Chemistry PDF Worksheets: www.video-tutor.net/chemistry-basic-introduction.html Full-Length Videos & Exams: www.patreon.com/MathScienceTutor/collections Direct Link to The Full Video: bit.ly/3k4vtUk
@user-pi1mq5td3n2 жыл бұрын
At first I want to thank you for your clear and understandable explanation, but it is a bit sad for me, I even cried because I cannot watch the full video of this difficult topic. You are one of the few who explain these complex topics in such a smooth way. It is sad that I can only watch something simple. Therefore, at the present time, I cannot subscribe, perhaps later, but now it is difficult, but I hope that you will open this video, even for a month or even a week for free, and I promise to subscribe, but please open it now, I will fail 😭💔
@ryanlyle92013 жыл бұрын
This channel lowers the activation energy of studying.
@djmadman36513 жыл бұрын
hahaha
@leen81752 жыл бұрын
good one
@corn._.flakes2 жыл бұрын
lmaooo it really does
@yayaboru90132 жыл бұрын
H🤣h yes it is catalyst
@epicmoments19642 жыл бұрын
You can say that again😂😂😂😭
@dagmawigirma97483 жыл бұрын
Julio Gonzales you one of my favourite human being ....26 days left for my exam i been watchin ur videos for 3 years
@haimanotmulugeta30413 жыл бұрын
I am also from ethiopia bro and i have almost seen them all .it really helped me
@dagmawigirma97483 жыл бұрын
@@haimanotmulugeta3041 ow nice to meet you
@haykojan65903 жыл бұрын
Bro how long is that class loll on the real though this channel is incredible
@efratawolde71422 жыл бұрын
Yagere lij😅
@endoumamoru38352 жыл бұрын
Bro I have exam in 12 hours
@7schlaefer9 ай бұрын
You are the reason I became an A-student in chemistry. I wish my books were as coherent as your videos! You explain everything super logical and with the right examples. Explained by you, any material just makes sense. Thank you so much!
@Stasia.Chronos-stasis Жыл бұрын
This channel is one of the most relevant KZfaq channels out there. I can tell the sub count has been always exponential here
@CaseyVaughn-kq7hy2 ай бұрын
Your chill personality comes through on all your videos and turns the volume down on the confusion and makes it so much easier and more enjoyable to learn the material. By far the best teacher I've ever had. I'll be a subscriber for life.Thank You !!!!!!
@nonhlanhlansele67993 жыл бұрын
All I would like to say is that you my best lecturer,and I'm gonna make it to chemical engineering because of you Sir. I am so great full for this Channel.
@littlechemist3 жыл бұрын
Every video of this Chanel inspire me to fullfill my dream as I want to be a chemist
@smuel_email68443 жыл бұрын
Me too man!
@kesavdarshan3 жыл бұрын
All the best pal...
@littlechemist3 жыл бұрын
@@kesavdarshan thank you
@RyanMSilverman2 жыл бұрын
The only confusing part is that "A" is used as the concentration of the first reactant, and also as the frequency factor.
@saisudhapurushothaman8909 Жыл бұрын
A is concentration in the rate of the reaction, while A in the Arrhenius equation is frequency factor
@sharon_u_r Жыл бұрын
Good teaching sir 😊
@lenops-uu7bw11 ай бұрын
There will be a box around A for concentration so it's fine.
@nkheng7542 жыл бұрын
THANK YOU so much this is so helpful, don't know what I'd do without you
@7schlaefer9 ай бұрын
Right? I would be long lost, too!
@fancytracy7 ай бұрын
This is an amazing perspective, it helped me a lot understanding this physical phenomena, thank you for your work
@roberthan1173 ай бұрын
You are not just Organic Chemistry tutor, you are my life tutor ;'''')
@nimmi6885 Жыл бұрын
You will never know about the respect that I have for you sir!
@wildernessgamer-zn9wo6 ай бұрын
If you are watching this video give this man a thumbs up and drop a comment since its the only way we can truly support him. We thank you julio
@gloryimags4511 Жыл бұрын
Who ever you are behind this screen, thank you!! You're amazing!
@SandTheMan7612 жыл бұрын
Thank you for helping me pass my chemistry final 🙇
@fadeyibimayowa10213 жыл бұрын
You mean a lot to me master ♥️
@namatalubasi79342 жыл бұрын
Me too
@solution11113 жыл бұрын
Thanks I am in this lesson👑👑 greater than teacher ☺️☺️☺️☺️☺️☺️☺️☺️☺️☺️
@englishandscience22023 жыл бұрын
You really do good jobs. I appreciate it from 🇯🇵
@user-jd2tg3qs8o5 ай бұрын
Bro u understand that what he was saying
@DR_INSULIN2 жыл бұрын
JG is my greatest role model
@rayyanaburukun34423 жыл бұрын
I would like to make a request for a video about the magnus effect, I know nobody would explain it any better than you do since I have been watching your videos for a year and a half now and I'm just 13 years old. Anyways, keep up the fabulous work
@army73472 жыл бұрын
For the last problem, I put the numbers into the equation into my calculator exactly as you wrote it several times and I keep getting 0.005212 for k2, which is not what you have. Is there some kind of calculator pitfall I'm missing here?
