CIE IGCSE Additional Maths: Permutations & Combinations
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Күн бұрынTOPIC: Permutations & Combinations (Rules & Examples)
Welcome to the Rules & Examples (R&E) Simultaneous Equation video for the CIE IGCSE Additional Mathematics (or Additional Maths, Add Maths) series by Yi MakesItEasy. My name is Yi, and welcome to my channel!
In this video, I discussed the basics for permutations & combinations, and examples. I talked about the basic counting principles, as well as formulae for permutation (P) and combination (C). This concept is really confusing (it was really confusing when AI first learnt it) - so watch till the end for my reasoning for the questions!
If you have any questions related to Permutations & Combinations (or any other topics), feel free to comment down below or drop me an email (email in KZfaq bio!)! :)
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Check out the whole CIE IGCSE 0606 Additional Mathematics playlist here:
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@yimakesiteasy 2 жыл бұрын
CIE IGCSE Add Maths time stamps: Permutations & Combinations - Basics: 00:18 Permutations & Combinations - Examples: 08:20
@Cubewuse161 7 ай бұрын
Hey! Thanks for all your videos, they really helped me learn add math, and they're great! Keep it up man :)
@yimakesiteasy 7 ай бұрын
Glad you find them useful! Let me know if you need any help!!
@scalpers2024 Ай бұрын
Thanks, Sir.
@yimakesiteasy Ай бұрын
Hope it helps! :)
@krissywissy9927 Жыл бұрын
Hello! For 8:47 I was wondering when doing my add maths paper do I have to write out the permutation like 8P5 = 8x7x6x5…/3x2x1 or can I immediately write 8P5 = 6720 if I use my calculator
@yimakesiteasy Жыл бұрын
Hello there! Generally if the question is one mark, you can just put 8P5, but if the question is worth two or three marks, it's better to write out 8P5 = (8*7*6*5*...)/(3*2*1) = 6720 so the examiner can see your working. But what I usually do is i just write all my working out to: 1) Avoid losing any working marks, 2) So it's easier to check my work and to find any errors
@aryantheslumpgod2174 Жыл бұрын
the last question part c why cant we do 4C1 to find the 1 junior multiply it by 6C4???
@yimakesiteasy Жыл бұрын
Hi! Because the question asks about “at least” 1 junior, so using your method you have to consider the number of combinations for 1 junior + 2 juniors + 3 juniors + 4 juniors 😀
@m_r_ii 5 ай бұрын
Hey! what keywords should you look out to easily determine a combination or a permutation question?
@yimakesiteasy 4 ай бұрын
Hello! The keywords include "only", "at least", "equal to", "not", "(no) restriction"
@m_r_ii 4 ай бұрын
@@yimakesiteasy Thank You very much! I really like your channel, and your website is very helpful! I recently did an exam with the aid of your website! I'll report back with the results!
@yimakesiteasy 4 ай бұрын
Your support means a lot to me! Well done with your exam, I’m sure you aced it :)
@bahahytham7579 6 ай бұрын
Hello there in question 19:00 b) they didnt say 3 seniors only so it can includw 4 5 or even 6 seniors am I wrong?
@yimakesiteasy 6 ай бұрын
Hello, it is 3 seniors only. I should’ve specified “only”. Thanks for pointing it out!
@bahahytham7579 6 ай бұрын
@@yimakesiteasy yeah thx man but if the question was written as it in the video which way should u solve it
@yimakesiteasy 6 ай бұрын
Generally if the answer may involve 4 or 5 or 6 or more seniors, the question will be “more than 2 seniors” or “greater than or equal to 3 seniors”
@ilililaaah 2 жыл бұрын
hi, why did u cancel put the 3! factorial in 8!/3!
@yimakesiteasy 2 жыл бұрын
Hello, I assume you’re talking about the steps I did in 8:45! If you see the formula for nPr in 5:43, you can see the denominator/bottom of fraction is the top number in P minus the bottom number in P (in this case, it’s 8P5, so 8-5 = 3, so denominator is 3!). When I have the numerator as 8!, and denominator as 3!, you can visualise it: 8! = 8*7*6*5*4*3*2*1 3! = 3*2*1 You can notice we can cancel the 3*2*1 from top and bottom (similar to how we can cancel 2 in (2*3)/2 to get just 3). 3*2*1 is 3!, so I don’t need to write out all of the values, and I know I can just take away values from the number in denominator to 1. I understand it’s a bit confusing; do you need another explanation?
@ilililaaah 2 жыл бұрын
@@yimakesiteasy ohh, thank you for the explanation! it’s more clear now ^•^
@yimakesiteasy 2 жыл бұрын
Awesome! Feel free to ask any more questions if you have any :)
@devanshpatil1065 Жыл бұрын
Hey, in the first question your answer doesn't account for the possibility that OR are arranged with R being before O
@yimakesiteasy Жыл бұрын
Hello, it does. I grouped O & R together, and before the 6!, I multiplied it by 2 so it accounts for the arrangement where O is before R and R is before O😀. Does that make sense?
@devanshpatil1065 Жыл бұрын
@@yimakesiteasy thank you (for the quick response and the clear explanation and the great channel)
@yimakesiteasy Жыл бұрын
@@devanshpatil1065 thank you for your support 🙏
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