Successive Ionization Energies
7:17
6 жыл бұрын
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@Blood_Wolf0_0
@Blood_Wolf0_0 20 сағат бұрын
Just reading about this got me nowhere but this video did! Thank You!
@gracearmstrong1846
@gracearmstrong1846 Күн бұрын
Thank you. Your explanation is so clear and it really helps me understand this lesson.
@chelseafreeze7190
@chelseafreeze7190 2 күн бұрын
Another great video!
@CrashChemistryAcademy
@CrashChemistryAcademy Күн бұрын
Thanks!
@sumindasuranga8544
@sumindasuranga8544 3 күн бұрын
@Doggo-inc
@Doggo-inc 5 күн бұрын
Thank you!
@ISHVVN09
@ISHVVN09 6 күн бұрын
This is absolutely phenomenal, I mean of course not the condition of the world but the video. This is such a clear explanation of the science behind global warming without making a person have to research on 50 something websites for the same information. And the clarity with which it has been explained is something I cannot put into words. Thanks a ton!!
@CrashChemistryAcademy
@CrashChemistryAcademy 6 күн бұрын
Thanks! I appreciate the comment!
@Inmydreams444
@Inmydreams444 6 күн бұрын
Cca is also cca Crash chemistry academy is also coolest chemistry academy.
@CrashChemistryAcademy
@CrashChemistryAcademy 6 күн бұрын
🙏😁😎
@foxdoglazy
@foxdoglazy 6 күн бұрын
Using Stefan-Boltzman in equilibrium, CO2, being 0.04% of the atmosphere, contributes little to the total Earth emissivity of about 0.95. CO2 alone doesn't give a warming result. Estimates of atmospheric H2O are all < 5% but even if atmospheric H20 were to double to 10%, Stefan-Boltzman gives the new equilibrium temperate increase at < 1C. Is that correct?
@CrashChemistryAcademy
@CrashChemistryAcademy 6 күн бұрын
The fact that emissivity of CO2 is so close to 1 at relevant IR ranges supports its importance in radiative forcing as described in the video, and so supports its importance to warming. Atmospheric water vapor concentration is limited by the amount of liquid water (primarily in clouds and surface water) that enables condensing vapor to reach an equilibrium with evaporating liquid water, which is what we call 100% humidity. This equilibrium can get as high as 4% atmospheric water vapor in hot climates. If water reached 10% of atmospheric gases, that would likely be past water's tipping point and so the earth would be in a runaway warming, so likely no equilibrium would be reached, at least not before we are all dead. Quantifying emissivity will give the same warming values presented in the video.
@sanjitpaul2953
@sanjitpaul2953 6 күн бұрын
Excellent video Sir. Thank you.
@AXAXAXAYt
@AXAXAXAYt 7 күн бұрын
Liquid lover
@NyakaisikiShallot
@NyakaisikiShallot 10 күн бұрын
This is the best explanation so far. Ive really been on a search. Thank you.
@CrashChemistryAcademy
@CrashChemistryAcademy 10 күн бұрын
Glad it was helpful! Thanks.
@user-be5ig4hp2m
@user-be5ig4hp2m 10 күн бұрын
life
@Tharushi_SM
@Tharushi_SM 12 күн бұрын
There’s two electrons existing in one orbital right. Two electrons of different spin states specifically. So one electron interferes with itself to form a standing wave. But in an orbital, or better termed degenerate orbital, where the energy level is the same two electrons are existing. How are their standing waves not interfering?
@CrashChemistryAcademy
@CrashChemistryAcademy 12 күн бұрын
de Broglie’s 1924 model was a description of electron behavior justifying Bohr’s quantum electron (1913). The mathematics of Schrodinger’s 1926 equation was modified by Pauli (1926) to include his exclusion principle, which creates degenerate orbitals to account for the existence of multi-electron atoms. These mathematical expressions I believe do not specifically address de Broglie’s idea of wave interference beyond the separation of degenerate orbitals. The flaw here is that all occupied orbitals overlap at some point since all orbitals converge at the nucleus. So while I have not really answered your question (sorry) I do think the answer lies in Pauli’s modification of the Schrodinger equation.
