Degrees of Freedom - Organic Chemistry - Class XI

Degrees of Freedom - Organic Chemistry - Class XI - XII

Рет қаралды 35,354

3 жыл бұрын

The number of independent ways in which a molecule or an atom can exhibit motion is called degrees of freedom
If a molecule contains N number of atoms.
Position of each atom can be defined by three coordinates (x, y, z)
∴ 3N degrees of Freedom
Total Degree of Freedom = Translational + Rotational + Vibrational
3N = DOF(Translational) + DOF(Rotational) + DOF(Vibrational)
Translational Motion (3)
Change in center of gravity of molecule.
∴ (3N - 3) = DOF(Rotational) + DOF(Vibrational)
Rotational Motion (2)
∴ (3N - 5) = DOF(Vibrational)
For diatomic molecules (HCl, CO, H2 etc) ➜ Linear Molecules
\text{ Vibrational degree of freedom } = (3N-5) = (3 \times 2 -5) = (6-5) = 1
For polyatomic molecules (CO2) ➜ Linear Molecule
\text{ Vibrational degree of freedom } = (3N-5) = (3 \times 3 -5) = (9-5) = 4
∴ (3N - 6) = DOF(Vibrational)
For polyatomic molecules (H2O) ➜ Non Linear Molecule H2O (N = 3)
\text{ Vibrational degree of freedom } = (3N-6) = (3 \times 3 -6) = (9-6) = 3
For polyatomic molecules (CH3Cl) ➜ Non Linear Molecule CH3Cl (N = 5)
\text{ Vibrational degree of freedom } = (3N-6) = (3 \times 5 -6) = (15-6) = 9
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Пікірлер: 33

@sumitrabehera 2 жыл бұрын

Finally understood..... 😀 Your animations helped me a lot.... And, Thank you.... 🙏

@Edmerls 2 жыл бұрын

Glad to hear that!

@aanchaljain7596 2 жыл бұрын

but going by the logic of mode of energy storage no. of vib. dof in diatomic mol. should be 2 pls clarify

@risanpaul1411 3 жыл бұрын

Finally understood 😅

@tatipallisateesh8994 3 жыл бұрын

Here in this diagram about y-axis degrees of freedom is not possible. But it shown z-axis.

@benYaakov 2 жыл бұрын

Hello , I have a question Whether it's linear , non - linear , monotonic diatomic etc etc , will it's translational degree of fredom be always 3 ?

@Edmerls 2 жыл бұрын

Yes,, because it can travel in only 3 direction ..

@benYaakov 2 жыл бұрын

@@Edmerls ok thanks

@jaafarwamwere6282 2 жыл бұрын

Thank you so much. You’ve made it so easy

@Edmerls 2 жыл бұрын

Glad it helped!

@Amit-hi9cb 2 жыл бұрын

Great

@AkashSingh-zy5xe 9 ай бұрын

Now I got the correct explanation

@pjrchemistryclasses3200 3 жыл бұрын

Such an excellent explanation madam through this lecture I can easily understand the group theory madamm........

@Edmerls 3 жыл бұрын

Glad to hear that

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