20c - 🔴MIDSEM EXAMS: Norton's Theorem Problems

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SkanCity Academy

SkanCity Academy

Күн бұрын

20c - MIDSEM EXAMS: Norton's Theorem Problems #knust
In this video we are going to learn how to solve circuit problems using Norton's theorem.
Norton's theorem states that any linear circuit connected between two terminals can be replaced by a Norton's current IN in parallel with a Norton's resistance RN.
To find the current flowing in a resistor;
1. Remove the resistor you want to find the current through and mark the terminal
2. Find the IN using KVL
3. Deactivate all independent sources, open circuit current sources and short circuit voltage sources and find the RN
4. Produce the Norton's equivalent circuit and reconnect the resistor you removed.
5. Find the current through the resistor using the formula I = RN/(RN + RL) * IN
00:00 - Problem 1
10:01 - Problem 2
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Пікірлер: 82
@winter.k.mwanza9932
@winter.k.mwanza9932 Жыл бұрын
Thanks for the good work🙏. Request: Could you make a video on Millman's Theorem.
@jdanderson9727
@jdanderson9727 Жыл бұрын
Thanks for the help. Very few examples out there with more than two sources. I needed this.
@SkanCityAcademy_SirJohn
@SkanCityAcademy_SirJohn Жыл бұрын
You are welcome
@MemorizeQuranEasy
@MemorizeQuranEasy 2 жыл бұрын
Thanks
@MemorizeQuranEasy
@MemorizeQuranEasy 2 жыл бұрын
Please record a video on Reciprocity Theorem
@jdanderson9727
@jdanderson9727 Жыл бұрын
Also, now that I have a Norton equivalent of my multi-source project, I would like to see what the Thevenin equivalent is. If you were to explain it as well as you did here, it would build my confidence.
@SkanCityAcademy_SirJohn
@SkanCityAcademy_SirJohn Жыл бұрын
Kindly check the playlist on applied electricity you will see lessons on thevenins theorem
@siphesihlenkosi
@siphesihlenkosi 8 ай бұрын
For the second calculation , why are we adding the 20 Ohm to RT ' , because current takes the easy route , so there wont be current flowing in 20 ohm , since its connected parallel to IN' ?
@SkanCityAcademy_SirJohn
@SkanCityAcademy_SirJohn 8 ай бұрын
No, that is not the case, IN' is not in parallel with the 20ohms due to 4 ohms you see there. Assuming the 4ohms was absent, then you claim will be true. At the point you should realize that the 20 and 4 are parallel connected hence 20 should be factored on the calculation for RT'
@BrianKipturu-yc2kh
@BrianKipturu-yc2kh 17 күн бұрын
Good work but try explaining some parts in detail,,Kindly🙏🙏🙏
@SkanCityAcademy_SirJohn
@SkanCityAcademy_SirJohn 17 күн бұрын
Thank you very much for your comments. Concern noted. Thanks for watching
@clevermwiinga3106
@clevermwiinga3106 2 жыл бұрын
Perfect explanation sir keep it up
@SkanCityAcademy_SirJohn
@SkanCityAcademy_SirJohn 2 жыл бұрын
Thanks so much, Clever. Where do you watch me from?
@user-zo5wu8os7n
@user-zo5wu8os7n 6 ай бұрын
clear explanation great!!!
@SkanCityAcademy_SirJohn
@SkanCityAcademy_SirJohn 6 ай бұрын
Thanks so much for watching
@user-zt4ev6we4j
@user-zt4ev6we4j 9 ай бұрын
Thank you ❤❤❤
@SkanCityAcademy_SirJohn
@SkanCityAcademy_SirJohn 9 ай бұрын
You are most welcome
@mohubemahlatsephaladi6246
@mohubemahlatsephaladi6246 3 ай бұрын
Hi sir if i solve norton's theorem exactly how you taught us how to solve thevenin i'm still correct right i mean in terms of finding vth?? i don't know if you get my question.
@SkanCityAcademy_SirJohn
@SkanCityAcademy_SirJohn 3 ай бұрын
That's correct, but you still need to do it how I taught you
@21khalid8
@21khalid8 Жыл бұрын
the second example what if the sources are more that 2 like 4 can i still use the superposition
@SkanCityAcademy_SirJohn
@SkanCityAcademy_SirJohn Жыл бұрын
Yes, you can still use superposition
@21khalid8
@21khalid8 Жыл бұрын
@@SkanCityAcademy_SirJohn so i will let out alone all the sources and add them together to get IN
@SkanCityAcademy_SirJohn
@SkanCityAcademy_SirJohn Жыл бұрын
Yes please
@user-or8eh1mh6p
@user-or8eh1mh6p 5 ай бұрын
Thanks alot dear am helped
@SkanCityAcademy_SirJohn
@SkanCityAcademy_SirJohn 5 ай бұрын
You are most welcome. And thanks for watching.
