Centripetal Acceleration & Force - Circular Motion, Banked Curves, Static Friction, Physics Problems

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Centripetal Acceleration & Force - Circular Motion, Banked Curves, Static Friction, Physics Problems

Рет қаралды 1,670,077

Күн бұрын

This physics video tutorial explains the concept of centripetal force and acceleration in uniform circular motion. This video also covers the law of universal gravitation, weightlessness, banked curves with friction, kepler's third law of planetary motion and other stuff. This video contains plenty of examples and practice problems.
Centripetal Acceleration:
• Introduction to Centri...
What Is a Centripetal Force?
• Physics - What Is a Ce...
Centripetal Force Physics Problems:
• Centripetal Force Phys...
Tetherball Physics Problems:
• Tetherball Physics Pro...
Tension Force - Vertical Circle:
• Uniform Circular Motio...
_______________________________
Static Friction & Centripetal Force:
• Static Friction, Centr...
Normal Force on a Hill:
• Normal Force on a Hill...
Banked Turn Physics Problems:
• Banked turn Physics Pr...
Non-Uniform Circular Motion:
• Non-Uniform Circular M...
Gravitational Force:
• Gravity, Universal Gra...
______________________________
Universal Law of Gravitation:
• Gravity and the Univer...
Gravitational Acceleration:
• Gravitational Accelera...
Gravitational Field Strength:
• Gravitational Field St...
Satellite Speed:
• Speed of a Satellite i...
Kepler's Third Law of Motion:
• Kepler's Third Law of ...
____________________________________
Kinetic Energy and Potential Energy:
• Kinetic Energy and Pot...
Work, Energy, and Power:
• Work, Energy, and Powe...
Final Exams and Video Playlists:
www.video-tuto...
Full-Length Videos and Worksheets:
/ collections
Physics PDF Worksheets:
www.video-tuto...

Пікірлер: 578

@TheOrganicChemistryTutor Жыл бұрын

Physics PDF Worksheets: www.video-tutor.net/physics-basic-introduction.html Full-Length Videos & Exams: www.patreon.com/MathScienceTutor/collections

@AliKisubi-sv4ul Ай бұрын

thanks so much

@iconic410 4 жыл бұрын

Timestamps for this lesson: Note: He sometimes teaches concepts(Kepler's third law, tangential acceleration...)during the practice problems so make sure to look out for those 0:00 - Intro 0:15 - Centripetal Force 14:31 - Centripetal Acceleration 15:22 - Period and Frequency 16:32 - Tangential Velocity 32:40 - Vertical Circle Problem(Varying centripetal acceleration) 1:10:59 - Gravity and Newton's Law of Gravitation Problems: 1. 18:50 2. 23:42 3. 26:27 4. 35:26 5. 38:05 6. 40:17 7. 46:31 8. 50:15 9. 58:12 10. 1:01:41 11. 1:07:31 12. 1:15:51 13. 1:22:29 14. 1:24:35 15. 1:31:22 16. 1:36:53 17. 1:43:24 18. 1:47:45 19. 1:50:34

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@chovvyy 5 жыл бұрын

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@rei___l 4 жыл бұрын

click open transcript in the three dots next to the save button, you'll see timestampss

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@realphy6656 3 жыл бұрын

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I'm just curious why the problem at 45:00 does not use formula FT = sqrt(FTx^2 + FTy^2), taking into account the effects of gravity

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@picturebazzare 3 жыл бұрын

The circular motion and, the effect of magnitude of radius on the time period of an object was investigated in this practical. According to this the relationship between the radius and the period as follows, T 2 = r According to the collected data it was able to prove that above statement.

@therandomperson9627 Ай бұрын

1:01:30 the answer for net acceleration is done right but due to intermediate rounding the answer became off by 0.4 In this scenario, 0.4 is a slightly large difference since the answer itself is less than 10. Rather if a direct input of the v^2/r in the Pythagorean equation then it would yield about 5.26. You taught the right way but it was just off due to rounding. But still you helped me learn how to approach these problems

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@evanjones9602 3 жыл бұрын

Is anyone else watching this the day before their big physics test over centripetal force, acceleration, and gravitation?

