Difference Between Partial and Total Derivative

  Рет қаралды 536,716

Physics by Alexander FufaeV

Physics by Alexander FufaeV

2 жыл бұрын

• All Physics Explained:...
More: en.fufaev.org/questions/1235
Books by Alexander Fufaev:
1) Equations of Physics: Solve EVERY Physics Problem
en.fufaev.org/physics-equatio...
2) Alexander Fufaev and His Never Ending Story:
en.fufaev.org/lifestory

Пікірлер: 330
@fufaev-alexander
@fufaev-alexander 2 жыл бұрын
eBook: en.fufaev.org/physics-equations-book Paperback: tinyurl.com/physics-paperback Hardcover: tinyurl.com/physics-hardcover
@touch_detective
@touch_detective 10 ай бұрын
Me in highschool math class: never pays attention Me in bed at 3am: Yes Derivative is and has always been my passion
@fufaev-alexander
@fufaev-alexander 10 ай бұрын
haha :D
@psychoshooter095
@psychoshooter095 6 ай бұрын
and i thought it was just a cooler way to write...
@artey6671
@artey6671 Жыл бұрын
Well, in this case the difference is easy: The partial derivative is expected to use sensible notation, whereas the total derivative somehow thinks that y is a function.
@simonmarcoux5879
@simonmarcoux5879 Жыл бұрын
if y was independent of x and you still used d instead of del ...it would yield the exact same result. I wholly agree with your opinion that it is by no mean a sensible notation nor is it intuitive.
@artey6671
@artey6671 Жыл бұрын
@@simonmarcoux5879 I once took a class where I worked on the problem sheets with a physicist. He understood the strange notation and he tried to explain it to me, but I didn't get it. I gave up on the class not much later and he apparently almost made it at least. It was semiclassical analysis.
@BladeOfLight16
@BladeOfLight16 Жыл бұрын
It's not a question of what the operation "thinks." It's a question of the _assumptions_ *you* are imposing on the problem space. A partial derivative means you are assuming the variables vary independently, and this means the derivative of the variable with respect to the other variable is 0. y does not change value _at all_ when x changes value; any pair of values for x and y is possible (within their respective domains). y can still be a function, but it cannot be a function _of x._ A total derivative discards this assumption and allows for the possibility that they may be dependent, but it reduces to the partial derivative in the case when they are not. It is not valid to take a partial derivative when the assumption of independence does not hold. In other words, taking a partial derivative is declaring that you know (or are assuming) the variables to be independent. It would be completely equivalent to merely write, "Because x and y are independent, dy/dx = 0," and use that to continue solving the problem instead.
@artey6671
@artey6671 Жыл бұрын
@@BladeOfLight16 Is that what engineering calculus books say? Damn.
@simonmarcoux5879
@simonmarcoux5879 Жыл бұрын
@@BladeOfLight16 wow! Now that is what i call a clear explaination. It lift away the confusions I had while watching the video. I must admit that it as been 12 13 years since the last time i used any form of partial/total derivative in a math sence. I still often calculate a discrete rate using embedded programming, but it has 0 mathematical formality to it: change on a value divided by the elapsed time between values. Thanks a lot for the insightful reply.
@Exist64
@Exist64 Жыл бұрын
I love that this video is so short and yet insightful.
@manwork6545
@manwork6545 2 жыл бұрын
Basic stuff but excellent explanation!
@fufaev-alexander
@fufaev-alexander 2 жыл бұрын
Thank you! Do you like short videos like this that answer a specific question?
@mathematicaleconomist4943
@mathematicaleconomist4943 Жыл бұрын
@@fufaev-alexander Brilliant! I am generally more likely to "tap on" brief videos (like this one!). There's usually no time! The more intuitive the explanation, the better! That being said, I am certainly not allergic to long videos when I have the time. But I definitely like the brief ones!
@kikilolo6771
@kikilolo6771 Жыл бұрын
@@fufaev-alexander Personally I like short videos like these that make things clear and don't go into too much stuff we don't care but I also appreciate longer videos that go more deeply into the subject
@Flaystray
@Flaystray Жыл бұрын
Yes, because everyone in the world should already know this by now! If they don't, they must be fucking stupid!
@TepsiMorphic
@TepsiMorphic Жыл бұрын
​@@fufaev-alexander i also prefer short videos but the thing is, can you always compress an interesting topic into a short video without it losing something meaningful?
@Husain_bohra
@Husain_bohra 5 ай бұрын
Okay in simpler terms Partial derivative differentiates the x term normally but expects every other term to be a constant.
@jacobstarr9010
@jacobstarr9010 2 ай бұрын
Basically this: if partial, treat all other variables other than the one you’re differentiating with respect to as a constant. If total, differentiate everything.
@austinburrington6434
@austinburrington6434 3 ай бұрын
I’m honestly surprised they never explained this when I took multivariable calculus.
@moslynmoslyn679
@moslynmoslyn679 3 ай бұрын
seriously😅
@phild8095
@phild8095 10 ай бұрын
As a student I loved loved differential and partial differential equations. They were the poetry of engineering. They represented beauty and truth.
