saw this on tiktok as a 1h vid and compressed to 20 pixels per frame, decided to watch it here after enduring the 16 minutes spent there lol
@c_dorado5 күн бұрын
For the 18:30 Check your understanding problem I got: ρ(x, t) = c₁²•|X₁(x)|² + c₂²•|X₂(x)|², so, I don't find the time-dependence.
@Al-Qaisi_Iraqi12 күн бұрын
Thank you
@Al-Qaisi_Iraqi12 күн бұрын
Thank you
@Al-Qaisi_Iraqi12 күн бұрын
Thank you
@enzolerose200814 күн бұрын
I guess at 6:55 the inequality for a and b has to be reversed
@tates300monkyears414 күн бұрын
Adieu
@fiftysevenforce17 күн бұрын
And that's a really ugly Psi Must fix.
@user-gq1bt4rt2x22 күн бұрын
Ill-defined?
@user-xk8uu4gk9l28 күн бұрын
did anyone understand the spin =wtf thing
@ifrazali305212 күн бұрын
Of course That was a joke
@user-xk8uu4gk9l28 күн бұрын
I be watching this on my pz
@user-xk8uu4gk9l29 күн бұрын
my guess a) no istnt smooth, curves wrongon Left side b) smooth curves wrong on left side. looks good on right sidde c) All correct d) Has to curve When E<V so also bad
@user-xk8uu4gk9l29 күн бұрын
PSi looks very communist
@user-xk8uu4gk9lАй бұрын
I dont understand the check questions answer/ What is correct?
@user-xk8uu4gk9lАй бұрын
Anybody got the answer to the Understaning Check?
@user-xk8uu4gk9lАй бұрын
14:48 There is a star missing on the last blue psi for those who are confused :)
@user-xk8uu4gk9lАй бұрын
So is the continous distribution is not a wave funktion. Youd would have to square the wave funktion, and then integrate to get the expctation values for that right?
@albertliu2599Ай бұрын
Check your understanding: . . . 1. Eigenvalue of Sy : hbar/2 and -hbar/2 ( just like Sx and Sz ) 2. Eigenvectors of Sy: y_plus = 1/sqrt(2) * ( 1, i ) # with eigenvalues hbar/2 y_minux = 1/sqrt(2) * ( 1, -i ) # with eigenvalues -hbar/2 3. x_plus state can be expressed in Sy eigenstates, as x_plus = ( 1/2 - i/2) * y_plus + ( 1/2 + i/2 ) * y_minus. So the possibilities is both 0.5 to attain one of the states of corresponding eigenvalue. 4. Same as before, 0.5 possibility to get both states and corresponding eigenvalues.
@albertliu2599Ай бұрын
check your understanding: . . . 1. L2|f> = 2hbar^2|f>, L = 1, Lz could be -1, 0 , 1 ( all * hbar ) . A total of 3 states. 2. L2|f> = 15/4 hbar^2|f>, L = 3/2, Lz could be -3/2, -1/2, 1/2, 3/2 ( all * hbar ). A total of 4 states. 3. Lz|f> = 0, L2|f> could be any (hbar)^2 * l * ( l+1 ), l = 0, 1/2, 1, 3/2, .... 4. Lz|f> = 3/2 * hbar |f> could be any (hbar)^2 * l * ( l+1 ), l = 3/2, 2, 5/2, 3, ... Shouldn't there be a |f> at the end for the 4th question?
@albertliu2599Ай бұрын
Check your understanding: . . . . 1. [x, Py] = 0 2. So we could measure x and Py as precise as we want. 3. [Px, Py] = 0 also. So we could measure Px and Py as precise as we want.
@MinMax-kc8ujАй бұрын
I kind of liked that proof of the roots of unity. that x^3=1 bit. You make y=0, the unity thing kicks in anyway.
@albertliu2599Ай бұрын
Check your understanding: . . . . 1: H applies on the right state |ψm>, and return Em|ψm>. Em is just and number and get outside of the braket. So Hnm = Em<ψn|ψm> 2: Hnm is a diagonal matrix with values E1,E2...En on its diagonal line. 3: a+|ψm> and returns 1*|ψm+1>. a+nm = <ψn|ψm+1>. 4: a+nm is a off-diagonal matrix with values 1,1,1,1,1.... on the line just below the diagonal line.
@albertliu2599Ай бұрын
Check Your Understanding at 19:30: . . . Part 1: a. Got (QR+RQ-2(µQ)(µR))/2, So it's not a commutator I guess. b. -(µQ)(µR) is an extra term, what does it mean? Part 2: Because µR is just a number, it could be moved outside of the braket to the front, and the rest part is just expectation of Q.