@waelal-amri2161 3 жыл бұрын

yup

@picturebazzare 3 жыл бұрын

The force causing the vertical acceleration comes from the centrifugal force. This causes the swings to move at a faster speed which then ultimately leads to the swings moving outwards and, in the direction, going up.

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@greatpharoh0303 4 жыл бұрын

Slight correction for the teatherball problem, for T x all you use is mv^2/r and T y is mg so you get 29.6 and 2.45. By pathagorean T = 29.7N right?

@arhamsiddiqui7083 4 жыл бұрын

One thing that really helped me understand the free-body diagrams is that remember that fNET= Fac all the time. So in the roller coster example, at the bottom, Fnet= Fac= FN-mg and then at the top it is Fnet = Fac = mg - FN

@ro1882 4 жыл бұрын

arham siddiqui what do you mean by fac? I guess i have studied too much and am starting to mix things up

@arhamsiddiqui7083 4 жыл бұрын

@@ro1882 i meant force of centripetal acceleration

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@ArcherGabs 5 жыл бұрын

Hey I think you made a mistake at around 35:00, the tension at the top is equal to the sum of the weight force and the centripetal force, and the difference of them at the bottom.

@DavidGarcia-ve2ll 4 жыл бұрын

Archer i’m thinking the same thing too but thinking about it it kind of makes sense because at the top the tension would be less than the tension at the bottom since gravity is helping the fc at the top and relieving tension, and at the bottom fc is trying to go up wards and gravity is pulling the opposite direction, increasing the tension. so the tensions there should be T at point A>C which proves his equation but i also get what you mean so i’m very confused lmao

@ralphanthonymallillin2712 3 жыл бұрын

Nope..actually it'a correct...he said that centripetal forces are positive when the direction is seekin to the center of the circle..He wrote it as Fc=T+Mg at the top since both Mg and T are directed through the center..and Fc=T-Mg at the bottom since T is directed through the center and Mg is away from the center :)

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@roberto3196 5 жыл бұрын

Great video, but one question. At about 46:28 did you just not count the tension force for the Y component when calculating the overall tension force because the Y component tension is almost negligible? I counted the Y component and got 29.7 N instead of 29.6 N.

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I can’t thank you enough I understand centripetal force problems so much better now thank you!! 😁🥰

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@ntingletstacy3977 11 ай бұрын

I think there's an error; the value of the speed is 251.3m/s because the period T is equal to 0.25 sec not 0.2

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As always, great video. Perfect for my physics class.

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@user-clouddy 2 жыл бұрын

it has been 5 years that u made this video. I am not sure whether u r gonna answer my question or not. But still, (56:39) u solved Normal Force equals to mg/cos. What makes it different from the other questions that the normal force was usually mg x cos? why makes the normal force to be mg/cos? Also, Thank you for making these videos. I like how u explain the general concept first and then u solved questions that are related to the concepts that u just taught.

@kabouch 3 жыл бұрын

8:49 in this example, I would think that the normal force is balanced by a force of the magnitude of mgcosΘ and in an opposite direction; while, the acceleration along the direction of the velocity is due to a net force equal to the (mgsinΘ-friction) force. At the initial point when the moving object is no longer in touch with the ground i.e. when the gravitational force is not balanced by the normal force, the object accelerates downwards by gravity.

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@tatiana1310 3 жыл бұрын

35:05 Somebody could help me? Why they are both negative if they are pointing to the center (positive)?

@ralphanthonymallillin2712 3 жыл бұрын

@andrewpq5149 Жыл бұрын

35:21 I got a question. Shouldn't the forced acting on the ball at point A be T-Fg because only T is pointing towards the circle. Point C should be T+Fg because both T and Fg are providing the centripetal for, so they should both be positive

@Josh-pm4qx 5 жыл бұрын

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@ralphanthonymallillin2712 3 жыл бұрын

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@emigdiovillalobos5417 6 жыл бұрын

force is linear with R, because V itself is a function of R. and when you square V you get an R^2 and R^2 divided by R is R. so R is linear with force.