыл бұрын
Please look at p. 6 of Timoshenko and Goodier. They use the same approach (and elaborate on it a bit further) to derive this result and it is used throught that textbook and within the field of mechanics.
@defendermodsandtravels
@defendermodsandtravels Жыл бұрын
@@DrRans OK will do and thanks for the suggestion. You are correct that the principle of complementary shear stresses is widely used although I had no reason to question its generality until I saw your video. The T&G derivation is identical to yours so one cannot question it. Out of curiosity I will satisfy myself that some postulated stress distributions (say a 2 term polynomial) satisfies the various equilibrium equations etc. I guess the other way to demonstrate complementary shear stresses is via Mohr's circle. Thanks for posting the video.
@franciscopostigogarcia2694
@franciscopostigogarcia2694 Жыл бұрын
UwU
@venkatasubramanianm2559
@venkatasubramanianm2559 Жыл бұрын
For octagon hollow shaft how we calculate maximum shear stress sir ?
@danielhailegebriel
@danielhailegebriel Жыл бұрын
THANK YOU SO MUCH
@vvsalb1041
@vvsalb1041 Жыл бұрын
Thank you !!
@iancioch4994
@iancioch4994 2 жыл бұрын
why is this guys hairline so weird
@808bigisland
@808bigisland 2 жыл бұрын
Aloha and thx!
@shashankmohan8422
@shashankmohan8422 2 жыл бұрын
Hi, where can i find the video talking about hole filling shown in 1:53 ?
@deleted7446
@deleted7446 2 жыл бұрын
What's the difference between moment and torque
@deleted7446
@deleted7446 2 жыл бұрын
@@DrRans 👍 thanks
@tousifakhtar5934
@tousifakhtar5934 2 жыл бұрын
Greatly Explained 👍
@Charbeltoumieh
@Charbeltoumieh 2 жыл бұрын
Dude the humour in this video is worth the 👍 alone.
@raviputrevu4982
@raviputrevu4982 2 жыл бұрын
Awesome video with real life failure videos
@Its_A_Gundam
@Its_A_Gundam 2 жыл бұрын
Thank you so much for this, and the other videos on fastening/attaching things. So much better than the 124 slide PowerPoint designed to be presented in person we were sent to read through.
@purnalingamr6803
@purnalingamr6803 2 жыл бұрын
Thank you for the video, so for a thermosetting resin like epoxy matrix (for example, a GFRP prepreg with epoxy ), the only way to join it to a metal structure is through adhesive?