@con_el_maestro3544
@con_el_maestro3544 10 ай бұрын
I need to know what you drinking, I guess my stuff is not strong enough
@phild8095
@phild8095 10 ай бұрын
@@con_el_maestro3544 I'm drinking Iowa water with a touch of lemon juice. Worcester Polytechnic Institute. Dr. John Van Alstyne taught ordinary differential equations and Dr. Robert Wagner, Dr. Anthony Dixon, Dr Y.H. "Ed" Ma, Dr. Bob Thompson and Dr Al Sacco all taught Chem Eng Partials in various classes. The best was a project I did with Ed Ma. It was modeling physical adsorbtion in 3d and finding the speed of molecules diffusing into pores of zeolites. I developed about 20 equations and worked it down to the one that gave velocity of molecules as they bounced down the tine pores in the zeolites and then plugged in my raw data to get the diffusion rate and mean velocity. Absolutely glorious. That was many decades ago. About 15 years ago in the process of moving I found my research project report and started going through the derivation and was amazed at what I had done my senior year. That report was the most hard core engineering math I had ever done. I suppose it is still in the WPI library as a pdf. As part of my research to do the project I had done some reading and found a mistake in some work that had published a few years prior. I don't miss the endless hours solo in the lab, but the writing and modeling was a blast.
@yamatanoorochi3149
@yamatanoorochi3149 6 ай бұрын
I only learned about this today and it's not even in my curriculum yet Excited about that
@DrSmoke2104
@DrSmoke2104 Жыл бұрын
I needed this video in my Differential Equations course back in 2014. Thanks dude!
@david_porthouse
@david_porthouse Жыл бұрын
There’s a deficiency in notation for partial derivatives. They should strictly be followed by a vertical bar and a subscript to indicate what is being kept constant. Normally this is taken for granted, but it can cause confusion.
@death_parade
@death_parade Жыл бұрын
Thanks for mentioning this.
@zeybarur
@zeybarur Жыл бұрын
Yes, it's extremely important in thermodynamics, for exmaple... Learned that the hard way 😅
@egoreremeev9969
@egoreremeev9969 Жыл бұрын
Actually there is no deficiency in notation in the case of partial derivatives. Each other variable is by definition of partial derivative - constant, so notation \partial_{x_2} f(x_1,x_2,...,x_n) is telling us how function behaves on line (x_1, y, ..., x_n) with y - as variable It only becomes necessary if we want to make "not total" derivative, i.e. keeping some variables constant.
@iyziejane
@iyziejane Жыл бұрын
The reason we do that in thermodynamics is not that partial derivatives are unclear, but to remind readers of which variables are taken to be the independent variables for each of the thermodynamic potentials. So the thermodynamic energy E is naturally a function of entropy S and volume V (so that pressure P and temperature T are not independent variables, but depend on S and V). The Helmholtz free energy F = E - TS naturally trades out entropy S for temperature T. E(S,V) vs F(T,V). The Legendre transform is used to switch one independent variable for another because of the way it leads to the the corresponding differentials being changed, e.g. dE = T dS - P dV compared with dF = - S dT - P dV . The extra notation on the partial derivatives is just an extra helper to keep these definitions straight, so you may write T = (\partial E / \partial S)_V to remind you that V is the other independent variable when your thermodynamic potential is E. But that fact never changes and can just be learned as part of the definition of E.
@sebastian8870
@sebastian8870 Жыл бұрын
That is common notation in thermodynamics!
@j3i2i2yl7
@j3i2i2yl7 Жыл бұрын
I appreciate the brevity of the video. It takes a while for concepts, even basic ones, to sink in.
@atrandom1438
@atrandom1438 Жыл бұрын
this video gives better understanding. nice explanation! thank you so much for clearing all confusion.
@apm77
@apm77 Жыл бұрын
As I understand it the main motivation behind the difference in notation is that it serves as a preventative against certain careless errors, for example it reminds you that you can't use the two-dimensional version of the chain rule.
@Thedarkknight2244
@Thedarkknight2244 10 ай бұрын
Wow 4 years of engineering and 3 thermo and thermo related modules, and I find out it was that simple
@spaceluke420
@spaceluke420 6 ай бұрын
super clear and quick explanation + nice little exalple to understand everything. Great video!
@renesperb
@renesperb Жыл бұрын
Partial derivative simply means : all other variables are kept constant. For two variables it is also useful to know the geometric interpretation: z= f[x,y] represents a surface over the (x,y)- plane . If we take the partial derivative with respect to x , we get the slope of the curve obtained by intersecting the surface and the plane y = constant , and of course similarly if we take the derivative with respect to y .
@solwizard
@solwizard 11 ай бұрын
Thanks! You nailed it for me.
