Lets do peer LC lol

Great, Keep posting the good stuff👍

I was doing the same questions today, and it was on my feed nice.

ans = [1] * len(nums) prod, zero_count = 1, 0 for i in nums: if i != 0: prod *= i else: zero_count += 1 for i in range(len(nums)): ans[i] = 0 if zero_count - (nums[i] == 0) > 0 else prod // (nums[i] if nums[i] != 0 else 1) return ans

Nice. I solved it in a different way

nice

your approach is genius! opened a new perspective for me. thanks so much for sharing!

Hello! try to improve the sound, it's very hard to hear you.

Where would you say is the best place to learn about data structures like this (I've never heard of a trie structure before)

Thank you keep doing

I like how you're targetting all coding platforms, just sort them in a playlist too for the ease of it 👍🏻

Thanks for the explanation. I've got stuck with this * k operation

That's the worst hackerrank exercise i ever did. Zero coding, zero algorithm. This shiuldnt be in hacker rank