@chelseafreeze7190
@chelseafreeze7190 13 күн бұрын
You're amazing.
@CrashChemistryAcademy
@CrashChemistryAcademy 5 күн бұрын
Thanks for watching!
@Manigo1743
@Manigo1743 13 күн бұрын
"He had no reason to suspect that anything would happen". I wonder why he did the experiment then.
@CrashChemistryAcademy
@CrashChemistryAcademy 10 күн бұрын
Rutherford had done prior experiments with different metals that gave the same result as gold. For Rutherford, these experiments confirmed Thompson's atomic model and strongly suggested there could be no other result-- he assumed looking beyond a 2 degree range would yield nothing. However, being the consummate experimentalist that he was, in addition to knowing the substructure of the atom was resting on indirect evidence, he understood that the model could be wrong, even if he did not believe that would be the case. Additionally, he wanted to strengthen his conclusion of the validity of Thompson's model by showing there were no deflections beyond the 2% range. So he went ahead and looked for deflections a full 360 degrees around the gold foil. The positive results strongly showed a revision of the model was required.
@Felicias_demons
@Felicias_demons 13 күн бұрын
OMG. I`m a second-year biotech student, and FINALLY, I UNDERSTOOD THIS STUFF. I love that Mr. Crash explained it so simply, without all fancy words. My tutors are so furious that I don`t get all chemical names and that I can`t remember such basic things, and okay, sorry, it`s hard for me to get everything oral, I need pictures and simple words. THAT`S ALL I`M ASKING FOR. SO THAAAAANK YOOOOOUUUUU SOOOOOO MUUUUCHHH!!!!
@ISSACNewtonAdvanced
@ISSACNewtonAdvanced 15 күн бұрын
Your video was the only in which my eyes didn't got red
@nuttyrl
@nuttyrl 18 күн бұрын
THANK YOU
@CrashChemistryAcademy
@CrashChemistryAcademy 17 күн бұрын
You’re welcome! Thanks for watching.
@PhilMoskowitz
@PhilMoskowitz 18 күн бұрын
Schrodinger based his model on de Broglie's theory. Heisenberg did not and use matrices instead.
@joelweiner4156
@joelweiner4156 18 күн бұрын
Yes, but Heisenberg's (1926) model was the same as Schrodinger's (1926), based on the electron's energy manifesting as a wave. A mathematician (forgot who) in 1926 pointed out the the two mathematical expressions were describing the exact same atom, the same electron behavior, and in 1930 Paul Dirac combined the two into a single formalism.
@kisho2679
@kisho2679 18 күн бұрын
how can the amount of energy for each sublevel (s,p,d,f) per shell (1,...,7) be calculated?
@h7opolo
@h7opolo 20 күн бұрын
my neocortex has developed another drupelet on that dedicated to the relatively unfamiliar "electron orbitals" drupelet, folds upon folds.
@CrashChemistryAcademy
@CrashChemistryAcademy 19 күн бұрын
Love the neocortex. Neocortical folds make for a manifold understanding of folds of atomic orbitals and folds of hybrid orbitals. For one more drupelet, I plan (soon!) on adding a video on molecular orbitals, for a final fold upon folds upon folds. By the way, love the drupelet metaphor. I never would have thought of it. Thanks! : ) BTW #2, if you really are lacking familiarity with electron (atomic) orbitals, see my video kzfaq.info/get/bejne/e92WarWdu7Smg3U.html
@airm9366
@airm9366 22 күн бұрын
Thanks man this helped a lot I have to retake a final and this was a subject I was really bad at thank you
@garymcleod6772
@garymcleod6772 22 күн бұрын
Reading Peter Atkins book,”Atoms, Electrons and Change.” He used Faraday’s lecture on the candle flame to introduce the same principles. Your video was a tremendous help in understanding this phenomena.
@CrashChemistryAcademy
@CrashChemistryAcademy 19 күн бұрын
I loved reading Faraday's lectures on the candle. The guy was too brilliant. I created an entire lab for my students based on his experiments. I also love reading Atkins. I'll have to take a look at that one.
