Vibration || Conceptual Prob || Newtons approach || Energy Approach || Natural Frequency || GATE

  Рет қаралды 20,074

ASHISH PUROHIT

ASHISH PUROHIT

3 жыл бұрын

Join My live Free Session on {VIBRATION OF PULLEY MASS SYSTEM (in Hinglish) GATE 2022 }
7:30 PM 29 Sep 2021 (Tuesday) at unacademy.com/class/natural-f...
Step by Step solution of a complex problem using both newtons and energy approach. Problem becomes complex when we assume mass of the rod. Important conceptual problem of Mechanical Vibration.
Another IMP problem of VIbration for GATE : • Vibration of Two Rolle...

Пікірлер: 24
@JosueA_455
@JosueA_455 9 ай бұрын
This degree of explanation is simply genius.
@Asalashjari
@Asalashjari 3 жыл бұрын
thank you! so helpful
@mohammadsohail3798
@mohammadsohail3798 3 жыл бұрын
Awesome sir❤️❤️👍
@bailey9435
@bailey9435 2 жыл бұрын
when simplifying the equation of motion in the first method, how did the L's disappear?
@-Shadow__Rider-
@-Shadow__Rider- Ай бұрын
Thanks 🙏🏼
@onabill155
@onabill155 2 жыл бұрын
Thanks 😊
@diplomats1778
@diplomats1778 3 жыл бұрын
Thank you
@anonuser6111
@anonuser6111 Жыл бұрын
Why was angle theta not used in the equation
@kaursingh637
@kaursingh637 2 жыл бұрын
sir =excellent =pls suggest book =thank u =amarjit
@adilsrana
@adilsrana Жыл бұрын
Sir, I am working on a project is it possible that you can help me to derive the natural frequency of my system. it is very similar to this problem but just with one spring.
@avyakth7995
@avyakth7995 2 жыл бұрын
sir, at 10:08 in energy approach why we considered translation KE for point mass why dont you take it as rotational KE just like for mass of rod you have taken
@ashishpurohit9138
@ashishpurohit9138 2 жыл бұрын
I would suggest you to also see this prob. see only up to energy method for simple pendulum 7 .00 min. Plz understand, in case of applying energy method to a mass moving in a curved line. either you will apply KE as 1/2mv^2 or 1/2I(omega)^2 where I is MOI about the point of rotation. so I = mr^2. So when you put I into second expression, it will become same as first expression as (omega*r)^2=v^2. I hope it is clear, if not let me know.
@avyakth7995
@avyakth7995 2 жыл бұрын
@@ashishpurohit9138 yes sir got it ,now i got both as same thing ... Thank you so much for your reply ❤️
@thomaschunga2375
@thomaschunga2375 2 ай бұрын
Why are all the forces assumed in the same direction..and when i assume one force in the spring to go a different direction the answer is different
@ashishpurohit9138
@ashishpurohit9138 2 ай бұрын
I guess you are talking about spring forces. When the body moves in a particular direction, all spring forces act opposite of it.
@thomaschunga2375
@thomaschunga2375 2 ай бұрын
Thank you I understand now.. all forces not in direction of motion of mass are negative
@thomaschunga2375
@thomaschunga2375 2 ай бұрын
Thank you I understand now.. all forces not in direction of motion of mass are negative
@joelledaany146
@joelledaany146 Жыл бұрын
Is that 8 or 16
@nipunbansal8977
@nipunbansal8977 3 жыл бұрын
why mg is not considered for the inertial mass during newton's method?
@axcessventures2572
@axcessventures2572 Жыл бұрын
It cancels itself out in the beginning.
@quant459
@quant459 3 жыл бұрын
Sir are u from odisha??
@ashishpurohit9138
@ashishpurohit9138 3 жыл бұрын
No Dear Subrat, I belongs to Central India. Bu currently in punjab.
@quant459
@quant459 3 жыл бұрын
@@ashishpurohit9138 sir I want to talk with u for 5 minutes can u give your contact no plz.....I want to talk with u regarding mtech on iiT
@ashishpurohit9138
@ashishpurohit9138 3 жыл бұрын
ashishpurohit1(a)gmail
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