Hi, can you explain what material have you used to do the circuit? Thank you.
@squidwardsbussyАй бұрын
do u wanna play fortnite duos with me
@squidwardsbussyАй бұрын
nvm u sound british
@user-if3jd9yf5dАй бұрын
Thank you so much. And one think that might help is that, you need to hold the paper/ phone screen perpendicular to your desk not on it
@darcy4522Ай бұрын
I sometimes struggle on the harder questions like with laptops being at angles opening. I find it hard to recognise some of the angles and perpendicular line of action. The ones that arent apparent. I dont know why, I just hope it clicks like the rest did at some point. Videos like these really help. Thank you.
@josephh067Ай бұрын
for number 30 why do you divide by 4 at the end
@AR2K77Ай бұрын
31:55 isn't your reason for choosing option B basically what option A implies?
@BlueBoy75262 ай бұрын
thanks for the great vid
@ufrsn2 ай бұрын
Great video
@YukonD22 ай бұрын
👺👺👺👺👺👺👺👺👺👺👺
@justineverett50123 ай бұрын
thank U
@IQTIDAARISMAIL3 ай бұрын
Thanks for the great vid
@tanishshah65363 ай бұрын
can you make a pdf of your topical question and then put it in your videos?
@justmustafa55133 ай бұрын
idk if you're going to see my comment, but I love you bro, all this for free is mad
@user-or2kp2ns7k3 ай бұрын
u are so great sir
@myan_mi3 ай бұрын
For part a, how do we know the phase difference?
@alexhunderson97783 ай бұрын
11b should be X(-35)not +
@user-gg2ri6dl8r3 ай бұрын
Thank you for the well paced explanation because of you I scored 167/170 in Physics in my mocks with A*!!
@hm.cooking6694 ай бұрын
❤
@takdirsaiful6284 ай бұрын
Hi is dis for ocr a?
@burrowsphysics4 ай бұрын
pretty sure this is for AQA A but the electricity questions are pretty much the same in both
@storm_17844 ай бұрын
Where is section A
@user-zj9ft2hl4h4 ай бұрын
Guapo!
@bigg.grizzlybear26705 ай бұрын
1:41, Why did you use the parallel formula for the two 30 ohms resistors? Are they in parallel the two 30 ohm resistors?
@burrowsphysics4 ай бұрын
Yes there are 2 parallel routes taking you from X to Y. One with a resistance of 60 (30+30) and the other with a resistance of 40 (20 + 20), hence the use of the parallel formula
@unstudystudytube5 ай бұрын
amazing video
@user-lf6ds3fb3x5 ай бұрын
This was genuinely so helpful, thankyou so much because I can never seem to find good exam questions on youtube.
@blinkyrob1825 ай бұрын
Excellent video - thanks for the upload 👍
@fidaaghanem21215 ай бұрын
Is the wasteful energy always thermal energy?
@burrowsphysics5 ай бұрын
There is often more than one type of wasted energy by all processes produce thermal energy to some degree. However remember that sometimes the heat is useful energy e.g. a kettle so heat is always produced but it is not always waste
@pratyasha2796 ай бұрын
is charge carrier density different to/same as number density?
@burrowsphysics6 ай бұрын
Yes same thing
@pratyasha2796 ай бұрын
Sir do you have a video about all of the derivations we need to know (1st year OCR physics) ? Kindly suggest..
@burrowsphysics4 ай бұрын
No I don't, it i has been a while since I taught OCR but I don't recall students having to know derivations (might have changed since however)
@pratyasha2796 ай бұрын
can we make summary sheets for each module based off of these videos (as another piece of revision)? Kindly suggest
@burrowsphysics6 ай бұрын
I wouldn’t recommend that. Too many people consider making notes revision, the only real way to revise physics is practice questions and seeing constantly how to answer better
@pratyasha2796 ай бұрын
Alright sir, thank you!@@burrowsphysics
@jaideeppatil44146 ай бұрын
In the question at 17:42 can not solve it with the E.M.F = V+Ir formula, because when I try to solve it the r comes 0 ohms?
@ethan01736 ай бұрын
for the last question, can you not find that the horizontal component of T is T*tan24, therefore you can use pythag (root T² + T*tan24²) to find the hypotenuse which is the perpendicular distance from the pivot
@ethan01736 ай бұрын
then do the hypotenuse*2.5 =8F and then solve for F
@yall28426 ай бұрын
4:47 Why does the displacement time graph start at a displacement of >0?
