Good to hear! Hope you enjoy your exploration of fictitious forces.

I'm glad it helped - thanks for watching.

Happy to hear that it was intuitive!

Thanks!

Thanks! That's a fair point, I do try to do this but probably forget sometimes.

@@DrBenYelverton but nice job nonetheless! I would love if you try to answer a doubt I have :) What if someone from the northern hemisphere tries to watch some clouds or winds in the southern hemisphere? Will he find the winds turn to the right or the left?

@@aniketdhumal2692 The Coriolis force only depends on the angular velocity vector of the Earth and on the velocity vector of the clouds - not on the position of the observer. So, the clouds are always going to deflect towards their own left. This means that if the clouds are moving towards the equator, the deflection will be towards the observer's right, while if they're moving towards the South pole, the deflection will be towards the observer's left.

@@DrBenYelverton Again thanks for the reply. Oh okay that's clears stuff up!! I thought (like the example you gave) the observer is the person itself. Again thanks

oh yes! if Fc = mv^2/r, we could also write it as Fc = m * v * v/r. but v/r is w, so Fc = m * v * w, or Fc ~ v * w, and since v and w are perpendicular, V x w = V * w. So, everything is fine, thank you ... !!

Good question! The moving object in the video is in fact experiencing both the centrifugal and Coriolis forces in the rotating frame - I didn’t mention this as I wanted to focus qualitatively on the effect of the Coriolis force and keep things intuitive. The centrifugal force always points radially outwards, but the Coriolis force will in general have both radial and tangential components (since it’s always perpendicular to the velocity, which changes direction over time). I think what’s happening here is that the inward radial component of the Coriolis force is balancing the centrifugal force, so that the radial distance increases at a constant rate, and the spiral shape of the trajectory is due to the tangential component of the Coriolis force. I haven’t worked through all the maths but maybe it would be worth going through the process of solving the equation of motion in the rotating frame, showing that the expected trajectory is reproduced only if both fictitious forces are taken into account.

The radius and the angle from the line of sight are both increasing linearly with time, so it's actually an Archimedean spiral.

@@DrBenYelverton Can you kindly give reference from where I may study about how this trajectory is proved to be an archimedian spiral ?

@@AmitKumar-xw5gp We can prove it as follows: since it’s moving at a constant speed, the object’s radius is given by r = vt, where v is speed and t is time. Then, since the observer is moving at a constant angular speed ω, the angle θ from the line of sight is given by θ = ωt. Thus, r = v*θ/ω, i.e. the trajectory is r = (v/ω) θ and r is proportional to θ.

@@DrBenYelverton Thank you.. Appreciate it very much.

Interesting - no, I've never done anything for Isaac Physics!

Thanks. Yes, absolutely - I used matplotlib to make the thumbnail but the focus of the video is on the Physics. Maybe in the future I can do another video showing how I made the figure, if there's enough interest.