Thank you!

What do you mean by if we integrate this equation around 7:10

Hi, When I say integrate, I'm talking about using "Integral Calculus" to solve the equation. For context, since many students have not taken calculus prior to this topic, I just write out the solution without showing how, since the "how" is calculus. Once you have the formula after integration, you just need to use it to solve for unknown quantities using the rules of algebra. I hope that makes sense :)

Hi, When I say integrate, I'm talking about using "Integral Calculus" to solve the equation. For context, since many students have not taken calculus prior to this topic, I just write out the solution without showing how, since the "how" is calculus. Once you have the formula after integration, you just need to use it to solve for unknown quantities using the rules of algebra. I hope that makes sense :)

Hello! Not at this time. Out of curiosity, what are your rates?

@@chemplistic how can i connect with you

I think I need to look at the calculation understand what you are referring to.

@@chemplistic I think I explained it badly. Let's say I measure 99.9g of salt and do some chemistry calculations on it; I've got three significant digits, and maybe I'll determine that my chemical reactions result in 1.48 mJ of energy released (three significant figures). Now let's say I measure 100.1g of salt and run calculations on the same chemical reactions; this time it works out to 1.493 mJ of energy released (four significant figures). You see how I get one whole more digit of precision, just by adding a fraction of a percent more salt? It wouldn't have happened if we were using base 11 or base 9.

Thank for the explanation. How many significant figures you end up with depends on the precision of your initial measurement. This is decided by your instrument. For example, if you use a scale that gives you only 1 decimal place, then that’s going to be the limiting factor; however, if you use a different scale which is more precise and gives readings up to 2 decimal places, then that increases the precision of your measurement and hence calculations. I hope that makes sense.

Thanks, John!

That is correct

Thank you!

You’re welcome! Glad you found it helpful!

Glad it helped!

Thanks, John!

Because we started with two sig figs.

Glad you liked it, John! It’s easy to forget the rules of logarithms.

You’re very welcome! Glad you found it helpful, Adarsh!

Yay!! Was the timing good? Like enough time to absorb what was being explained.

There’s always something new to learn :)

@andygranja2816 did you have a specify question or comment?

Thanks @fennerd glad it helped you!

Good point. I’ll keep that in mind for future videos. I think I said something about that in example 2 of scientific notation.

Yes it is, John! Thanks for your comments!

Thanks John!!