@burrowsphysics4 ай бұрын
Well the position where displacement is zero is entirely arbitrary so why not start > 0 (or less than zero for that matter). You can make whatever point you like a displacement of zero (the origin) You do often see the initial position defined as the origin so having a displacement of zero but there is no rule saying it has to be and sometimes it is useful not to have the initial position = 0 displacement
@MuhammadQasim-th3ed7 ай бұрын
Brilliant explanation sir ...💛👼🔥👍
@legendaryarchie65128 ай бұрын
Whatsup Neil goldman
@edwardmerritt3588 ай бұрын
But this doesn't work if your X values are different for each data set. Do you have a workaround for that? For instance, if your coordinates for one set are 1,10: 3, 13: 5, 16 and for the second set they're 2, 12: 4, 15: 6, 18 the graph will only use the X variables from the first set and not use the 2nd set of x points.
@burrowsphysics8 ай бұрын
The solution that occurs to me would be to use the biggest values in the first set of data.
@idiaics8 ай бұрын
on number twelve why are we transforming kw to w if the result is in kw??
@burrowsphysics8 ай бұрын
Fair question. Out of habit I always change everything into SI units at the start, could have saved time by not but I tend to think that is a good habit to be in
@IMRANA-q1v8 ай бұрын
crazy how this was actually my hw.
@itaniloagotobedza25288 ай бұрын
Thank you
@jamespeter90639 ай бұрын
felt like I got told off throughout the video
@floce70808 ай бұрын
Word😂😂
@0ned9 ай бұрын
7:50 See James DeMeo and Maurice Allais on Dayton Miller. The ether rotates slightly faster than the earth, like a gentle breeze on a high speed sailboat keeping time with the wind.
@0ned9 ай бұрын
That's why Michelson & Morley found barely ten mile an hour ether wind in a stone basement at sea level but Dayton Miller found much greater speed ether wind and with regularities at times of day and year in a wooden and glass structure atop Mount Wilson.
@0ned9 ай бұрын
To paraphrase Marco Todeschini, Relativity is Galilean, Classical Invariance.
@0ned9 ай бұрын
Yo, fake! Michelson Morley disproved Maxwell's equations BEFORE Poincarré perverted them and Einstein plagiarized them. To rephrase, Kelvin's equations deriving 10³³ergs/cm³ replaced E=MC² before Einstein plagiarized it. Hermann Fricke's hydromechanical ether replaced Kelvin's superfluid ether and vortex mechanics were replacing wave mechanics before the Nazis stole power and burned libraries of now censored history. Back to your historical research, maybe history of engineering because it's empirical physics, practical physics, not theoretical physics. Fricke was an astrophysicist but Ott Christoph Hilgenberg sacrificed a successful career teaching history of engineering to become a librarian saving libraries from both Nazi and Soviet book burning. Carl Frederick Krafft, originator of the vortex mechanics, also, was an engineer, specifically a US Patent Clerk.
@shashininethmini89119 ай бұрын
🎉🎉🎉🎉🎉🎉🎉🎉❤❤❤❤
@SP-hr1fc10 ай бұрын
Where can I find these types of questions?
@Anna-pw4db10 ай бұрын
Thank you for your video. I was wondering, why is there a reaction force at the pivot, O? I'm confused since the force V acts in an anticlockwise direction and the force of gravity G acts in a clockwise direction, so why would we need a reaction force to balance them out? And why is the reaction force at the pivot point an upward force? Is that always the case at a pivot point? Thank you in advance.
@burrowsphysics10 ай бұрын
So addressing those backwards. The reaction force at the pivot is not always upwards, it just happens to be in this case. In reality the pivot force is in whatever direction required to keep the object in equilibrium. In this case because all the forces are up or down, in this case it ended up being upwards. Also remember it is not just the moments that need to be in equilibrium, the forces also need to balance out. If you look at the magnitudes of the other forces you can see they don't balance without a reaction force.
@Anna-pw4db10 ай бұрын
Thank you so much for your reply, it was very helpful! 😊
@HostileLemons10 ай бұрын
Great!
@aryaman19311 ай бұрын
i dint get q at 9:20 pls explain
@nestorynelenge968811 ай бұрын
What could be the limitations or the uncertainties to this experiment and to improve them?
@goranmalmsten5306 Жыл бұрын
13:15 Not always true. The non-driving wheels on a vehicle are affected from the ground by static friction forces pointing backwards. But those forces are present only for the rotation of the wheels, are not slipping and are not braking on the car.
@goranmalmsten5306 Жыл бұрын
6:00 How does the resistive force F work on the car?
@burrowsphysics Жыл бұрын
So there are typically 2 resistive forces. The main one is drag or air resistance from air particles colliding with the car, the other is rolling resistance which is a frictional force e.g. when the axle is rotating it rubs against its surroundings
@goranmalmsten5306 Жыл бұрын
Thanks for a quick answer. Air resistance is directed backwards but velocity dependent. The other friction forces, by some people called "rolling friction", are working inside the car, not on the car. Those internal forces have no special direction backwards and cannot be included in Newtons second law. A very common misconception. Newtons second law is not valid for vehicles on wheels, only for rigid bodies.
@kpopeditsz Жыл бұрын
this is so hard, i dont think u explained very well personally..