@vladimirsemenyuk792
@vladimirsemenyuk792 10 ай бұрын
Finally, someone who knows math
@reinhardtristaneugen9113
@reinhardtristaneugen9113 11 ай бұрын
...gerade habe ich eine KZfaq-Synopsis zum Thema gewöhnliche Differentialgleichungen gesehen und weil Differentialgleichungen für mich ähnlich schön sind wie klassische Musik, kommt hier meine Kurzsynopsis zum Thema, wie ich sie unterscheide: eine gewöhnliche DGL ist jede DGL, die nicht partiell ist, was bedeutet, dass in ihr nur nach eine Größe abgeleitet wird... z. B. ist die Funktion z = f ( x, y ) nach mehreren Größen ableitbar, sodass sie partiell ist, und eine Ableitung ist z. B. df ( x, y ) / dx, wobei man sich das < d > bitte in kyrillischer Schreibweise vorstelle, weil es die partiellen Ableitungen indiziert. Eine DGL ist linear, wenn die Größe, nach der abgeleitet wird nicht quadratisch ist, keine Wurzel vorhanden ist und kein Winkelargument vorkommt, zudem ist y ( x ) mal y' ( x ) = 1/ x nichtlinear, weil die Ableitung mit der gesuchten Funktion multipliziert wird, was Linearität auch unmöglich macht. Weiterhin gibt es lineare Differentialgleichung mit konstantem Koeffizienten, was die Koeffizienten betrifft, die vor x stehen, indem sie konstant sind, wenn sie nicht von x abhängig sind. Homogen ist eine DGL, wenn die Größe, nach der abgeleitet wird oder eine ihrer Ableitungen in allen Termen vorkommt, sodass jeder sieht, dass y''( x ) - 3y' ( x ) = 2xhoch2 inhomogen ist, weil der Term rechts der Äquivalenz eine Funktion ist, die für die Inhomogenität sorgt. Die höchste Ableitung schließlich bestimmt die Ordnung einer DGL, wobei das für viele ein Stolperstein bei zweiten Ableitungen ist, indem sie fälschlich annehmen, das Quadrat zeige Nichtlinearizität an, wobei ich diesen Flüchtigkeitsfehler vermeide, indem ich mir die Terme geklammert denke, sodass sich die Linearität klar zeigt, weil das Quadrat eben sehr deutlich einer Ableitung zugeordnet werden kann, die Teil eines Term ist. Für mich fast so schön wie Musik von Bach... ...übrigens ist das Erkennen von Unterschieden in Differentialgleichungen nicht wirklich schwierig, aber sehr inspirierend ( ...es erfüllt mich mit Leben... ), und es ist unerlässlich, weil es für die verschiedenen Arten von DGL's auch verschiedene Wege gibt, sie zu lösen... Le p'tit Daniel
@Trooman20
@Trooman20 10 ай бұрын
Thanks this helped a lot. I am currently studying Potential energy and Force so this helps a lot in making out the difference between both the types of derivatives
@Allahu_Akbar_the_one
@Allahu_Akbar_the_one 9 ай бұрын
Partial differentiation are the mini major bosses you see in games that very scary but easy to beat
@touseefhasan
@touseefhasan 10 ай бұрын
Short and precise. Thank you for this!
@FreydaStern
@FreydaStern Жыл бұрын
Wish i found the channel when you started 3 years ago, it would have been a huge help to me
@SomeoneCommenting
@SomeoneCommenting 6 ай бұрын
Wow, I took this on Calculus so long ago that I just realized that I forgot something so simple. I got both wrong in the _y_ part. Keep practicing your math or it will go away.
@MH-sf6jz
@MH-sf6jz 8 ай бұрын
For someone who wants to know more, total derivative is only used when there is only one input (in Real), i.e. a path composed with the function. To be more specific, let f(x1,…xn) be a real valued function, and g(x) =(g1(x),g2(x),…,gn(x)) be a vector valued function, then the function f o g is a single variable function that has one input, we call the function g a path. So when the path is specified, we write d/dx f = d/dx (f o g), where the (total) derivative is clearly well defined for f o g. The path makes all other variable dependent on one. Intrinsically there is no relation between each variable x1,…,xn, it is the entries of the path g that has relations. Note that for one variable functions, partial derivative is the same as total derivative, because they are just normal derivative (not in the sense of normal direction derivative).
@curtisnewton2295
@curtisnewton2295 Ай бұрын
1:43 very well spent. Thanks very much!
@tb1197
@tb1197 10 ай бұрын
Many students would simplify both to f/x😲
@hamzawasi2003
@hamzawasi2003 2 ай бұрын
Great stuff, Sir keep it up.
@jobr2866
@jobr2866 Жыл бұрын
Exactly the thing i needed to understand my mechanic lecture , thank you a lot!!
@fufaev-alexander
@fufaev-alexander Жыл бұрын
Well, I'm glad I could help you make sense of your mechanic lecture! Keep up the mechanical brilliance!
@TK-bj1yg
@TK-bj1yg 9 ай бұрын
thank for this video. It's very easy to understand compare to my lecture
@qazxl123
@qazxl123 11 ай бұрын
I took college math all the way through partial diff eq and I still didn’t know the difference until 10 seconds ago
@rubenlarochelle1881
@rubenlarochelle1881 Жыл бұрын
Interesting to note that, if in doubt, you can use the second method: the first one is just one step further...
@AJ-et3vf
@AJ-et3vf 2 жыл бұрын
awesome video! thank you!
@connor9024
@connor9024 10 ай бұрын
All I know is that when the ratio of prices in a budget is equal to the ratio of partial derivatives of the Indifference Curve of the items in that budget, that’s the amount that maximizes utility.
@12-343
@12-343 11 ай бұрын
Interesting, I had only ever seen them as separate notations for the same operation.
@mtaur4113
@mtaur4113 Жыл бұрын
I usually dislike using partial and total notation for the same function. It becomes very dependent on context and interpretation. Having g(x)=f(x,phi(x)) leads to unambiguous dg/dx notation that can also be expanded wrt the partials of f, but notation overkill can be a danger too. One of the things that is hard to explain in a chain rule is when the variable name appears at two different depths, when a truly unambiguous chain rule would have different notations for each variable slot of each function, but again, the price is notation overkill. Overall it kind of sucks, lol.
@samslara
@samslara Жыл бұрын
Best video explaining the difference. Good job.
@LCGamingOriginal
@LCGamingOriginal 6 ай бұрын
nice video!
@yarenkaya7872
@yarenkaya7872 Жыл бұрын
Straightforward explanation, thank you sir
@fufaev-alexander
@fufaev-alexander Жыл бұрын
Hey Yaren, thank you for your feedback!