@user-jg1pz2fy1x
@user-jg1pz2fy1x 3 ай бұрын
good job on electronics
@SkanCityAcademy_SirJohn
@SkanCityAcademy_SirJohn 3 ай бұрын
Thanks so so much
@emmanuelboatengjunior9910
@emmanuelboatengjunior9910 Жыл бұрын
Please I have a question...... In example 1, why did you choose 2 and 6 to be in series over 8 and 6 when solving for the Norton's Resistance?
@SkanCityAcademy_SirJohn
@SkanCityAcademy_SirJohn Жыл бұрын
Okay, so we are asked to find the nortons resistance that is being viewed from ab. So you assume a voltage source between the terminal ab, the current that is produced by v is divided at the node where 8 and 6 are connected, hence they are not in series. Mind you the current that flows through 6 is same through 2, (series) . Don't make the mistake to view from the extreme right, with that 8 and 6 will be in series.
@emmanuelboatengjunior9910
@emmanuelboatengjunior9910 Жыл бұрын
@@SkanCityAcademy_SirJohn Well understood Gratitude
@SkanCityAcademy_SirJohn
@SkanCityAcademy_SirJohn Жыл бұрын
You are most welcome
@NANOR_OB
@NANOR_OB 5 ай бұрын
pleae can you just use the norton theorem procedure alone without SUPERPOSITION
@SkanCityAcademy_SirJohn
@SkanCityAcademy_SirJohn 5 ай бұрын
Yes, you can.
@paiterhammondkodua
@paiterhammondkodua 5 ай бұрын
Why didn’t you take the last loop but the second one on the first example
@SkanCityAcademy_SirJohn
@SkanCityAcademy_SirJohn 5 ай бұрын
Can you be more precise by stating the exact time in the video for easy reference?
@excalibirb9204
@excalibirb9204 Жыл бұрын
Geez Louis, use source transform dude. Your method is like the second most tedious method next to node and mesh analysis.
@SkanCityAcademy_SirJohn
@SkanCityAcademy_SirJohn Жыл бұрын
Thank you, but that willl be for another video
@ebodonkoh6636
@ebodonkoh6636 2 жыл бұрын
Question of reciprocity
@SkanCityAcademy_SirJohn
@SkanCityAcademy_SirJohn 2 жыл бұрын
noted
@xavier2704
@xavier2704 2 жыл бұрын
boylsted or sadiku Which one is good
@SkanCityAcademy_SirJohn
@SkanCityAcademy_SirJohn 2 жыл бұрын
Both of them are quite good...you can complement one with the other
@addetnancy7401
@addetnancy7401 8 ай бұрын
I used super mesh to solve number 2. Why isn’t it possible
@SkanCityAcademy_SirJohn
@SkanCityAcademy_SirJohn 8 ай бұрын
It is possible, I guess you have an error in your calculation
@fakhir_26
@fakhir_26 Жыл бұрын
Sir you not add super position theorem in problem 1 and add super position theorem in problem 2 , how wo detect in which problem we add super position theorem??? Kindly clear me please 🙏
@SkanCityAcademy_SirJohn
@SkanCityAcademy_SirJohn Жыл бұрын
Superposition theorem was used for all two questions, superposition theorem is used when you have more than one source in the circuit.
@oluwatobioyedokun5039
@oluwatobioyedokun5039 3 ай бұрын
​​@@SkanCityAcademy_SirJohnThen why are these circuits solved separately unlike the problems in the first and second questions sir? And is superposition also used in solving thevenin's theorem problems as well?
@SkanCityAcademy_SirJohn
@SkanCityAcademy_SirJohn 3 ай бұрын
@@oluwatobioyedokun5039 yes, you can combine superposition with thevevin or norton's theorem. the issue is, you can solve superposition theorems without involving thevenin or norton, however, we choose to combine them when the circuit looks complex. but if you can do it without involving thevenin or norton, then its fine.
