Center of Mass Physics Problems - Basic Introduction

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6 жыл бұрын

This physics video tutorial provides a basic introduction into center of mass. It explains how to find the center of mass in typical physics problems. This video contains a few examples of finding the center of mass of a system of masses along the x-direction and along the y-direction. In addition, it explains how to find where to place a massive load on a truck to move the truck's center of mass to the middle of the truck.
Impulse and Momentum:
• Introduction to Impuls...
Conservation of Momentum:
• Conservation of Moment...
Rocket Propulsion:
• Rocket Propulsion Phys...
Inelastic Collisions:
• Inelastic Collision Ph...
Impulse Momentum Theorem:
• Impulse Momentum Theor...
____________________________
Force-Time Graphs:
• Force Time Graphs & Im...
Ballistic Pendulum Problem:
• Ballistic Pendulum Phy...
Elastic Collisions:
• Elastic Collisions In ...
2D Collision Problems:
• Conservation of Moment...
Impulse & Momentum Test Review:
• Impulse and Momentum C...
_____________________________
Center of Mass - Calculus:
• Center of Mass & Centr...
Intro to Rotational Motion:
• Rotational Motion Phys...
Full-Length Videos and Worksheets:
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Physics PDF Worksheets:
www.video-tutor.net/physics-b...

Пікірлер: 156

@TheOrganicChemistryTutor Жыл бұрын

Physics PDF Worksheets: www.video-tutor.net/physics-basic-introduction.html Full-Length Videos & Exams: www.patreon.com/MathScienceTutor/collections Impulse & Momentum Practice Test - 47 Problems: bit.ly/3Qj9FjO Next Video: kzfaq.info/get/bejne/jbdpdKtjuJ6mZo0.html

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@tombrady339 3 жыл бұрын

in the last problem, it depends on what reference point we are going to pick. We can use the one that our professor, The Organic Chemistry Tutor, used wherein the back of the truck is in the x=10m or we can use the other one wherein the back of the truck is in x=0m and the front of the truck is in the x=10m. In this case, the computation will be 5m= (4,000kg(6m) + 1400kg(x2))/5400kg and if we solve it algebraically, the result will be 2.14m. Why 6m? It is because based on the problem, the truck "has its center of mass 4m behind the front of the truck." If we use the reference point where the front of the truck is in x=10m, then 10m-4m is equal to 6m. Let me know if you also use this one.

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@lyricsonly4894 3 жыл бұрын

is this like a part 2 video bc u u started with the questions but there was no introduction nor formula explaining

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@yan_eng8661 3 жыл бұрын

wouldn't the answer to the last question be 2.14m if the truck was facing right instead of left?

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@imtehcumseh 2 жыл бұрын

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@abdulrhmanmohammed9505 5 жыл бұрын

In the last problem why did he used the x1 for the truck 4 insted of zero, since the front of the car is located at position zero?

@na-chan163 5 жыл бұрын

he just arbitrarily assigned the 0 to be the front of the truck, so the cm of truck is at 4m relative to the origin zero. What the answer of 7.86m means is that the center of mass of the object weighing 1400kg must be at 7.86 m relative to the origin. This cm of the individual objects give rise to the needed 5m center of mass of the system.

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@vinaybhat4330 Жыл бұрын

in the last question i dont understand why you multiply the truck weight with its centre of mass whereas in the other problems you multiplied the mass usually with the distance.Kindly guide me Thanking you in advance

@Ihatelife Жыл бұрын

Same I don't get it either

@jovilynmarabe6809 4 жыл бұрын

Excuse me, why that the center of mass on the 4th problem is 5? Isn't it 4?