@distrologic2925
@distrologic2925 11 ай бұрын
practically partial deriviation is just a special case of total deriviation where y(x) is constant
@fufaev-alexander
@fufaev-alexander 11 ай бұрын
yep
@mohamedmohamed-lf2eq
@mohamedmohamed-lf2eq Жыл бұрын
In the total differential, not that y can depend on x, but because the dx, and dy are considered as an elementary objects, so in d(3x^2)/dx we can write d(3x^2) = 6xdx than the dx cancel out, but in the case of dy/dx, dy can not be cancelled with dx, both are considered as an elementary differential objects in a defrent axis
@ReynoldsGarrett
@ReynoldsGarrett Жыл бұрын
Man I’ve been looking for this video for the past 6 years.
@JakubS
@JakubS 11 ай бұрын
So the partial derivative is when dy/dx=0?
@matusmoro955
@matusmoro955 11 ай бұрын
Yea
@austinburrington6434
@austinburrington6434 3 ай бұрын
In this example it’s a consequence of the partial derivative. I like to think about it in terms of orthogonal systems.
@comma_thingy
@comma_thingy Жыл бұрын
Maybe I'm missing something here but this doesn't make any sense? For a single variable function of course the partial and total derivative are the same. When we have a multivariate function (I'll stick to a vector space like R^n cause I'm not that well informed for other situations), we can take partial derivatives in each variable and also in some linear combination of them (a directional derivative). The relevance being of course that this derivative is the standard derivative of the function at the point we evaluate at, in "the direction of" the variable we differentiated by. The total derivative (if it exists, which it might not) is then a function which encodes all this information for all possible directions at all points, which, in the case of a multivariate function, will lead to this function being matrix valued (in the case f:R^n->R^m, it will be a mxn matrix), with each entry of the matrix a function of the original variables. Overall, the total derivatives represents the tangent plane, whereas the partial derivative just tells you the slope of that plane in a particular direction. Of course, there is a relation between the two derivatives: we can obtain partial derivatives by applying this total derivative linear map to the direction we want to consider and we can obtain the total derivative by considering the partial derivatives in the direction of each of the variables to get a column vector for each. We then combine these columns into a matrix and we get our total derivative. It's important that any direction vectors we use are normalised so we don't create random constants everywhere. Sometimes we write this total derivative as Df, or maybe ∇f, but writing df/dx for a function f(x,y) just seems wrong, unless y is some function of x itself, in which case the partial derivative should also acknowledge this. The partial and total derivatives for a function of the form f(x,y(x)) will be the same, since this f is really just another function g(x)=f(x,y(x)). When we compute the total derivative, it will be a mx1 matrix (since g is R->R^m), and this corresponds to the column vector we get when we take the partial derivative in x. I come from a pure maths background and some people in the comments seem to be physics based, so perhaps this is some sort of weird notation physics is using, but this is not the difference between total and partial derivatives.
@t33can
@t33can Жыл бұрын
This is the actual answer. Like you said, the video is somewhat confusing and doesn't seem to realize that both expressions as stated in it must lead to the same result.
@iyziejane
@iyziejane Жыл бұрын
The videos notion of total derivative is related to your more sophisticated perspective of the total derivative as a linear map. First we are specializing to functions f: R^n -> R so your total derivative that is matrix valued in general is now a single row vector, (i.e. the co-vector that represents the linear functional, or it is also a differential form). I'll write Df = [ (∂f/∂x_1) , ... , (∂f/∂x_n)] to represent this linear map as a row vector. Now suppose you have a smooth function X: R -> R^n with X(t) = (x_1(t),...,x_n(t)). Let F be the composition of f with X, so F(t) = f(X(t)). Now dF/dt is a derivative of a real-valued single variable function. We can express it with the chain rule as (d F/dt) = (∂f/∂x_1)(dx_1/dt) + ... + (∂f/∂x_n)(dx_n/dt). In these introductory calculus classes, this chain rule expression for (d F / dt) is called a total derivative. As you can see, it is your total derivative linear map acting on the unnormalized tangent vector to the curve X: R -> R^n at that point. This situation comes up all the time in calculations, including physics, or anything to do with real time. To take a finance example, the price of A might be related to prices of other goods B, C , D, so we have P_A(B,C,D) , but all these prices are functions of time as well, so d P_A / dt will use this "total derivative" chain rule.
@JoseGalois
@JoseGalois 11 ай бұрын
you are right. they all have no idea what's happening and are just playing around with notation.
@appleorange754
@appleorange754 10 ай бұрын
thank you
@jamesraymond1158
@jamesraymond1158 Жыл бұрын
thank you. I learned this many years ago but couldn't remember the difference. Now I know again.
@MrZero12132
@MrZero12132 11 ай бұрын
Opps I have been using them both interchangeably not knowing they are different💀💀💀💀💀💀💀💀
@ismahelo
@ismahelo 7 ай бұрын
How did you create the animations for the video? I love them!
@justahobby9794
@justahobby9794 Жыл бұрын
Thank you very much sir! very useful video
@fufaev-alexander
@fufaev-alexander Жыл бұрын
Thank you for the comment! 🙃
@shifanathpkm182
@shifanathpkm182 Жыл бұрын
Omg never knew maths was this interesting!
@tarikboukara7612
@tarikboukara7612 Жыл бұрын
Thank you amazing video
@isuckatthisgame
@isuckatthisgame Жыл бұрын
In partial derivative, y is seen as constant and derivative of any constant is zero.
