thank you so much...

thanks

thanks a lot.🙏

thanks a lot

Thanks a lot.🙏

Thank you for the video.

class Solution: def canBeEqual(self, target: List[int], arr: List[int]) -> bool: return sorted(target)==sorted(arr) #one line code in python

if(arr[i] >= 0) break;

I dont get this, why would microsoft and big tech companies would ask this question?? Why not the hardest and toughest question ever out there ??

first sight and i wanna quit now

in the solution, line #10 should be int j=i for a single character string. Also line #15 should be i=j if that falls true.

string reverseWords(std::string s) { int i = 0; int n = s.length(); string ans; while (i < n) { while (i < n && s[i] == ' ') { i++; // skip spaces } if (i >= n) break; int j = i; while (j < n && s[j] != ' ') { j++; // find the end of the word } string word = s.substr(i, j - i); // extract the word if (ans.empty()) { ans = word; // if it's the first word, no need to add space } else { ans = word + " " + ans; // prepend the word } i = j; // move to the next word } return ans; }

string reverseWords(std::string s) { int i = 0; int n = s.length(); string ans; while (i < n) { while (i < n && s[i] == ' ') { i++; // skip spaces } if (i >= n) break; int j = i; while (j < n && s[j] != ' ') { j++; // find the end of the word } string word = s.substr(i, j - i); // extract the word if (ans.empty()) { ans = word; // if it's the first word, no need to add space } else { ans = word + " " + ans; // prepend the word } i = j; // move to the next word } return ans; }

:12" So essentially, a web server is a computer system that runs web server software???

Nice Video!

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Starting the Leetcode Journey

Im not able to find videos line by line

Nice proof. ❤❤

upcasting and downcasting should have been explained

Nice explanation with fabulous approach.

So wrong man

For java users here is the code class Solution { public String reverseWords(String s) { char []str=s.toCharArray(); String result="",w=""; int n=s.length(); int i=0,j=0; while(i<n) { while(i<n && str[i]==' ') i++; j=i+1; while(j<n && str[j]!=' ') j++; if(j<=n) {w=s.substring(i,j); if(result.isEmpty()) { result=""+w; } else result=w+" "+result; } i=j+1; } return result; } }

thee best video I ever had in this ques

By the way there was no need to swap;

this was best solution so far

how to set the normal c++ coding we learn this c++ is not easy to understand

Legendary playlist

i want full course

i want full course

THANK YOU SIR

Such a great explanation!

Best video on dynamic_cast, thank you sir!

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terrible video can't understand a thing i came to learn about a term but this mf keep bomabarding a more hundred terms on me like tf is a static db. what is HTTP response and request. make sure if you are using a term not overone on the internet knows about that you already know. make me hate this subject more. Bravo!

I think you have to work on your English

At 3:12 'i' variable is looking for space and 'j' variable is looking for non space. Anybody Correct me if i am wrong?

wonderfulll solution, thanks

but it starts from a.begin and till d-1 as per your explanation, then why in code it is till d only?

Do they ask to solve in iterative way? it doesn't even seem efficient?

can you please let me know what is auto

thanks, amazing video

amazing video

hi, I solved this problem without giving regard to which task has higher frequency. I am just scheduling the first available task that is past the cooldown period. All test cases passed. I am using two maps one to keep frequency count and one to track the earliest possible time I can schedule the task next.

thank you sir the videos are really nice not skipping over the dferivations

This is desnecessarily complex.

Yoo check out my page I’m doing LeetCode in Swift

Thanks ❤