Beautifully explained - better than my book! Thanks

An outstanding presentation. It has cleared up all the problems I had understanding the physics behind coaxial cables. Thank you Brian Rook

Why doesn't this have more views... I'm gonna share it with all my emag friends. Thank you, Ninja! When I graduate and have an engineer's salary I will be able to contribute and quantify my gratitude for your videos!

Without watching about 2 minutes of the video, i can already tell that there's good teaching in this video

Excellent video, thank you for creating this. Studying for my E&M final and this has been extremely helpful

Thanks Ninja... Just got it at the right time for my presentation the next morning

Hey dude I guess you made a mistake. It will be good for you if you check the b

Thanks for going into the details! You have a nice voice as well!

Amazing! I really understood the exercise. Thank you!

Perfect! I was always confused by these things. Thank you very much! Saved me!

You've just saved an anonymous student on the internet! This explanation is awesome!

It is the best video for a college student studying electromagnetism. It was very helpful. Thank you.

Thanks for the clear and smooth explanation

This was beautifully done. Thank you.

simple explanation...helped me a lot.. Thank you Sir

Thanks man! Was having trouble understanding this question!

How could you do this same problem butt starting from the magnetic energy density of a ideal solenoid and combining that with amperes law to find the density as a function of distance radial out from the axis and use this to find the inductance in the cable. thank you.

simple explanation! I love it!

I think you just saved me before my midterm tomorrow. 😂 Thanks so much!!!

Great explanation! I wish I had you teaching my physics class!

Thank you so much .you explained so easily

This was explained so well thank you so much!

Thanks a lot man, it was wonderful.

Hi ninja ninja leader. Cheers!!. I have a question, what is the difference between magnetic field and magnetic field intensity? Thank you.

This really helped me. Thanks!

This is the best video on the god damn internet

Thank you for this clear solution.

So well explained!

Thanks for great explanation.

Great explanation! Thank you. Can we also calculate the B-Field for high frequency currents taking the skin effect into consideration with this method?

13:23 does the direction of the current matter in terms of the sign for B? would dl and b be in the same direction?

Thank you so much! Not even Griffith’s could properly go over these types of problems

The world's best teacher thanks sir

Great Explanation !! TY

these are great please make more

is there any possibility of electric field being produced by this coaxial cable (atleast in a

Beautiful explanation! You're great! :)

Thank you so much! This was very helpful!

Great explanation!

You're awesome. This helped me a lot.

Tq very much man...save my day 🙌🙏

Really helpful

Congratulations from Brazil, your video help me a lot!!

Thx from Brazil!

thank you well explained

Thank you 🙏🏼

This is awesome!

thank for your lectures, I am a teacher, I would like to know exactly the divide you (everyone) used to draw lectures beautifully?

Fantastic work

GREAT HELP SIR !!! 💞INDIA

Very helpful video!

Thank you Physics Ninja!!!!

@21:05 Which current is taken positive and which one negative is also included in ampere's law - First arbitrarily consider the direction of path that you have choosen (generally taken same as magnetic field) The apply right hand thumb rule to the path choosen the direction of thumb is taken as positive that mean on applying RHT rule on path all the enclosed current in the direction of thumb are taken as positive and all other currents opposite to direction of thumb are taken as negative..

Great video, thank you!

Thanks a lot, this video helps me a lot anytime i need :)

Very clear explanation, thank you! On a side note though, in the final screen you accidentally put another I in the equation for b < r < c

THANK SO MUCH!

This was so helpful! Thank you!

Thanks for this great help. 😃

thanks a lot

Thanks a lot!

Great good teacher

man you are the best, I tried to find the answer to the same question

Thanks brother!

Thank you.

thanks so much

God Bless You

Could you please also calculate the current density for each interval?

Literally saved my life God bless your soul

Thank you so much

tnx a lot! very well !

You’re better than my professor, thank you

Thank you ♥️♥️

this isn't an empty cable right? like it's not a shell of a coaxial cylinder cable? and if that was the case shouldn't the magnetic field in the r

dude, thank you!

Would a

thank you

Nice one

for b < r < c situation, why is it (r^2 - b^2) but not (r - b)^2 , same as (c^2 - b^2)

Thank you :3

Well explained,but when u do the closed integration it should be integration over rho product with dfi according to cylindrical co-ordinate system(Here rho is a product with dfi because rho is the perimeter across the arc dfi).Above all its good. Another thing is that u may use H(Magnetic field intensity) instead of B (Magnetic flux density) because when we r considering free space only then they aren't equal that is B=meu(o).H.But in practical cases medium may vary according to products choice

Brasil love's you!! grateful!!

Thanks physics ninja, you might help me not fail uni xxx

as the inner cylinder is a conductor so all charges would be at the surface of the cylinder and hence the current should flow through the surface (as current is the flow of charges) so I would be zero for r

Nice! Thanks alot :)

Thank you :))

Audio mixing could be improved, but the content is very helpful.

Just wondering, does this implication of the magnetic field being 0 outside the outer loop bypass the limitations of really small computers? I remember hearing somewhere that there's a limitation of how small circuit elements can get because their magnetic field would induce currents in nearby circuit elements.

You are special❤❤❤❤❤

ur a legend

Thank u

Thanks so much, this clarified my Delima about the magnetic field everywhere in space.

Completely random but... is that dotted line for inside the second conductor really purple? I'm genuinely afraid I'm colorblind now :D

better explanation than books..

Thanks man

wow. you nailed it,, well explained.. Wonder if you could make videos about magnetic moments for rotating charge disk, spheres, etc.

Melhor explicação que encontrei

Hello sir, thank you for your thorough explanation. I just need to understand something please. Let us for now consider only the small conductor (gold). Seeing that it is a conductor, will all the charge/current not be located on it's surface only? Ergo, a proper Amperian loop would be such that it goes around the entire conductor and not inside the conductor. This would then change the outcome of this part and the rest of the problem. I need to understand this because there are so many people on the internet doing their own thing and in the end the information conflicts in the small but very necessary details. Thank you again for this explanation.

what if the equation was asking for r

thanks a ton!! i couldnt understand the solution given in my text, they didnt clearly write the exolanation.