@hamman_samuel
@hamman_samuel 11 ай бұрын
If only my calculus teacher had explained it this simply 😑
@benicioterrymendoza9302
@benicioterrymendoza9302 10 ай бұрын
I like to think of a partial derivative as taking the total derivative of curve thats formed when u cut an n dimensional function with a 2d plane. The partial derivative would be the slope of the tangent line in that confined 2d space.
@tolkienfan1972
@tolkienfan1972 Жыл бұрын
This is the clearest explanation I've seen
@fufaev-alexander
@fufaev-alexander Жыл бұрын
thanks, tolkienfan1972!
@evelyntromp789
@evelyntromp789 Жыл бұрын
Thank you!
@fufaev-alexander
@fufaev-alexander Жыл бұрын
Thank you back, for the comment, Evelyn!
@Anik_Sine
@Anik_Sine Жыл бұрын
I used to think that the other variable is taken as a constant in case of total derivative too. Hence my belief that partial derivatives are pointless.
@darkdelphin834
@darkdelphin834 Жыл бұрын
Me too. My teacher in Calc3 said that since you write down the variable you are differentiating with respect to then it doesn't really make a difference on the notation. I assume he said that because we were always given the functions. Plus later we used the chain rule with which it was necessary to understand which function depends on which variable... Still though it wouldn't matter much on the notation idrk... Nevertheless this video did explain it quite simply.
@darkdelphin834
@darkdelphin834 Жыл бұрын
On another note, in physics the teachers never even bothered using the partial derivative notation and they always use the d/dx symbol... They also say that it doesn't make a difference since you are writing down the variable you are differentiating with respect to...
@Empire-Trades
@Empire-Trades 8 ай бұрын
thanks bro
@chrismarklowitz1001
@chrismarklowitz1001 11 ай бұрын
Simple its not the whole infentesimal change in f just the part in one direction. Thats why when you learn directional derivatives its just adding them together to get the actual change.
@ericephemetherson3964
@ericephemetherson3964 Жыл бұрын
The difference is the difference between partial y contained in x and the other way round where the answer must be derived again.
@Manuelsanchez-eu7ez
@Manuelsanchez-eu7ez Жыл бұрын
Gracias chavall!!!
@DeepakDhaarmik
@DeepakDhaarmik 11 ай бұрын
Here in India we teach This as Follows Next, an excerpts from one of my books: This fourth example is regarding the differentiation of functions in two variables. For a function in two variables, say z = z(x, y), at a value x=a, y=b, the elementary change in z, say dz, can be seen in infinitely many directions. In fact, these directions are along the lines at various angles starting from the point (a, b) in x-y plane. Let us consider an arbitrary direction from the point (a, b) at an angle, θ. Angle θ is measured anticlockwise from the increasing direction of x. We trace an elementary distance, say dr, on this line from point (a, b). At the end of this elementary trace, the coordinates of the point specify the respective changes in values of x and y. The term “dr” refers to the elementary change in a variable r that takes values as the distances along the direction θ. Obviously, dx will be dr.cosθ and dy will be dr.sinθ. Hence, tanθ = dy/dx and dr is √[1 + (dy/dx)2].dx. Now, at point x= a, y= b, in this direction, that is at angle θ, the change in z, that is dz, is z(a + dx, b + dy) - z(a, b). Let us see the rate of change in this arbitrary direction, θ. Rate of change here can be considered in three needful cases- 1. When the variable with respect to which the rate is calculated is r, the rate of change is called directional derivative. It is [z(a + dx, b + dy) - z(a, b)]/dr. It is denoted as dz/dr. 2. When the variable with respect to which the rate is calculated is x, the rate of change is called x-derivative. It is [z(a + dx, b + dy) - z(a, b)]/dx. It is denoted as dz/dx. 3. When the variable with respect to which the rate is calculated is y, the rate of change is called y-derivative. It is [z(a + dx, b + dy) - z(a, b)]/dy. It is denoted as dz/dy. Now, at the point (a, b), we define the directional derivatives in two standard directions- 1. Along x-axis, θ=0, we define [z(a + dx, b) - z(a, b)]/dx, which is called partial x-derivative. It is denoted as ∂z/∂x. 2. Along y-axis, θ=Л/2, we define [z(a, b + dy) - z(a, b)]/dy, which is called partial y-derivative. It is denoted as ∂z/∂y. Now, we can express dz/dr, dz/dx and dz/dy in terms of partial derivatives- 1. A re-arrangement of [z(a + dx, b + dy) - z(a, b)]/dr gives- [z(a + dx, b + dy) - z(a, b + dy)]/dr + [z(a, b + dy) - z(a, b)]/dr = [z(a + dx, b + dy) - z(a, b + dy)]/[ √[1 + (dy/dx)2].dx] + [z(a, b + dy) - z(a, b)]. [dy/dx]/[ √[1 + (dy/dx)2].dy] = [∂z/∂x]/ √[1 + (dy/dx)2] + [∂z/∂y].[dy/dx]/ √[1 + (dy/dx)2] 2. A re-arrangement of [z(a + dx, b + dy) - z(a, b)]/dx gives- [z(a + dx, b + dy) - z(a, b + dy)]/dx + [z(a, b + dy) - z(a, b)]/dx = [z(a + dx, b + dy) - z(a, b + dy)]/dx + [z(a, b + dy) - z(a, b)]. [dy/dx]/dy = [∂z/∂x] + [∂z/∂y].[dy/dx] 3. A re-arrangement of [z(a + dx, b + dy) - z(a, b)]/dy gives- [z(a + dx, b + dy) - z(a, b + dy)]/dy + [z(a, b + dy) - z(a, b)]/dy = [z(a + dx, b + dy) - z(a, b + dy)].