@saorisaori3467 5 жыл бұрын

Is this a Integral formula? Can anyone answer my question please??? Thank you in advanced :)

@JonathanL_ 3 жыл бұрын

Maybe

@harshavardhanreddyy1979 4 жыл бұрын

I have a doubt sir, in the last problem who have taken x1 value 4 which is center of gravity , but we should take 10 right , but why did you take 4 as x1🙂 plz give me answer sir

@tlili3990 2 жыл бұрын

he took 4 because the x values should be the centres of individual masses and the centre of mass is at 4 meters for the truck. the 10m lenght doesnt need to be in the equation, it just shows that the centre of mass will be somewhere between 0 and 10.

@Ihatelife Жыл бұрын

@@tlili3990 But doesn't x need to be distance? Why would he take it as centre of mass of truck? I m confused af💀

@dammybankz6398 2 жыл бұрын

Sorry is the illustration of diagram compulsory ??

@kwabenadarkey8964 4 ай бұрын

Hey but does anyone know where I can get detailed notes on the topic

@faisalmohamed4595 7 ай бұрын

How did we get the 5 at the last question and why is it xcm=5

@kindcolt2747 Жыл бұрын

How come none of these adress the fact that an object has more than one “position. If it begins at 0 and is .5 meters long, is the position the avg length? (0+.5)/2=.25

@leviticusdionysushunt7080 Жыл бұрын

yeah so most of these examples are for particles but there are some problems where the masses have more than one position. once i had a problem where 3 boxes had different lengths/masses (but same height) and i had to find their Xcms from an origin point set at the bottom left corner of the first box. Basically ycm was half the total height cause the 3 boxes all had same height, but for length it was different cause the three boxes had different lengths. box A had length 0.25 m, mass 0.8 kg box B had length 0.35 m, mass 1 kg box C had length 0.2 m, mass 0.6 kg i'm not sure if mass is relevant to your question, but you would use it to find the center of mass of the whole system. however, if we're just looking for center of mass for each box, this is how: I solved it with: X(a)cm = 0.25 m/2 = 0.125m X(b)cm = *0.25* + (0.35 m/2) = 0.425 m X(c)cm = *0.25m + 0.35 m* + (0.2m/2) = 0.7 m if we wanted to find center of mass for the whole 3-box system: xcm = (0.8kg * 0.125m) + (1 kg * 0.425m) + (0.6kg * 0.7 m) DIVIDED BY (0.8 kg + 1 kg + 0.6 kg) then we get the answer, the center of mass of the system is 0.394m. hopefully this answers your question!

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@muhibbul7255 Жыл бұрын

did we assume that the weight of only the front of the truck to be 4000 and not the whole truck?......

@thsbig741 4 жыл бұрын

Why you choose 5m is a center of mass in article 4.

@Brandon-lx3mf 4 жыл бұрын

because the question asks for it to be moved to the middle, and the middle of a 10m truck is 5m

@calhoun_0 2 жыл бұрын

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@tatiana1310 3 жыл бұрын

I dont know if someone will answer me but I could not understand why at 11:31 he use the center mass?

@wardahdarwich3718 3 жыл бұрын

he used the center of mass of the truck as x because if u want to calculate x the mass will be canceled and x is equal to the center of mass i don't know if you got it

@Ihatelife Жыл бұрын

I don't get it either

@joshuaantony9716 3 жыл бұрын

error in calculation in last question 27000/16000|=11000

@berserkexe Жыл бұрын

@musah7300 Жыл бұрын

Reading this 20 minutes to exam 😹

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@nkosingiphilenene2237 Жыл бұрын

How did you got 5m as center of mass?

@maryamibrahim8283 Жыл бұрын

Because in the question they said the center of mass will be right in the middle of the truck and the truck is 10m long so the middle of the truck is 5

@faisalmohamed4595 7 ай бұрын

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@krissandrew4524 3 жыл бұрын

Wat..I..dnt.. undstnd..is How..d..5..came..2..b Did..we.. assume..it.? Also..my.. weakness..is.. trying..2 Interpret..a... question..it.. really Killing..me

@herondalecarstairs1480 3 жыл бұрын

dude i cant understand your doubt..in case its the last qn,then its bcz its said that Centre of mass is in themiddle of the truck meaning 10/2=5..its middle