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CORRECTION: Associating -216 with a - cubed.

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I apologize for the error. I'll make sure to double check my equations in the future

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log x^(cube root) = log x^(1/3) = 1/3 log x 1/3 log x + log x = 10 ( base 10) 4/3 log x = 10 ( base 10) log x = 10 × 3/4 =15/2 ( base 10) log (base 10) of b = a then 10^ a = b. [ exponential logarithm formula) Therefore x = 10 ^ 15/2 x = 10^ 7.5 = 10^ ( 7+ 0.5) x = 10^7 ×10^ 1/2 x = 10^7 × 3.16227766 x = 31622.7766

@@DommarajuJyothi very sorry, my fault, if f(x)=lnx, then f(x)^cube root +f(x)=10. {cube root √lnx +lnx=10, x=? , I know only the answer e to the 8}

( log x)^1/3 + logx = 10 Let a = log x a^ 1/3 + a = 10 a = 8 log x = 8 x = e^8

@@DommarajuJyothi 👍👍, EXCELLENT, may I ask you, which country are you from?

I am from India 🇮🇳

Absolutely right! Great job spotting that

Thanks for the feedback! Logarithms can be tricky but they're also really interesting .Do you have a favorite math concept or topic you'd like to see covered next?

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@@DommarajuJyothi l need such logarithm questions

Today's post is just what you needed! I posted another logarithm question, check it out and let me know what you think

Can you solve please: (49 to the logx) +7=8.(x to the log7)?

"Hi sir! Thank you for pointing out the mistake. You are absolutely right, the equation log(a + b) = log(a) + log(b) is not correct in general. I apologize for the error. The correct rule is log(a × b) = log(a) + log(b), known as the product rule of logarithms. I'll make sure to double-check my equations in the future. Thank you for helping me improve my accuracy!" Please subscribe my channel. Next time I will not disappoint you sir.

Thank you for sharing a more formal and precise proof using mathematical induction! Your approach is absolutely correct and provides a stronger foundation for the conclusion. By the recursively applying the formula and simplifying, you've elegantly shown that n!>A(n) for all n, including the specific case of 100! > A(100). Your input is invaluable. I appreciate the time you took to share your insight. This will certainly help others understand the problem more deeply. I hope you like the another concept that cubing of unique pairs 11^3, 22^3,... .If you like this content please subscribe my channel and we'll learn together.

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Hi, how are you

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Thankyou for your observation! While I didn't explicitly mention in the thumbnail that a &b are integers, I made sure to explain it during the video to ensure clarity for everyone. I appreciate your attention to detail and hope you found the explanation helpful!

@@DommarajuJyothi yeah i saw, great videos from you ! keep up as long as you enjoy it:)

Thank you.

" Glad you liked it!" Thanks for the encouragement

Thank you for your insightful input! I appreciate your suggestion for considering the general solutions of (1 + 2a) and (1 + 2b).

Thanks for sharing your approach! While setting a=0 simplifies the equation, it's important to note that it only works for specific cases. Exploring various scenarios,like negative integers, allows for a more comprehensive understanding of the problem. Both methods have their merits in different contexts.

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Ok mam

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Thank you, I really appreciate you taking time for me to express that. And please subscribe.

Thank you so much for your kind words! I'm glad you found the video helpful. If you have any more questions , feel free to let me know. Your feedback means a lot!" 🙏

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Thankyou for your insightful question about square roots! I appreciate your curiosity. If you have any more math queries, feel free to ask. As for the answer, square numbers end with 0,1,4,5,6 or 9. If a number ends with 2,3,7 or 8 that number is Non-perfect square number. " In my upcoming video, I'll be explaining perfect and Non-perfect square roots.

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