[dx/dy]/dx + [z(a, b + dy) - z(a, b)]/dy = [∂z/∂x]. [dx/dy] + [∂z/∂y] Note that if we take the point (a, b) on some curve in x-y plane, say f(x, y)=f(a, b), then the directional derivative of the function z = z(x, y) in the direction along the curve at point (a, b), which is along the tangent to the curve at point (a, b), will use dy/dx value as that calculated from the equation of the curve, that is f(x, y) = f(a, b). The equation of the curve may be given in parametric form. Or, it may be given in some other coordinate system. Directional derivative with respect to a variable in one coordinate-system in terms of directional derivatives with respect to variables in other coordinate-system can be found easily using the relations among the variables of two systems. Now, we would like to find the direction and magnitude of the maximum rate of change of function z = z(x, y) at point (a, b). Note that at the point (a, b), the value of the function is z(a, b). The set of all points for which the value of the function is same as at point (a, b) will correspond to a curve whose equation will be z(x, y) = z(a, b). Such curve is called equi-valued curve for the function z(x, y). Along this curve at any point, the change in the value of the function will be zero. Therefore, dz/dr = 0, along this curve. That means [∂z/∂x]/ √[1 + (dy/dx)2] + [∂z/∂y].[dy/dx]/ √[1 + (dy/dx)2] will be zero along this curve. Hence, we can find the direction along the curve z(x, y) = z(a, b) at point (a, b) as given by the value dy/dx, which is in fact the slope of tangent to the curve at point (a, b). It comes out to be -[∂z/∂x]/[∂z/∂y]. Now it is clear that if a new value of the function slightly greater than that at point (a, b) is considered, the set of all points in x-y plane for which the function has this value always, will correspond to a curve in close vicinity to the old curve. For a single valued function, these two equi-valued curves will never cut at any point. It is clear now that the maximum rate of change of function z = z(x, y) at point (a, b) will be in the direction perpendicular to the equi-valued curve through point (a, b). Note that for these two close equi-valued curves, value of dz is same for all points, thus to have dz/dr maximum, dr should be minimum. dr is minimum in perpendicular direction. The slope of this perpendicular direction is the slope of the normal to the curve z(x, y) = z(a, b) at point (a, b). It is [∂z/∂y]/[∂z/∂x], as slope of tangent is: -[∂z/∂x]/[∂z/∂y]. Now, the directional derivative in this perpendicular direction, which is obviously maximum of that in any direction, is calculated by substituting [∂z/∂y]/[∂z/∂x] for dy/dx in the expression for directional derivative. After certain simplification, it comes out to be as √[(∂z/∂x)2 + (∂z/∂y)2]. To tell the direction of maximum rate of change in terms of the unit-vector, we see that the slope tanθ for the direction is [∂z/∂y]/[∂z/∂x]. Thus the unit-vector in this θ direction, cosθ î + sinθ ĵ, evaluates to [[∂z/∂x]î + [∂z/∂y]ĵ]/ √[(∂z/∂x)2 + (∂z/∂y)2]. Finally, the vector giving the magnitude and direction for maximum rate of change of function z = z(x, y) at any general point (x, y) comes out to be [∂z/∂x]î + [∂z/∂y]ĵ. As a terminology, it is called gradient vector of scalar function z(x, y).
@education5862
@education5862 Жыл бұрын
thank you for the information
@fufaev-alexander
@fufaev-alexander Жыл бұрын
thank your for the comment
@248harish
@248harish Жыл бұрын
Short and to the point.
@fufaev-alexander
@fufaev-alexander Жыл бұрын
Thanks! Check out my other videos as well! :) Or my website: en.universaldenker.org
@roomiegupta6984
@roomiegupta6984 11 ай бұрын
Found helpful 🎉
@EdKolis
@EdKolis Жыл бұрын
I never thought I would understand partial derivatives. But now maybe I do.
@stevecloud4soft
@stevecloud4soft Жыл бұрын
If you could explain with some applications, it could be useful to understand need of these derivatives.
@nianyiwang
@nianyiwang Жыл бұрын
so, the only difference (by formal) is whether you keep the dy/dx (where top & bottom are different variables) terms?
@jafir6065
@jafir6065 Жыл бұрын
love it❣
@fufaev-alexander
@fufaev-alexander Жыл бұрын
Thank you for your positive feedback, Jafir!
@arkadipray1210
@arkadipray1210 Жыл бұрын
Thank you sir
@fufaev-alexander
@fufaev-alexander Жыл бұрын
Thank you too! And welcome to the World of Physics :)
@peyohumbert9896
@peyohumbert9896 15 күн бұрын
Hi, I have one question for you : Let us suppose that we have a function f(q,p) such that f(q,p) = (q+p)^N where N is a positive integer and p is a function of q such that p = 1-q. We can easly see that the function f is equal to one and df/dq = df/dp = 0. My question is, if we use the partial derivative del f/del p, we consider the two variable p and q independant so del f/ del p = N(p+q)^(N-1) which is equal to 1 if N>2. That is correct? Thank you.
@panzer2686
@panzer2686 Жыл бұрын
Thanks for the explanation. I was so confused, I had to go on a site to get help, and all the people there did was try to tell me I know nothing. Yeah no shit that's why I'm asking. Anyway thanks for the video it really helped.
