These type of supposed proofs are good for a laugh but that is as far as it goes. The proof is utter garbage. The problem with this video is the incorrect use of BODMAS rule. Brackets are the 1st operation required. this then leaves 1^2 = 1^2. ie 1 =1. Order or power is the 2nd operation in BODMAS and cant be performed (or as in the silly video, eliminated as it appears on both side of the equality. I would also like to point out that this isn't algebra either. Algebraic expressions must include at least one variable (pronumerals)
9^9^9 has 369693100 digits in it starting with 428124773175747048036987115930563521339055482241443514174753723053523887471735048353193665299432033375060417533647631000780326139047338608320802060374706128091655741320864460198619996145203105244285814895981151471949351767796559302159393385015023969426231052967581656943333463147492553849485933778120876249572165041952206018045713015178640510145940790419486633273366718306544107602348236334279338847...
@RyanLewis-Johnson-wq6xs2 күн бұрын
5^5^5^5>9^9^9
@modern.73732 күн бұрын
Well, 65 in not actually a huge number. You can try powerrs of 3, which are greater than 65. 81 is greater than 65, which is 3^4. 81 - 65 = 16, which is 2^ 4. Here is it