@Cloud-ow4jr
@Cloud-ow4jr 25 күн бұрын
Thank u so much sir.. this helped me a lott
@CrashChemistryAcademy
@CrashChemistryAcademy 19 күн бұрын
Thanks! You're very welcome.
@aprilc.4029
@aprilc.4029 28 күн бұрын
Hi there - the link says the file is in your trash folder. Would love to have it if its hosted elsewhere? TY!
@CrashChemistryAcademy
@CrashChemistryAcademy 28 күн бұрын
Hi- sorry I just retired (!) and these files were on my school account which has been closed. I’ll have to dig them up and will post them ASAP! Thanks for asking!
@CrashChemistryAcademy
@CrashChemistryAcademy 26 күн бұрын
I found them. This is the MSWord file, the formatting requires MSWord-- docs.google.com/document/d/1yUeVy6xfQ_50EK1dLCaa3SbjrlZjD0Yd/edit?usp=sharing&ouid=116884422502737165564&rtpof=true&sd=true and this is a pdf of the Word file drive.google.com/file/d/1TX2Kzdsw1HQyIzsHsL6ZDaRCkvkKzftb/view?usp=drive_link
@critiqueofthegothgf
@critiqueofthegothgf 29 күн бұрын
I periodically come back to this lecture as I make my way through an environmental science degree and it never disappoints.
@CrashChemistryAcademy
@CrashChemistryAcademy 28 күн бұрын
Thanks so much for a very gratifying comment. You should know (if you haven’t already noticed) that I pinned a previous comment and my answer regarding the potency of CO2 versus CH4, something that was not well considered in the video narrative.
@orangethew
@orangethew 29 күн бұрын
no matter how much old the video gets the teaching and explanation is always on the top tier
@CrashChemistryAcademy
@CrashChemistryAcademy 19 күн бұрын
Thank You!
@brenofrancisco3745
@brenofrancisco3745 29 күн бұрын
Professor, you're amazing. I'm learning a lot. Thank you very much.
@CrashChemistryAcademy
@CrashChemistryAcademy 19 күн бұрын
Great! Thanks for the comment!
@richardsreviews8820
@richardsreviews8820 Ай бұрын
I found this very informative. Thank you.
@CrashChemistryAcademy
@CrashChemistryAcademy 19 күн бұрын
I'm glad it was helpful!
@ayaaltamimie8911
@ayaaltamimie8911 Ай бұрын
you deserve the world I've been trying to fit this in my head and I couldn't my brain wasn't braining and u brained it, I love youuuuuu.
@CrashChemistryAcademy
@CrashChemistryAcademy 19 күн бұрын
Thanks for the comment. Luv u 2!
@AFRICANDIVA
@AFRICANDIVA Ай бұрын
OMG!
@veergupta7143
@veergupta7143 Ай бұрын
I want heat question and answer For class 7
@xmsuper2909
@xmsuper2909 Ай бұрын
why !i want to know the sp2about N
@fitnessbeasts_
@fitnessbeasts_ Ай бұрын
phenomenal explanation, thank you
@CrashChemistryAcademy
@CrashChemistryAcademy 19 күн бұрын
Thanks for your comment!
@random.__.2
@random.__.2 Ай бұрын
I CAN'T CONVEY TO YOU HOW MUCH THIS VIDEO HAS HELPED ME!! THANKS A LOT :D
@CrashChemistryAcademy
@CrashChemistryAcademy 19 күн бұрын
I'm very glad it helped!
@aybuke8552
@aybuke8552 Ай бұрын
thanks 🇹🇷🇹🇷
@haywoodjohnson2865
@haywoodjohnson2865 Ай бұрын
Well done 👏 ✔️ 👍 👌 😀
@AnaReene
@AnaReene Ай бұрын
I don't really understand chemistry
@AnaReene
@AnaReene Ай бұрын
I don't understand
@kisho2679
@kisho2679 Ай бұрын
Since for the electron configiration of the d-bock periods you have to subtract -1, so why are those d-block periods not just depicted one row abowe in the periodic table of elements (then it would be easier to directly read instead of conducting this subtraction as exeption)?
