The current for that 2ohms will be zero so it will be(2×0)

Current isn't entering the 2ohms below ... Current is only moving along the side of the circuit

Taking a look at the circuit diagram, the only loops that current flow through is the first and third loops. There is or there will be no current flow in the middle loop because is an open voltage source. Remember Open means there can be no successful flow of current in that loop. In that case, the 2 ohm resistor you’re talking about, will have no current flowing through it hence, you cannot write a KVL equation including it. Always remember V=IR I hope this helps you in your future analysis of circuit related problems.

Welcome🙏🏽

I'm glad my video helped you understand. All the best

Can you be specific with the particular question you're talking about? You can use the time stamp to help me know the particular question.

The total resistance without the 2 ohms, is gonna be Rth = (2//3)+(2//2)

@user-tv6rp4sh2b Taking a look at the circuit diagram, the only loops that current flow through is the first and third loops. There is or there will be no current flow in the middle loop because is an open voltage source. Remember Open means there can be no successful flow of current in that loop. In that case, the 2 ohm resistor you’re talking about, will have no current flowing through it hence, you cannot write a KVL equation including it. Always remember V=IR I hope this helps you in your future analysis of circuit related problems.

I'll make a tutorial video on how to calculate using Norton's Theorem ASAP and upload.

I believe there will be a short circuit across that branch which will prevent current to flow to the adjacent resistor...

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Taking a look at the circuit diagram, the only loops that current flow through is the first and third loops. There is or there will be no current flow in the middle loop because is an open voltage source. Remember Open means there can be no successful flow of current in that loop. In that case, the 2 ohm resistor you’re talking about, will have no current flowing through it hence, you cannot write a KVL equation including it. Always remember V=IR I hope this helps you in your future analysis of circuit related problems.

Looking at the loop which contains the 2 ohm you’re talking about, you’ll realize that that loop was open and that no current flows through that loop . So basically, you cannot write a KVL equation without a current flowing through the resistor. i.e., V = IR

I still don't get it, it doesn't make sense

Which equivalent resistors are you taking about? You can make it simple by adding a time stamp so I know what you're talking about. Thanks

Hi Bernard, I guess your question is why didn't I consider the current produced by the 12V but considered just the 10V's current. This is why........If the 10V produced a current for instance i, the 12V will also produce a current i' but this ( i together with the current i' will join or will add up to be just a single current) this is because the current from the 10V and the one from the 12V won't be able to go through the Vth loop since that side is an open circuit. so the the only thing it can do is to add up to form a single current say "I" which i used in the loop. So Bernard, I did consider the current produced both by the 12V and the 10V as well. I hope you get. If you don't you can whatsapp me and come to my office for more insight to that. Thank you.

@Ledwaba Welcome🙏🏽

Since there's no current flowing through that resistor, it's of no use in your equation. This is because V = IR, that's for Kirchoff's voltage law, you need a current and a resistor but once there's no current flowing through that resistor it's going to be like V = no current * resistor. In other words, it's V = 0 * resistor. Which is always going to be Zero at the end. I hope this helps you.

Sabastian! I really like your observation skills. It's true that I didn't add the 2 ohm resistor down there and this is because if you distribute current through the circuit you'll see that no current flows through that particular resistor. And we've learnt in KVL that sum of voltage sources should be equal to voltage drops. What's a Voltage drop?? It is any current multiplying a resistor. So sine no current was flowing through that resistor, I can't consider that 2 ohm resistor as part of my KVL equations when finding the Vth. I hope this helps you. If you're still not clear on this you can contact me so you meet me at my office for further explanations. Thank you!

​@@kinemarc ohhhhhhhhhhhh Guy you too good Then you should have said it when teaching na

Lamar, I'm willing to explain everything to you but it will be best if you contact me on whatsapp so I show you my office and you come for explanations. Thank you!!

If you try to assign current, the 2 ohm resistor does not receive any current or current doesn’t flow through it so you can’t include it in your equations. I hope this helps you. Have a nice day

Taking a look at the circuit diagram, the only loops that current flow through is the first and third loops. There is or there will be no current flow in the middle loop because is an open voltage source. Remember Open means there can be no successful flow of current in that loop. In that case, the 2 ohm resistor you’re talking about, will have no current flowing through it hence, you cannot write a KVL equation including it. Always remember V=IR I hope this helps you in your future analysis of circuit related problems.

Exactly what do you wanna ask?

Hi Victor! You can whatsapp me so that we meet for further discussion yeah

@@kinemarc can i also reach you on whatsap sir

@@roberthaizel484 Yeah

comment I was having

Norton's Theorem will be uploaded soon. Keep your notification on. Thank you!!!

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