The formula for finding the Exponent is: 2^(k-1) - 1. Since you have 8 exponent bits, replace "k" with 8 in that formula. You get 2^7, which is 128. Subtract 1 from that, and you get 127 as your final answer. :)

We have 8 bits to represent the exponent. We can represent 2^8 = 256 numbers with 8 bits. The bias is considered to be half of it minus 1 so that we can represent both positive and negative exponents.

thanks for this information

And it is 1023 for 64 bit which is called double precision.

Thank you :)

Couldn't agree more!

congrats !

yeaaaaaaaaaaaaaaaaaa.

5 years later same thing, and congrats

Two years later, and this gave me hope to pass my exam today. BIG THANKS

People with PhDs in computers get swirled into talking about irrelevant and overly complex things very easily. Its hard for them to stick to the point.

Professors get so much better at what they do that they forget what it's like to learn it for the first time or what it's like to not knowing these things, it becomes very obvious to them.

phd in computers

i agree with you sub apnu manjan bech rhy hn sajhny waly dhony prty hn

Probably because they still don't understand it LOL XD

Probably because is yet another indian xD

Probably because she's a scammer

Because it is a kid and those uni students feel insecure about a kid teaching them.

Because they're from UT

Right!!!!!!

How did he get 23 in mantissa? I still can't understand this part? Where did 23 come from?

4 hours :X

2 hours :c

8 AND A HALF :P

27.5 hrs :P

11 AND A HALF XD

She's from Texas A&M, what did we expect?

@@EdwardForgacs when in Rome...

😅same issue here thank for this video

Jaja💩

lol same

LMAOO

She could be from America too you know

Yep. She is obviously from America

@@mayankdeshpande7212 i mean if you ignore her accent sure

She is Indian American as this is from Texas AM University

actually it's a girl

yes yes ofcourse studenst are stuck in university professors lecture which cointain 45 min and no one can understand any of this. Allah kry hamry teachers ko samj ajy ky student ky mind ko kessy prhaty hn we have not good enough teacher but good enogh enough degree personn p.h.d , masters etc

How did he get 23 in mantissa? I still can't understand this part? Where did 23 come from?

N749 dddddTO

indian accent😶

How did he get 23 in mantissa? I still can't understand this part? Where did 23 come from?

Pressure sensor at work, spits out IEEE754 on UART. :)

for some coding projects it's good to know for example if you have limited space on any device, it's good to know that floating point in this notation only requires 4 bytes (32 bits)

I like to know what I'm working with.

you can say that for any subject except STEM

In embedded systems programming, a programmer is often writing code which operates at a low level by dealing with bytes and bits. Suppose you are writing code for a product which employs a microcontroller and you are using some communication protocol, e.g., SPI or I2C, so the microcontroller can communicate with an external device, e.g., a shift register. Suppose we are transmitting the value of a floating point number, e.g., you are programming in C and the data type of the value is double, which is represented in IEEE 754 notation. During testing you discover that the shift register is receiving a value which is different than the value stored in a variable in the microcontroller, i.e., you have a bug in the transmission code. So, you hook up your oscilloscope so you can view the signal being transmitted. The signal should go high when transmitting a 1 bit and it goes low when transmitting a 0 bit. You need to determine where a wrong bit is being transmitted because that will help you locate the bug. Therefore, you need to know the IEEE 754 binary floating point representation of the double value being transmitted so you will know when a 1 or 0 bit should be sent.

Helo, we ar tring to help yu, these es da maicrosoft soport teem

what?

Lmap

Bring tom with you sorry for my bad english

The IEEE standard has 4 different concepts to handle. 1. Non infinite normalized numbers 2. Non infinite denormalized numbers 3. positive or negative infinity. 4. Not a number. Used for error indications that propagate so it doesn't have to be checked for every mathematical operation. Notice that the range -126 t0 127 represents a total of 254 distinct values (don't forget the 0). But 8 bits can represent 256 distinct values. The 2 extra values are used to handle infinities and denormalized numbers. Number format s eeeeeeee mmmmmmmmmmmmmmmmmmmmmmm S = s E = eeeeeeee M = mmmmmmmmmmmmmmmmmmmmmmm if E is 00000000, the number is denormalized, value is (-1)^S * 0.M * 2^(-126) 00000001 - 11111110, number is normalized, value is (-1)^S * 1.M * 2^(E-127) 11111111, number is either infinity (M=0), or a NaN (Not a Number) if M 0. Notice that for the denormal numbers, that the most significate digit of the mantissa is 0, while for the normalized numbers, the most significant digit is 1. The most significate digit IS NOT EXPLICITLY STORED. That lets the IEEE standard squeeze in an extra digit of precision. So binary32 is consider to have 24 binary digits of precision, while only storing 23 of those digits. Same for binary64. Considered to have 53 digits of precision, while storing only 52. By the IEEE standard, Min will always have a magnitude one less than Max. So for binary32, we have 8 bits for the exponent. Since we have to account for positive and negative exponents, we have Max = 2^(8-1)-1 = 2^7-1 = 128-1 = 127 Min = -(Max-1) = -(127-1) = -126 For binary64, we use 11 bits for the exponent, so Max = 2^(11-1)-1 = 2^10 - 1 = 1024 -1 = 1023 Min = -(Max-1) = -(1023-1) = -1022 Doing it that way allows for the all zeros or all ones value of the exponent to handle denormal numbers as well as the special value infinity and the Not a Number error indications.

@@johncochran8497 John can I pay you to tutor me lol.. It is funny but I am serious. Please reply

@@TheAntonioclewis I'm willing to help you, but don't require any money. Perhaps this book drive.google.com/file/d/1-nWgEU-RcliZGmYIEQmoy43UocDUhHUQ/view?usp=sharing will help a bit.

pretty sure its a young boy

@@MyGdoggy the channel has a girls first name, and plus this is for a university class so she cant be a young boy

@@jetacedark123 Yeah you're right, she has a different video and you can see she's a girl. My bad.

@@MyGdoggy you so funny... This kid is funny

How did he get 23 in mantissa? I still can't understand this part? Where did 23 come from?