@CrashChemistryAcademy
@CrashChemistryAcademy Ай бұрын
The periodic table was originally organized according to properties and weight (1869), the weight was replaced by #protons (1917), but that did not change the organization. That organization was later found to fit perfectly with electron organization (late 1920s). So the answer to your question lies in electron organization and Schrodinger's original quantum mathematics from 1926. The mathematics gives a simple formula for how many electrons will occupy a given energy level (principle quantum number, n), which is 2n^2. Another organizing principle is that when going from one block to another on the periodic table, the added electron will go to the next higher energy level in the very specific order given in electron configurations. This is the aufbau principle. OK, so what happens when going from 4s to 3d? The issue here is that 1) the 3d orbital has a slightly higher energy than the 4s orbital, and so 3d has to be filled after 4s. 2) This also allows for the fullfilment of the 2n^2 rule. The reason 3d has more energy than 4s is due to angular momentum. The shape of the 3d orbital is far more convuluted than the simple sphere of 4s, which in turn requires that the 3d electron have a much greater angular momentum (which translates to more energy) than a 4s electron. The same explanation tells us why 4f comes after 6s, and why 5d comes after 4f. I hope that makes sense!
@kisho2679
@kisho2679 Ай бұрын
Thx
@masha22092000r
@masha22092000r Ай бұрын
You saved my life. Why can't college professors explain it this easily - God knows...
@siderealvictor9813
@siderealvictor9813 Ай бұрын
Daymm that was perfectt ty
@chickpeaperry4786
@chickpeaperry4786 Ай бұрын
Thank you so so much this was an absolute game-changer for me I really appreciate it
@Pinkshark27
@Pinkshark27 Ай бұрын
i JUST WANT TO TELL YOU THANK YOU SO MUCH YOU DONT EVEN UNDERSTAND I'VE NEVER HAD SO MUCH FUN, EASE AND UNDERSTANDING WITH CHEM ESP CALCULATIONS THANK YOU SO MUCHHHH
@CrashChemistryAcademy
@CrashChemistryAcademy Ай бұрын
I'm always happy when people are having fun! Thanks for the comment!
@Shojomanganosekai
@Shojomanganosekai Ай бұрын
this person is wonderful
@theclassroomdoc
@theclassroomdoc Ай бұрын
Ridiculously amazing! THANKS
@b1ack_x
@b1ack_x Ай бұрын
wow, more than like half the ppl in the comments here are probably graduated in college, really hope i can join the bunch
@CrashChemistryAcademy
@CrashChemistryAcademy Ай бұрын
I graduated college in 1982. It's been a fun 42 years, especially after the discovery of youtube. I believe it was at an archeological dig in the Mohave.
@_iha
@_iha Ай бұрын
THANK YOU!!!!!!!!!
@youremyaddiction3801
@youremyaddiction3801 Ай бұрын
OH GOD THIS IS THE BEST VIDEO THRU OUT THE YT!!!!!!!!!!!!! THANKS ALOT MAN!
@CrashChemistryAcademy
@CrashChemistryAcademy Ай бұрын
Thanks for the comment!
@anueid.studios
@anueid.studios Ай бұрын
At 3:58 why did you put 18.2 nm * 1 cm / 10^7 = 1.82 * 10^-6?? why didn't you keep it as 18.2 * 10^7 ? is it because since it's in the denominator, it needs a negative exponent to show we are dividing ??
@CrashChemistryAcademy
@CrashChemistryAcademy Ай бұрын
Sorry it took a while to get back. When dividing by a positive exponent (= dividing by a large number) the result is a small number. And dividing by a large exponent, in this case 10^7, is exactly the same as multiplying by its inverse, which is 10^-7. Notice the exponent is still the same, however it is now negative instead of positive, which gives the same small number as if you were dividing. NOW, the answer could have been written as 18.2 * 10^-7, which would be correct. I moved the decimal to the left one digit, so it is now 1.82, to follow the convention of writing scientific notation with the decimal after the first number. This makes the coefficient ten-fold smaller than 18.2, and so to compensate and keep everything equal, the exponent must become ten-fold larger: 10 x 10^-7 = 10^-6. So 18.2 x 10^-7 = 1.82 x 10^-6. Hope that makes sense.