The world and schooling industry needs more people like you man, kep it up and stay blessed

Thanks for the help I needed it and couldn't find a comprehensive video all over youtube

I wish I saw this earlier you really work magic and make lever problems seem easier thanks a lot

You are a lifesaver, scholar, & a gentleman!

Great Stuff! Straight forward. No errors or bumbling. Easy to follow. Thank you!

Im talking a mechanic diplomas & it's really help me, thanks alot

A perfect way to combine learning and entertainment. Thx a lot this helped me understand lever problems. Thank you again.

Thank you so much. That was very simple to follow and easy to understand.

Really nice keep up the amazing work!

Clearest explanation of this topic ive seen. Thanks a ton! (actually thanks a Newton)

For anyone who need this MA= input distance / output distance . Distances are inversely proportional to force so MA = Output Force / Input Force. My way of remembering this is " Mechanics (mechanical advantage both share the mech in the name) only WORRY about the INPUT DISTANCE not about the output distance so they can get paid. So be very careful of your input distance because mechanics will try to trick." No hate to mechanics.

This video has helped me so much !!

in block and tackle system , if we have 6 pulleys.can we keep 4 in upper block and 2 in lower?

i just wanna say tysm this rly helped me on my science test! i scored 100% just because of this video *hugs*

Thx, this help me in the medium school. I like yours explanations, are very great and chill. xD

It is so simple! I have a very hard time understanding this at first. Thank you so much for this video!

thanks for the explanation on the thing that i forgot to pay atention to in class, really helped with homework

If you push the long end of the lever down a distance d1, how much does the other end move up? (Call this distance d2.) Express you answer in terms of L1 and L2. Part 2 Assume that the work you do is equal the work done on the load. Express this assumption in terms of the forces F1 and F2 and displacements d1 and d2, and use your answer from part 1 to derive the lever equation. Part 2 (you can do this part without doing part 1 or 2) If I gave you a lever arm 10 m long, where would you have to rest it on the fulcrum to lift a 1000 kg object off the ground? (I.e., what must the ratio L1/L2 be?) (Hint: The force you can exert is probably largest if you lean on it and push down with all your weight.)

How do u calculate if there’s multiple Resistance on the output side?

This video was very helpful in explaining lever problems with good clear cut examples. Thanks for sharing.

Sir, this is beautiful video by you really this is very helpful for us thanks for sharing this types of video here we are requesting you kindly upload more and more video

Question Problem #4. Assume the triangle has only the one right hand side and that is welded to the lever at the apex as shown and the pivot now becomes the bottom of that leg and sat on the ground, is my input length increased by half the base of the triangle and my resistance length reduced by the same measure? I'm making a log roller/lifter. Nice to know the maths that go with it.

Thank you so much for helping me in school

You are a great instructor

THIS SAVED ME

At what point in the ruler you should put the load to take less effort in lifting it?

People of the world when your sit and watch someone vid and it help educate you please subscribe to give these servants of humanity credit it cost you nothing for your humanitarian efforts .. They don't have to do this for us!!!!

great sir🙌

Thank you!

youre a great teacher

thank you so much studying for the operating engineers union

Awesome video

Great source for learning from basics. Thanks

excellent!!

God bless you 😊

I have one im trying to get in a book. if any one can help. be awesome. a fire lieutenant is demonstrating how to use a crow bar to lift a concrete slab up about 2 in to allow a piece of shoring to be put under the concretes edge. the lieutenant ask the group of fire recruits to estimate how much effort would be needed to lift a 300 pound slab if they use a crow bar that is 6ft 6 in. long and the fulcrum is 6inch. from the adz end. the recruits would be most accurate if they agreed that the effort would be approximately . the answer says 25 pounds of effort. but i keep missing somthing? i keep getting it wrong. can any one here help?

this was very helpful thanks

Thank you.

The way I do it is multiply the input force by the beam divided by the output beam , much quicker for me.

How can I calculate the weight of a body to create certain angle in a seesaw? Tnx for your class.

May I ask has anyone already worked out a chart or tablet for a class A lever that provides the force weight and distance needed to lift on the other side? If so kindly provide the Link. Thank you

OMG THANK YOU SOOOOO MUCH

Hello. I am designing a machine that uses a pneumatic cylinder to operate a hole punch to punch through sheet metal. I will be using a lever to get a mechanical advantage to provide the force necessary. I am trying to figure out what kind of force would be experienced by the fulcrum or pivot point. I'm not having any luck finding information on how to calculate that. I would appreciate any help that you could provide. I know I haven't provided much detail here but I can give whatever information is needed to calculate that. Thanks.

Thank you very much.

It's helped me understand better thanks

It was amazing

I could make out very easily the problem you thought 🎩 off to you sir

really excellent

Super

Is of pascal"s hydraulic law as a simple machine,to be included?

nice explanation but you just make it more Complex you can do it very simple way

Thx, helpedALOT

stan lees brothher

I was looking at Problem 1 and I could be mistaken here :) but it didn't look correct to me. I'll explain. The input side said 200N at a distance of 4 Meters I thought to figure out the amount of force on the input side one just needed to times the mass by the distance so in problem one on the input side it would be 200N X distance of 4 meters which equals 800NM of force and then you would do the same thing on the other side and ask yourself what mass times 1.5 meter distance equals 800NM of force, to balance it all out which would be 533.3333333333333 X 1.5 meters equals 800NM

Thank you bro 🙏

Sir, can u please tell me if they ask the length what will i do

nicce

The same issue appears to be in Problem 2.

A proportion: example problem: (2m X 100N) divided by 1m = 200N..............1 st problem: (4m X 200N) divided by 1.5m = 533.33N this is the correct value since it was round off. 2 nd problem: (2.2m X 150N) divided by 4.6m = 71.74N etc review the side with two given value are multiply then divide by the side with one value.

What is maximum mechanical advantage possible???

response video: kzfaq.info/get/bejne/qqpxhcSG15eWhJ8.html

Thank you

Thanks

Sir please tell how to calculate leverage in brake pedal

A bag of sand 25g place at the end of a seesaw and a boy of mass 15g place at the other end of seesaw.the distant between the bag of sand and the boy is 25cm and acceleration due to gravity is 10m/s. Calculate, the mechanical advantage. 2 the velocity ratios. 3 the efficiency of the machine in percentage. Help me solve this example

is this the same with class 2 and class 3 levers?

“Short lesson.” 24 mins long. Well, that’s how it was at school. Im gonna play it at x1.5 speed Edit: this is a very good vid, thanks!

6 lever how to open 6 lever

I see it differently Problem 1. (200N x 4M) / 1.5M = 533.33N Problem 2. (150 x 2.2) / 4.6 = 71.739N Problem 3. (840 x 1)/ 6 = 140N Why the discrepancy?

is this guy still alive?

pero q es esto

What

Who is watching this at the age of 14 🙋‍♂️😅

sorry mate you tried but couldn't even put in 4 / 1.5

This guy fucked up the first two questions and is giving us long ass drawn out formulas that that aren’t even correct.