@army73472 жыл бұрын
Lol nevermind, I missed a zero the first few times. I corrected that and got the right answer.
@lemonyyofficial3 жыл бұрын
Yes boi I watch all ur vids and subbd.....u know I wish u were my high school teacher......keep up the gud wrk
@sanchariroy93253 жыл бұрын
Thank you!
@shahadmerani3116 Жыл бұрын
I was struggling so much bruh I didn’t know how to study having chemistry binders from different teachers and still being confused and I thought let me try organic chemistry this once too and IT WORKED again, wow
@stevelu4418 Жыл бұрын
Thank you a lot!
@barbarawrakonei7354 Жыл бұрын
It's so helpful to me.. Now I can calculate activation energy
@gbadamosiadijat16903 жыл бұрын
Thank you 😊
@juliancheung10013 жыл бұрын
The y axis in 13:28 should be number of collision
@frankensteinfranklin4617Ай бұрын
This guy is so fucking perfect
@RyanMSilverman2 жыл бұрын
Thank you so much bro
@daboi38673 жыл бұрын
Any of the dislikes are just teachers who wish they were this good
@theopenacademy91023 жыл бұрын
There aren't any? Plus he's paywalling all his stuff now.
@user-yx2dt7kx2m6 ай бұрын
"have sufficient energy to break some bonds and form some new bonds"
@toperaheem24 күн бұрын
Describes my entire social lifestyle
@mikekabamba-tt9pg5 күн бұрын
The best
@natnaelsileshi28543 жыл бұрын
What about R on k2 formola
@Royalty11113 жыл бұрын
Thank u 😘😊
@razasyed5752 жыл бұрын
you the man homedog
@agelopian7321 Жыл бұрын
what would happen on k iff the Ea gets the value equal to RT?
@ngawangr5324 Жыл бұрын
im already taking physics and calculus 2 right now and this whole video turned into calc and physics lol. what happened to chemistry
@timeless9820 Жыл бұрын
math and physics are more prominent and used in a microscopic level 8D
@JD-xb9eo3 жыл бұрын
When you will do face reveal? i want to see your face before i died
@mrblackbird69363 жыл бұрын
Look it up
@JD-xb9eo3 жыл бұрын
@@mrblackbird6936 Wdym?
@mrblackbird69363 жыл бұрын
I mean I saw his face on a website when I searched his name.
@JD-xb9eo3 жыл бұрын
@@mrblackbird6936 What's his name?
@mrblackbird69363 жыл бұрын
@@JD-xb9eo Julio Gonzales
@user-jk7fy8sm7v9 ай бұрын
Sir please recalculate the trial again. I’m confused. Thank you
@aishaakinbola22923 жыл бұрын
The membership link is not working. Please help fix it
@q8nkwani72 жыл бұрын
ahhhh this is so hard I can't do this uni shlt no more
@fairyyoongi Жыл бұрын
for the last question (#2) I got Ea= -16.05 kJ
@joshuannamdi5242 Жыл бұрын
it should be 16.407 kJ/mol
@noureldinayman63173 жыл бұрын
We want an AP Classes pleaaaaase ❤️❤️❤️❤️
@apekshayabhandari1213 жыл бұрын
Hello
@perriannesimkhovitch1127 Жыл бұрын
Chemistry: all the conditions met to stimulate an event, that is then icnored by the greater universe
@stefanugaz3 жыл бұрын
GOAT
@owenturnacliff781810 ай бұрын
saved
@concernkid Жыл бұрын
please are you Gonzales ?
@peps1overcoke3 жыл бұрын
First
@AlaaAbdullah-rm7orАй бұрын
شكلي العربية الوحيدة هنا 😂😂😂❤
@abassmobolaji9809 Жыл бұрын
🎉❤
@FF_BMG3 жыл бұрын
first
@ElGibb02 ай бұрын
Damn I don’t get this shit at all
@7sedma2 жыл бұрын
Am I the only one who's watching these because I like chemistry? not school or anything else
@olashileadekoya3375 Жыл бұрын
How can I calculate the free energy of activation by using this formula ∆Gǂ=-RT(2.303logkh/TKB)