@albertliu2599Ай бұрын
It is now 2024... I already forgot how much difference you can feel between 480p and 720p. This video is much sharper than the previous one.
@albertliu2599Ай бұрын
Check Your understanding: Part 1: C2=0, C3=1, C4=0 Part 2: -a/pi
@ifrazali3052Ай бұрын
How do we know that psi-0 is equal to B? Isn't it that we can not use psi-1 or psi-2 equations to solve for psi-0 because they do not include x=0? Then why are we using them to find psi-0?
@mysecondaccount1287Ай бұрын
kzfaq.info/get/bejne/gtNphr2Xl76qc5c.htmlsi=5h5AElm81LIXkFdT took your videos
@krishnendusaha61902 ай бұрын
is this is the part of jee syllabus
@xybrs3 ай бұрын
Ah yes, my go to data set when I'm trying to understand discrete probability distributions. ~sexual partners of the general public
@xinzeng-iq7zv3 ай бұрын
is this guy a dentist on some naruto shit
@JaneWorley3 ай бұрын
Had to set the playback speed to 0.75 that was way too fast man
@briannagopaul34933 ай бұрын
Thank you for these lectures, these make so much more sense!!
@paladin11474 ай бұрын
Amazing, just check the comments for certain errors or keep the Griffiths book next to you to verify. Thank you for the video
@StefaniaStella-zy1cc4 ай бұрын
At time 5:17 is said that the average momentum of an electron is zero because the Hydrogen atom is not moving: this is true only as for as the vecton momentum is conserned not as its value though which is constant.
@brianlockwood5073Ай бұрын
Momentum is a vector quantity. It has a magnitude certainly but if you say 'momentum' then you are talking about magnitude and direction which on average is definitely zero.
@amandapowell20604 ай бұрын
Thank you Dr. Carlson! Just blazed through your PHY4200 playlist to study for my final. You're an amazing teacher and your explanations really helped build intuition.
@davidhand97215 ай бұрын
When you write p-hat squared psi, does that mean p-hat(p-hat(psi)) or does it mean (p-hat(psi))(p-hat(psi)), i.e. squared in the traditional sense. For that matter, it looks like you're using (x-hat)(p-hat)psi = x-hat(p-hat(psi)), otherwise they would commute. But earlier, you definitely treated (p-hat)(p-hat) as p-hat squared. Can someone clarify please?
@BLVGamingY5 ай бұрын
why isn't at 22:30 the phi function an arbitrary sum of opposite exponentials as opposed to just one exponential nonetheless m ends up a whole number
@JonSedlak-xe5ef5 ай бұрын
so from the wave animation the wavelet flattens out and there is no more wavelet and the probability animation suggest that the particle can be anywhere. Is that right?
@BLVGamingY6 ай бұрын
at around 6:00 you assume the function only contains sines and cosines instead of letting it be complex exponentials, it ends up the same because once you assume those complex exponentials form an even function, then you arrive at sine anyways
@basomahassoun81916 ай бұрын
Maaaaaaaaaany thanks
@BLVGamingY6 ай бұрын
YAYY the static wavey has no momentum YUPPIIEEE
@jen_sen85086 ай бұрын
What the fuckkkkkkkkkkkkk 😢
@pepaxxxsvinka33796 ай бұрын
that's what I neeeeeeed!
@averagecornenjoyer63486 ай бұрын
why can you write a+ in the left side? isn't that implying that the ladder and the hamiltonian commute? (which they seem not to)
@dutchman24416 ай бұрын
you mixed up minus and plus signs in the opperators, but ill let it slide ;)
@Misterlikeseverythin6 ай бұрын
Thank you about the last part in particular. It does seem quite fishy, but it is very necessary in QFT. That one part caught me by surprize.
@Dekoherence-ii8pw7 ай бұрын
5:20 Maybe the correct approach is to say: It's NOT a point particle. If you do a measurement that collapses the wave function, then its position collapses to a point. But the rest of the time, it's a spread out thing. How does quantum field theory describe the electron? NOT as a point particle, right? But as a spread-out disturbance in a field, right? So maybe SPIN is some kind of phenomenon in what the electron field is doing.
@basomahassoun81917 ай бұрын
Maaaaaaaany thanks
@hidden_anonymous7 ай бұрын
Great lecture. Thank you!
@Dekoherence-ii8pw7 ай бұрын
19:00 "It SORT OF goes to zero". I'm thinking it might DEFINITELY GO TO ZERO if we use the Lebesgue Integral.