CIT PHYSICS EXPERIMENTS

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@Rajyalakshmi958 2 ай бұрын

Any jntua students 😂

@slumberking9442 2 ай бұрын

❤

@harmanjotsingh9240 3 ай бұрын

13:34 please explain me, how we calculate vernier scale coincidence, 56 which msr is 132 or in vernier A we have 312 degree msr Or vsc 5 , please explain?

@OGCOPPERHEAD 3 ай бұрын

Almighty Professor Balraju, you are a God!

@priyaa-iz6xt 3 ай бұрын

Thanks thala 🥳

@amitkumaryadav-ft3in 5 ай бұрын

Thanks sir

@vidhyanshsharma3039 5 ай бұрын

Well explanation 🙏

@scotcristianclg23 5 ай бұрын

super sir but i have a one doubt.if we identify the value of msr and vsc how to find out the total reading in vernier 1 and 2

@citphysicsexperiments7218 5 ай бұрын

MSR + (VSC x LC)

@user-oj6hq3un4u 5 ай бұрын

Superb explanation

@namobharat825 5 ай бұрын

very nice animation and explanation.

@NikhilUpadhyayIITB 5 ай бұрын

me at 1:43 AM now having😶 lab at 8:30AM

@rajat796 5 ай бұрын

Awesome sir we understand nicely

@fathimaazkiya 6 ай бұрын

thank u sir but while noting vsc, we sometimes see more than just one line which perfectly coincides with each other.. how do i correctly find what's coinciding? like at 13:32 54, even 55, were perfectly coincided..?

@Irannaf38450 6 ай бұрын

Today is my practical Exam tankyou

@user-me5jl2bf8q 6 ай бұрын

much better than IIT Bombay faculty in explaing it to students, Thanks sir

@hiteshkumarsrinivasan4736 6 ай бұрын

🙏

@ManitejaDiviti 7 ай бұрын

Good and positive approach explanation

@cricvirat8536 7 ай бұрын

Why should we need to kee current ar 0.5 amp

@gautamsingh3880 7 ай бұрын

Have my practical in 1 hour👻

@shramanpoojari8673 7 ай бұрын

Thank you so much sir, ur explanation is very nice ❤

@hinduism9497 7 ай бұрын

Thanks sir

@ADITYA_Z99 7 ай бұрын

I have my Physics Lab Class in college, gosh this is hard until you give everything❤️

@arianaazmir4321 8 ай бұрын

Hi sir thank you for the video buat i have question, where can i get the given formula for young modulus?I understand that it is from derivation of : young modulus= stress/strain But i have trouble with getting the formula for stress and strain based on the experiment. And i am very confused as there are other different formula…Could you show me how to get the formula or at least a citation for it..

@AathiswaranS-ik1sq 8 ай бұрын

Super sir 😊

@kushi715 8 ай бұрын

Very clear explanation sir. Thank you.

@rorycarter6948 9 ай бұрын

9:48 such a clear animation, very helpful. Thank you.

@baisalgaming3884 9 ай бұрын

Sir graph

@maturemental 9 ай бұрын

sir eh🔥

@sattusiri8724 9 ай бұрын

Thankyou so much sir🙏it means alot

@blazetgb1660 10 ай бұрын

Nandrigal pala

@priya-z333 10 ай бұрын

Thank you sir

@Vhrb 10 ай бұрын

Thank you sir 🙏🙏

@AnirudH24O1 Жыл бұрын

Slope= (y2-y1)/(x2-x1) ?

@namjoonwillshaveyoureyebrow Жыл бұрын

To be honest, this is one of the best video that explained the experiment in a way that , everone would understand. It's really great to come across you . Thank you so so much sir

@aditisoumendra1150 Жыл бұрын

Thankyou so much Sir! The concept is crystal clear because of how well you explained in the video🙏🙏

@prakashnarayan2447 Жыл бұрын

thank you very much sir , this is very useful for last minute preparations , hats off to CIT for producing such informative content . thank you balraju sir , this is on behalf of 10 students from another university

@user-mb5zi8nz3h Жыл бұрын

Any SASTRA students here😅

@Abisheknn 3 ай бұрын

😅

@ksm_0307 3 ай бұрын

😊❤

@physicsouruniverse2798 Жыл бұрын

thank you

@stkarthikeyan4318 Жыл бұрын

Mass thala

@naveendar Жыл бұрын

🧐

@medbrahim8739 Жыл бұрын

Thank you very much, Professor, for this benefit... I have a question, when zinc acetate is not available from the beginning, can we start with commercial zinc oxide?