CMOS Inverter Basics-I

Рет қаралды 97,469

IIT Roorkee July 2018

Күн бұрын

In this video we have covered the basic of CMOS Inverter. The switch model of the Inverter, its static behavior in terms of VTC is discussed in detail.

Пікірлер: 27

@hoytvolker3 3 жыл бұрын

Very good prof

@user-dd9fz5wu4k 9 ай бұрын

sir why pMos to saturation region when given Ov as input according to Vds < vgs - vth condition is false , it should drive in linear region for high output 13:29 please some one tell me if I wrong

@JVLESX 4 жыл бұрын

you speak very good english

@roshansharma5251 2 жыл бұрын

As in saturation MOS behaves as a current source ideally with resistance infinity...then why has sir considered the source to drain resistance as a finite resistance. Anyone please clarify.

@priyanshuchoudhary8319 2 жыл бұрын

Watch previous lecture

@pho3nix732 2 жыл бұрын

Thats "ideally". In practical obviously there is nothing like infinite resistance. Watch previous videos, your doubt will be solved.

@heyitsmea8883 9 ай бұрын

If change the source of pmos to gnd and nmos to vdd what will happen? I just want know answer

@crazyzone4064 2 ай бұрын

It will not be inverter it will act as voltage follower

@akhilakki8555 4 жыл бұрын

how i can download ppt which explained by sir

@dhairyaclasses6156 3 жыл бұрын

Mail me for ppt....premanand.patel@gmail.com, you will get it.

@zaidakhtar3093 3 жыл бұрын

@@dhairyaclasses6156 i will mail you, please send it

@dhairyaclasses6156 3 жыл бұрын

@@zaidakhtar3093 mail me then you will get it soon.

@Sankeerth_ 3 жыл бұрын

i.e in transcripts

@suchandramodak1137 4 жыл бұрын

At 9.15 you said the upper MOSFET is pMos but I think it's actually a Nmos because the arrow from source to Gate is inside.. am I wrong or right ? Please reply as soon as possible thank you.

@sriranganayakulu8513 4 жыл бұрын

upper one is pmos only, refer the first lecture of this series

@basicelectronics9182 3 жыл бұрын

You are wrong because for NMOS the arrow will be from gate to source

@94D33M 5 жыл бұрын

Why at 29:44 you said current flowing through them will be equal to each other? Isn't one always off?

@Pkmkb_786 4 жыл бұрын

At switching threshold voltage( Vm= Vdd/2)both NMOS and PMOS will be ON. At that point Current will flow from Vdd to ground and as they are in series current will be same in both of them.

@Sankeerth_ 3 жыл бұрын

Pmos becomes on when Vsg > |Vtp|, so when the input is 0 Pmos becomes on.

@ayushbachan6113 2 жыл бұрын

yeah as vgs=0-vdd=-vdd < Vtp

@pavanasathwik5549 5 ай бұрын

doubt at graphing part

@shilpa1949 3 жыл бұрын

Why there is the need of shifting from second quadrant to first quadrant

@nafizalam8097 3 жыл бұрын

Because if no shift on 2nd quad then that means I_ds_p = - I_ds_n ... the current for nMos flows in opposite direction to that of pMos

@raghavdubey9138 Жыл бұрын

Because , the input is dynamic and it`s fluctuates between 0(T/2) and 1(T/2) so for that half of the time Pmos will switch on and Nmos will cutt off and for another half time vice versa, So the Pmos will work in 3 rd quadrant for half of the time and the other half of the time Nmos will work as low resistance path to discharge the capacitor and current will be decreases at that moment in the 1st quadrant .