Hey man I really like. How you break the tricks down, I’m looking for a specific trick that I saw on you page where you have the spectator pick a card then get in the 3rd or 4th position from bottom then you set one down then put one on top end with 4 card and their selection is this in the pack if that makes sense

No set up... just get them to completely cut the deck in half.......yep.....lol

Thanks!

Thanks, happy new year!

Thanks so much man. I always appreciate your support! Happy New Year.

Glad it was helpful! Thanks.

That’s awesome. Thanks for watching!

Thanks, happy new year!

You're welcome!

Glad you like it!

Happy new year! Thanks!

Hey thanks!

@@MLTMagicTricks ya i watch all ur vids and starting watching u for like 1 or 2 years love ur tricks

Hey thanks!

Thanks! 😄

Thanks so much!

Thank you! Will do!

Thank you so much 😀

Thanks, you too!

Thanks! You too!

Happy new year

Happy new year!

Daniel Roy has good tutorials on it

@@rachaeltrimble1105 thanks

It will work always when the selected card is anywhere between 25th to 27th Card. (Counting from top). The piles can be 25/27, 26/26, 27/25.

@@sasipalagummi There's four stacks of 13 cards to choose from, though. So it could be in four different positions on either end, that's why I said off by two from the center. I guess maybe a better way to put it is that the card has to be in either the 25-28 position since each of those will be the 7th card in each of the four stacks. Another possible way to do this trick is to leave in the jokers if you have two different color jokers and then do six stacks of 9 cards each. This has two beneficial effects: 1) It makes the deck easier to manipulate as you are covering cards 25-31 and at the beginning you can pick up what you perceive to be the larger stack to drop on the smaller stack they place their card on top of, and 2) It makes it quicker to get to just the three piles of three cards after they pick the stack with their card. Having four stacks at the end with one you just automatically get rid of seems more suspicious, IMHO. With this setup, you are already at the three stacks of three cards each so you can do the forces necessary to get to the final reveal.

I agree to your suggestion of attempting this trick by including two joker cards. Alternately, we can still achieve this by asking the spectator to pick one card from the pack of 52. Then make nearly two equal piles and ask the spectator to place the card on top of either of the pile he chooses. Place the other pile on top and deal into 4 piles of 13 cards each. Having selected the pile having the selected card, deal again into 4 piles of of number of cards in each pile: 4,3,3,3. I often try this by not discarding the pile of 4 but combine all of them again and (the selected card will be in 9th position), I deal out all 13 cards and I pick out the 9th Card!!

Yes, I never had the chosen card in the middle pile. Always on one of the side piles, but in the middle of it. Your comment makes sense. I like the solution of letting them pick any card and then magician makes equal piles with remaining cards.

Why do people care when I watch?