@kindreon 2 жыл бұрын
This proof was so clean my desk got organized just by watching!
@gamersway960 2 жыл бұрын
I'm currently taking linear algebra 2 and one of the most hard proves I remember is the Cauchy-Schwarz inequality Thanks for teaching me an easier way to prove it❤️
@DrBarker 2 жыл бұрын
There are lots of different proofs out there! I found this proof in a paper with loads of other really neat ways of proving the Cauchy-Schwarz inequality.
@gamersway960 2 жыл бұрын
@@DrBarker Do you have the name or a link to the paper? That would be very appreciated!
@DrBarker 2 жыл бұрын
@@gamersway960 Yes, it's this paper: Wu, Hui-Hua, and Wu, Shanhe. Various proofs of the Cauchy-Schwarz inequality. Octogon mathematical magazine 17.1 (2009): 221-229. Enjoy!
@vijaysubramanian2037 2 жыл бұрын
That was a fun proof! Very well explained 👌
@perappelgren948 2 жыл бұрын
Very nice! Down to earth, to the point, and all this without using any kind of mathematical excesses. Very nice indeed! 👍
@numbers93 2 жыл бұрын
ahh when homework rolls in and you search “prove Cauchy-Schwarz by Jensen’s Inequality”
@kobethebeefinmathworld953 2 жыл бұрын
What a beautiful proof! Brilliant!
@DrBarker 2 жыл бұрын
Thank you!
@joaago1 6 ай бұрын
How would you prove Hölder's inequality using convex arguments? (Jensen's).
@sethdurais2477 2 жыл бұрын
Amazing proof!!!
@IlanAmity 6 ай бұрын
I know how to solve a/(b+c)+b/(a+c)+c/(a+b)≥(a+b+c)/(a+b+c-∛abc) The idea is to show that: LH≥3/2≥RH but I do not know how to solve a/(a+b)+b/(b+c)+c/(c+a)≥(a+b+c)/(a+b+c-∛abc) LH is not necessary ≥3/2 it can be smaller, but it seems it is always ≥RH Any Ideas on how to solve this?
@user-wu8yq1rb9t 2 жыл бұрын
Schwartz inequality even is practical for Quantum Mechanic. And ... Two videos per days would be great (I hope). Thank you so much dear Dr. Barker (The Beautiful Mind) 💓
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