@hopcfizl3671
@hopcfizl3671 Жыл бұрын
But if you do a total derivative of x in a circle, how in y dependent on x?
@donharrold1375
@donharrold1375 11 ай бұрын
Beautiful explanation.
@baok3791
@baok3791 6 ай бұрын
When you saw this d/dx [sin(xe^yzcosy)] You must consider it was Partials derivatives,.If you won't do that,you will see Mr incredible becoming uncanny.
@Hepad_
@Hepad_ Жыл бұрын
My man being a better teacher in 2 minutes than my analysis teacher in 2 months
@tomnoyb8301
@tomnoyb8301 Жыл бұрын
Yet, operators presuppose one or the other, regardless dependencies. Gradient, Divergence and Curl all presume partial derivatives and all must be modified when dependencies become muddled, such as inhomogeneous materials where material 'constants' vary with position; requiring tensor and tensor forms of GDC's. Therefore, it's a bit of a misnomer to say a-priori that a partial-derivative means y is not a function of x (to use the video's example); because the partial-operator depends entirely on the function, not the other way 'round. It's more accurate to say that at a problem's beginning, lack-of-interdependency is determined and partial-derivative notation is imposed throughout the forty next pages of derivation merely to remind the student of that initial assumption.
@user-bi9lh8mg6m
@user-bi9lh8mg6m 10 ай бұрын
Hmm i see
@niemandgefalltdas1471
@niemandgefalltdas1471 Жыл бұрын
This is merely a "special" case of the total derivative. For anyone keen to to know what total differentiability really means look up "total derivative" on Wikipedia, for example. This video does not grasp half of the definition of the total derivative. To describe in a few words what the difference is: A function is totally differentiable if there exists a linear map that approximates our function _on all dimensions of the domain_ (for the one dimensional case total and partial differentiability are the same, for higher dimensions that is generally not the case). a function is partial differentiable if you can find for each dimension of the domain of your function a linear approximation. If your function is partial differentiable in every direction (each single dimension, that means you find for every dimension/"variable" a one-dimensional linear approximation) AND all those partial derivatives are continous, THEN and only then your function is also totally differentiable.
@atrandom1438
@atrandom1438 Жыл бұрын
wow! nice video
@fufaev-alexander
@fufaev-alexander Жыл бұрын
thanks!
@cube7353
@cube7353 Жыл бұрын
Hey!! Great video! I am very new to calculus. Can you explain how y depends on x in complete derivative?
@yarenkaya7872
@yarenkaya7872 Жыл бұрын
It needs to be already given or inferred. To exemplify, if you're in a circle with radius r centered at origin, you know y = +/- sqrt(r^2-x^2). Then, you know dy/dx is 2x/sqrt(r-x^2).
@BIOLOGYWORM
@BIOLOGYWORM Жыл бұрын
❤ty
@yarenkaya7872
@yarenkaya7872 Жыл бұрын
@@BIOLOGYWORM You're welcome
@ismailmudhafar
@ismailmudhafar Жыл бұрын
u r king
@fufaev-alexander
@fufaev-alexander Жыл бұрын
Thank you, Ismail 🤓
@nicos1097
@nicos1097 Жыл бұрын
Very nice
@joaogabrielferes4347
@joaogabrielferes4347 Жыл бұрын
What's the value of d(dx)/dx ? Is the same of ∂(dx)/∂dx ?
@user-kg9dv3uv1j
@user-kg9dv3uv1j 10 ай бұрын
作為教學頻道傳遞錯誤的知識真的不行。 這部影片完全沒有解釋到什麼是全微分,而是拿方向微分來偷換概念。 討論全微分的時候,df/dx這個符號的x不應該被理解成x-y平面(定義域)的第一個變量,而應該是x-y平面(定義域)裡的一個向量。 留言區一大堆人被誤導,我很難過。 ========== As a knowledge popular channel, you should NOT spread misleading messages. This video has mentioned NO content of total derivative but directional derivative. For total derivative, you should not take the symbol "x" of "df/dx" as the first component of x-y plane (or the domain of f). Instead, it represents a VECTOR of x-y plane (or the domain of f). A lot of people have been misled. That's not cool.
@BalajiNadh
@BalajiNadh 11 күн бұрын
Sir how does it become 6x in differentation 0f a/ax*3x²
@emilianorosario5935
@emilianorosario5935 7 ай бұрын
Thank you for the video! Just to clarify, if ∂ is used to denote a derivative instead of "d" then is it safe to assume that a function definitely has more than one independent variable? Some of the problems I encounter in my Calculus 3 class make it difficult to tell if y is independent of x or if y is a function of x.
@CaffeineEnjoyer_
@CaffeineEnjoyer_ 7 ай бұрын
if it's ∂f/∂x then y is independet variable and if ∂f/∂y then x is independent
@thexavier666
@thexavier666 Жыл бұрын
Is there a limits equivalent for partial derivatives?
@melvinwarmpf1264
@melvinwarmpf1264 Жыл бұрын
Does this makes a difference in calculation?
@HelloWorld-bb1lm
@HelloWorld-bb1lm 11 ай бұрын
thanks
@fufaev-alexander
@fufaev-alexander 11 ай бұрын
You're welcome!
@mz00956
@mz00956 11 ай бұрын
I didn't know there are 2 xD we just used "d" and did partial xD
@TheBluePhoenix008
@TheBluePhoenix008 4 ай бұрын
That's really helpful!
