😂

Happy to help!

+Paul Jackson The exponent represents how many places the dot was moving so we need to start at a middle value (127 is roughly the middle of 8 bits which has a range of 0-255). Since we start at 127 we can move the dot 128 spaces to the left, or 128 spaces to the right.

Ah yeah, now it makes sense, thank you for the quick reply ^^

@@NicholasDingle do you +127 because it was a positive 4? Would it be -127 if it is -4?

@@wolfcompany2 correct 127 + (-4) or -4 + 127which would be 123 also we get 127 because its a 32bit standard if its a 64bit standard it will be a different value

Concise wasn''t necessary lmao

check this one he explains it properly kzfaq.info/get/bejne/d7tkd9epsp_LkmQ.html

I don't think it would be hard to do, after watching this. Just do the exact reverse steps he did and I think it should work. Like, Mantissa is what it's after the dot. Cool. Exponent, you just do 131 - 127 = 4, then that's the Exponent. As the dot is always after the first 1 in the binary number, then it's "1.Matissa", in this case, 1.011111. As the Exponent is 4, you just move the dot in the opposite sign of 4 (-4 --> right): 10111.11. And there it is. Then it's just convert from binary to decimal. 11 (binary) = 3. Then, 3 / 2 = 1.5 [reminder: 1]; 1.5 / 2 = 0.75 [reminder: 1] - you divide 2 times because that's how many numbers are in the decimal part of the binary. The whole part of the number (101111), 1 + 2 + 4 + 0 + 16 = 23. 23 + 0.75 = 23.75. Now, the binary to decimal part, I made it up a bit hahaha (didn't think on it when I said it wouldn't be hard hahaha). No idea if it's right or not though. Cool though, made me think hahaha. But worked, at least. Just don't know if that's the right way or not. Later I'll look for some video that does the opposite of this one to be sure of the right way.

the (10) shows it is base 10 denary rather than base 2 binary

1023

For a single-precision number, (127). For a double-precision number, (1023).