@oluwatobioyedokun5039
@oluwatobioyedokun5039 3 ай бұрын
@@SkanCityAcademy_SirJohn thank you sir
@Olakk20
@Olakk20 6 ай бұрын
On problem number 1 how to get the load resistance (Rl) pls answer my question thank you:(
@SkanCityAcademy_SirJohn
@SkanCityAcademy_SirJohn 6 ай бұрын
The load resistance is already in question, it's the resistor you removed before starting the whole solution process.
@Olakk20
@Olakk20 6 ай бұрын
​@@SkanCityAcademy_SirJohnI checked it's 2ohms not 4ohms how to get 4ohms Rl
@Olakk20
@Olakk20 6 ай бұрын
How to get 4ohms Rl?
@SkanCityAcademy_SirJohn
@SkanCityAcademy_SirJohn 6 ай бұрын
@joshuabumanglag9199 please check the question, the load resistance is 4
@Olakk20
@Olakk20 6 ай бұрын
@@SkanCityAcademy_SirJohnafter 8 ohms? series? is that the ohms resistor? right?
@addetnancy7401
@addetnancy7401 8 ай бұрын
I don’t know if my method of approach is okay, but I used; In = 3 + I (kcl) Using kvl; first loop 25 = 5*I + 20*I Solving this should result to 1 From kcl, In= 3+1 = 4
@SkanCityAcademy_SirJohn
@SkanCityAcademy_SirJohn 8 ай бұрын
Equation for mesh 1: 25 = 25 i1 - 20 i2 Equation for super mesh 0 = -20 i1 + 20 i2 + 12 i3 Applying kcl at Supermesh i2 = i3 - 3 Values for i1-3, respectively 0.2A, -1A and 2A
@addetnancy7401
@addetnancy7401 8 ай бұрын
@@SkanCityAcademy_SirJohn thanks I made a mistake and still got it correctly
@SkanCityAcademy_SirJohn
@SkanCityAcademy_SirJohn 8 ай бұрын
Oh okay. Follow my step, and see if you understand.
@SkanCityAcademy_SirJohn
@SkanCityAcademy_SirJohn 8 ай бұрын
Where do you watch from?
@addetnancy7401
@addetnancy7401 8 ай бұрын
@@SkanCityAcademy_SirJohn your videos. Super mesh
@najatal-hassan8420
@najatal-hassan8420 2 жыл бұрын
Please why didn't you use the first way you solved the first question for the second question
@SkanCityAcademy_SirJohn
@SkanCityAcademy_SirJohn 2 жыл бұрын
No issue, just wants you to see the variety... It doesnt change anything
@najatal-hassan8420
@najatal-hassan8420 2 жыл бұрын
@@SkanCityAcademy_SirJohn okay sure thank you
@SkanCityAcademy_SirJohn
@SkanCityAcademy_SirJohn 2 жыл бұрын
@@najatal-hassan8420 you're welcome
@sphumelelemabaso306
@sphumelelemabaso306 Жыл бұрын
you metod is wrong why using kirckkoff's law instead of norton
@SkanCityAcademy_SirJohn
@SkanCityAcademy_SirJohn Жыл бұрын
When you are asked to solve using Nortons Theorem it doesn't mean you can't used fundamentals like ohms law and kirckoff in your solution.
@fakhir_26
@fakhir_26 Жыл бұрын
Sir in problem 2 , according to problem 1 if the current direction is downward 👇 we take it negative but in problem 2 both currents IN'and InN" is downward 👇 but you take it positive why sir ?
@SkanCityAcademy_SirJohn
@SkanCityAcademy_SirJohn Жыл бұрын
The issue is, in problem 1 we have current in both direction, so you can either choose one direction to be + and the other to be -, its not compulsory to choose a specific direction for positive or negative. But for problem 2, both are in the same direction, so you can either choose positive or negative for both of them.
@fakhir_26
@fakhir_26 Жыл бұрын
@@SkanCityAcademy_SirJohn And sir can our answer of current be in negative??
@SkanCityAcademy_SirJohn
@SkanCityAcademy_SirJohn Жыл бұрын
Yes, you can have a negative current. Negative basically means, the actual current moves in the opposite direction
@SkanCityAcademy_SirJohn
@SkanCityAcademy_SirJohn Жыл бұрын
Are you okay with the answer?
@fakhir_26
@fakhir_26 Жыл бұрын
@@SkanCityAcademy_SirJohn yes sir I'm okay with your answers thanks a lot 😌😀
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