@bscutajar
@bscutajar Жыл бұрын
If f(x,y) and y(x), then isn't f just a function of x only all along i.e. f(x)? I never understood this notation
@Niklback1
@Niklback1 Жыл бұрын
Fantastic
@BalajiNadh
@BalajiNadh 11 күн бұрын
Sir 49% helpful 😅
@TheGlassgubben
@TheGlassgubben Жыл бұрын
The symbol for partial differentiation is not a curved del, but a stylized cursive d.
@GrizonII
@GrizonII Жыл бұрын
There’s some overlap in names here. The upside down capital delta symbol ∇ is often called “del” (as well as “nabla” or apparently “atled”) but the cursive d symbol ∂ is also often called “del” (as well as other names. I’m not really sure why; I’m guessing maybe since it looks kind of like a lowercase delta δ but with part cut out? Even though it’s origins are more directly related to the Latin d).
@TheGlassgubben
@TheGlassgubben Жыл бұрын
@@GrizonII, you're right people often call it del, but in this video it was pretty much implied that it's not a d and that is entirely incorrect.
@drdca8263
@drdca8263 Жыл бұрын
I just call it “partial”
@mattias3668
@mattias3668 Жыл бұрын
No glassgubbenen, it's just a good old d (although, in this video it is written in italic (not cursive)) written how they were written before they became upright. The letter ð is just an old d with a bar. d's are still written that way in e.g. fraktur.
@TheGlassgubben
@TheGlassgubben Жыл бұрын
@@mattias3668, true. Ironically I knew that, but my lazy attempt at fact checking only consisted of reading Wikipedia and I wrote my comment accordingly. The moral of this story is that bad fact checking might be worse than no fact checking at all.
@kabandajamir9844
@kabandajamir9844 Жыл бұрын
So nice thanks
@fufaev-alexander
@fufaev-alexander Жыл бұрын
Thank you for the comment!
@IqbalHamid
@IqbalHamid 2 ай бұрын
So you would use one or the other but perhaps never both. And that is because partial derivatives apply to when x and y are independent inputs to f(x, y). This applies to 3D SURFACES! Total derivatives, on the other hand, apply when x and y DEPEND on each other. Therefore, a total derivative is applied to a linear curve traversing across the x-y plane. In such a situation, f(x,y) only has values along the curve, y(x) across the x-y plane. It is therefore, meaningless to talk about taking the total derivative df/dx, for example, for a 3D surface defined by f(x,y) because f potentially has values for all points on the x, y plane.. However, you can take the GRAD of a surface. This is a vector quantity giving you gradients along each of the axis. The gradient along the x axis provides the x component of the vector and the gradient of the surface along the y axis gives you the y component of the vector. Check out this video for a great insight: kzfaq.info/get/bejne/nNehkriDmeDMln0.htmlsi=uRu-WX3oXaa-u6Bd
@MrTomyCJ
@MrTomyCJ 11 ай бұрын
I don't like that the use of one symbology over another indicates whether Y is an expression that depends on X or not. It's needlessly confusing. It adds yet another thing that you just have to know beforehand, instead of just simply stating whether y depens on x or not.
@miikke0
@miikke0 11 ай бұрын
That's because a better way to teach and understand the difference, is that by taking a partial derivative, you intentionally hold all other variables fixed while you take the derivative. It can then be implied that the other variables must not depend on the variable one is taking the derivative with respect to (ie. what he has tried to explain). A better and more intuitive way to think about partial derivatives, is exactly what they are: they are the change in one variable, in the direction wherein all other variables are held constant. This therefore means that y could certainly depend on x, but in the direction such that y is held constant, dy(x)/dx = 0.
Differential Equations. All Basics for Physicists.
47:38
Physics by Alexander FufaeV
Рет қаралды 103 М.
But what is a partial differential equation?  | DE2
17:39
3Blue1Brown
Рет қаралды 2,5 МЛН
아이스크림으로 체감되는 요즘 물가
00:16
진영민yeongmin
Рет қаралды 23 МЛН
Tom & Jerry !! 😂😂
00:59
Tibo InShape
Рет қаралды 67 МЛН
I Can't Believe We Did This...
00:38
Stokes Twins
Рет қаралды 82 МЛН
I CAN’T BELIEVE I LOST 😱
00:46
Topper Guild
Рет қаралды 100 МЛН
So Why Do We Treat It That Way?
7:51
BriTheMathGuy
Рет қаралды 136 М.
Gauss Divergence Theorem. Get the DEEPEST Intuition.
7:53
Physics by Alexander FufaeV
Рет қаралды 313 М.
Gradients and Partial Derivatives
5:24
Physics Videos by Eugene Khutoryansky
Рет қаралды 584 М.
Суть матанализа, Глава 1
16:00
3Blue1Brown Русский
Рет қаралды 491 М.
Oxford Calculus: Partial Differentiation Explained with Examples
18:22
Tom Rocks Maths
Рет қаралды 285 М.
Bra-Ket Notation and How to Use It
11:54
Physics by Alexander FufaeV
Рет қаралды 64 М.
ALL of calculus 3 in 8 minutes.
8:10
gregorian calendar
Рет қаралды 1,1 МЛН
Partial Derivatives and the Gradient of a Function
10:57
Professor Dave Explains
Рет қаралды 191 М.
Lambert W Function
14:35
Prime Newtons
Рет қаралды 570 М.
아이스크림으로 체감되는 요즘 물가
00:16
진영민yeongmin
Рет қаралды 23 МЛН