Sorry, no at the moment. I have 2d drawings only and some of them need to be redrawn to include corrections.

@@AccidentalScience ok. Loved the entire build process. Thinking if building a metal lathe myself. Would you say it was cheaper than just buying a metal lathe?

@@Demon_Mx2277 no it's not. But it could be more precise (that depends on your skills and equipment) and could better fit your needs . Certainly you get the chance to learn a lot in the process.

i like your sense of humor.

@@sergionowa thanks mate.

And a material list

Sorry at the moment it's not available. Maybe I'll do something sooner or later. Mi dispiace al momento non disponibile. Forse fraro' qualche cosa presto o tardi.

Exactly you got the point. 💙 Thanks for commenting and greetings from the Alps.

Glad it was helpful!

What do you mean?

I acknowledge your concern. It was meant as kinda joke, but I overestimated my ability to communicate it was a joke. I apologize. So I have replaced the thumbnail with something that I hope is better both at attracting people and to be felt less "awful cringe". Thanks for the feedback.

Hi Bob, good catch!

You *must* have a single ground. I mean a grounded spike to which all grounding convey, including the PE line. Power the oscilloscope referencing to that ground. Then use a couple of active differential probes rated at not less than 1000V. The measurement must be performed knowing the procedures of how to handle high voltages and you must know what you're gonna do because this could be lethal! I won't take liabilities. On the oscilloscope use math functions to know the difference between the two AC sources. You mention 460V RMS and ~651V RMS ...I don't think this is correct starting from 230VAC RMS, I'm afraid you keep confusing RMS with peak and peak to peak. Oscilloscopes *always* display peak to peak voltages. For voltages out of phase you can't really use the root square of 2 to go back and forth RMS. About the problem you face with that inverter I have a similar issue with a hybrid solar inverter, made by Voltronic, China. I have had no chance to investigate the problem deeply enough but it seems the problem arises from the fact that the inverter must disconnect neutral from ground when running over the grid, and reconnect it to ground when running over solar panels and batteries (UPS mode). What you describe, two separate neutrals, seems quite weird but for those inverter designed to run on two phases grids (no neutral) that are in use in some corners of the world. It seems an interesting case.

Go to the website: accidentalscience.com

First off thanks for commenting. Indeed your comment could be of help for others. It could be helpful because many could confuse some points that clearly I have taken for granted when they'd not ...that's the curse of people with experience :) The current value is correct: around 320uA @ 230VAC. So why it is correct? An oscilloscope do not take the RMS voltage but the peak(+DC) voltage, while it shows the peak to peak voltage. I know, this may arise even more confusion, but don't worry, follow me. Let's take a sine wave that you want to measure at the oscilloscope. The instrument will show the sine wave from a reference point that is the GND (ground) level. In respect to GND the alternate sinusoidal signal swings from zero to full positive; then back to zero (GND); then down to full negative and finally back to zero again, where the cycle start over again. So what you actually see on screen is a wave that swings from peak to peak. However what matters for the input circuit is the voltage peak as an absolute value, which is the maximum allowed voltage in respect to ground irrespective of the polarity. Indeed if we look at the specifications of an oscilloscope they tell us the maximum input voltage that is meant as peak+DC voltage. In other words it is the absolute maximum voltage, be it AC or DC. So speaking about a possible voltage to measure I took as a reference example 230VAC, the mains voltage in EU. Mains voltage is alwasy declared as RMS voltage. So, for a sine wave with a 230 RMS voltage, for the purpose of finding the voltage that the oscilloscope's input matter we need to find out the peak voltage. Which for such a sine wave is: 230 times the square root of two, or simply 230 * 1.41 = 324.3 Vpk. When we compute the current across a resistor usually we compute it as DC or peak value, rarely as RMS value. And since we want to know the voltage at the input of the oscilloscope we have to calculate the peak value. So the math is as follow: Input voltage 324 Vpk / (990Kohm + 10Kohm) = 324uA. Remember, the current flows through both resistors to GND. Now because we know the current, and because the same current flows on both resistors, we can compute the voltage across the 10K resistor: 324uA * 10K = 3.24Vpk. Notice we should also consider the input impedance of the oscilloscope which happens to be in parallel with the 10K resistor. Though since this impedance is about 1Mohm at DC (or at very low frequencies such as 50 or 60 Hz) it doesn't change much our computations: 1/ ((1/1M) + (1/10K)) = 9900 ohm, actually an added attenuation of 1% . The probe x1 change anything as it is just a chunk of wire. Now, about the safe usage of the instrument, understanding that you are not that experienced, I'd recommend you to avoid taking measurements from mains. Instead use it to make measurements of small voltages of devices fully insulated from mains. In such a case it is quite safe to use in any condition. I never heard of that brand/model of oscilloscope, BTW. Hope this will be helpful. P.s. Thanks for love. Love+Peace.

@@AccidentalScience I got your point! For all practical purposes, regarding AC voltage or current we talk about it's effective value, the root mean square RMS value that is equivalent to its counterpart DC's heating effect. It's the peak value of the AC V or C 'times' the Inverse of Square Root of 2 = 0.7071 In true measurement one has to consider the Peak Voltage or Current of the AC that's RMS value times √2=1.4142. So it would be around 325 uA. This has to be accommodated resistance and capacitance calculation. I'm grateful for reminding me!

Unfortunately faulty encoders are tricky to test without a specific instrument that basically compares pulses vs angle, count them and check the maximum throughput. A simple tester can be made with an Arduino, a precision photocoupler and a rig for the encoder to test. Also an oscilloscope is required as well.

It's my own design.

Thank you mate.

I read his whole paper and I don't remember he mentioned any kind of hexagon shaped surface. But I agree, the hexagon is the bestagon, after all :)

@@AccidentalScience From the book "The Whitworth measuring machine" 1877 page 7 "Sir Joseph Whitworth has lately patented an hexagonal surface plate with the view of preventing irregular straining the points of attachment" - With illustrations. from page 8: "Surface plates on the principle now referred to are found to possess so many advantages over the old rectangular plates that Sir Joseph Whitworth has adopted them throughout his workshops, and has ceased to use any others" Also in an oil portrait of him by Kennington he is depicted with a pair of them. Of course He did make other shapes too. You can get that book free online, its worth reading.

@@billshiff2060 great thanks for the information. I was thinking about his original paper, I missed that you said he "settled", sorry for the mistake.

@@AccidentalScience No problem. It gave me a chance to talk about his work which I admire. Even though he couldn't get along with anyone he achieved great things. His mentor Henry Maudslay on the other hand was much loved by all and became the father of machine tools but more memorable as a builder of men, including Whitworth and a legion of others. Every time I research any subject I find Maudslay somewhere in the back story.