Why don't you make a membership function for your account for donation?

@@mustafanaser9789 My videos will always remain free for everyone. But, if people want to donate, they can do so through my Patreon page at www.patreon.com/EugeneK Thanks.

Can you make some videos on EMT which can the subject a bit lucid...humble request 🙏🏻🙏🏻

I can't understand yet, sum of vector i and j to x, y axis also a vector in x,y plane, how that show z's change

Uyuyuy u hu it it usse usse usse fd fd F7YY for for fulfilled fulfilled FUGLLLLLLLCU FUGLLLLLLLCU FUGLLLLLLLCU fdfd fd fd fd fd fd fd fd fd fd clg clg clg clg clg clg clg ch fd fd fff fff fff fff fff fff fff clg clg clg clg clg clg clg clg clg clg clg fff fff fff fff fff fff fff fff fff fff fff fff fff fff fff fff cu

Glad you liked my explanation. Thanks.

The quality of explanation is always functions of time and technology.

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+Cow Norris, thanks. I am glad you liked my video, and the choice of music.

Physics Videos by Eugene Khutoryansky but it's always the Hungarian rhapsody with you.

Great videos Eugene. I would be interested in adapting them to Economics. What is the software you use to design the animations?

Philip, I make my 3D animations with "Poser."

Amazing videos.. That were what i was searching for..

+AlphaOmega, thanks for the compliment. Though, I am fairly confident that I will always still be doing all my own animations.

+Physics Videos by Eugene Khutoryansky Nice to see some visualization :D. About 65 % of people are visual learners

+Musa Yusuf By "Khan Academy status" I was referring to popularity and success. Eugene's videos are clearly of superior quality but also fundamentally very different from Khan Academy videos.

@@EugeneKhutoryansky I would like to do animations for my expertise field, I wonder which tool do you use to make those amazing graphics??

@@jhalvico he uses Poser, it's an animation software for Mac.

I am glad my videos ahe helpful. Thanks.

+Kiran Adhikari, thanks. I have always believed that having this type of intuition is more important than memorizing the equations.

+Physics Videos by Eugene Khutoryansky Absolutely. It also makes you more able to apply it to real problems because you know what's being the equations.

@@EugeneKhutoryansky ; wow. what a great philosophy. I really hope that this will be the future. Teaching and learning would then be full of fun for everyone :)

I am glad my video was helpful. Thanks.

Thanks for the compliment.

Hahah I could relate,mine started form 3D modeling 💀💀

Thanks. Glad to hear that you found my video useful and that you liked it.

What animation software do you use? Very nice

+Chike Ezebilo, I use "Poser" to make all my 3D graphics. And thanks for the compliment.

Thanks man

The only things that I really dislike about these videos are the Fundamental Missing Pieces in the explanations, which I notice at almost every video. For example, here the it does not explain why gradient indicates the direction for which the function increases by the largest amount. Missing explanations like that diminish the value of this channel by the largest amount. If you fill the "explanation gaps" a little further, I believe your channel would be one of the very best.

Your videos are just amazingly helpful. Best visualization. Best channel

Thanks for the compliment about my video.

where shall I find much more information about gradient?

Added subtitle in Turkish. Thanks for this great video!

I can't believe I didn't even know the basics what use was my education from 10th grade to uni I didn't even know the basics thanks for explaining everything so clearly

I am glad my video was helpful. Thanks.

+Dyuman Bhattacharya, thanks for that really great compliment. Lots more videos are on their way.

Thanks for the compliment about my explanation. More videos are on their way.

+Nessim, glad you liked it. Thanks.

Glad to hear that my video is helpful. Thanks.

Glad you liked my explanation. Thanks.

+Ahnaf Abdullah, thanks for the compliments. I am glad that you liked my videos, and I am glad to hear that I have helped inspire your pursuit of science.

Thanks.

I am glad to have you as a subscriber. Thanks.

Thanks. More videos are on their way.

Glad my video was helpful. Thanks.

Haha even I saw because of that only😅😂..

@@ganaa24 yo!!!! That's Good😆👍👍

I also came here after Aanand sir video on electric potential😀

@@dilrajrai7922 NICE...ITS BEEN A YEAR NOW..LOL...ALL THE BEST BUDDY

@@parthjoshi536 your comment is showing on top so i replied. All the best to you too🙂

+Alexandru Gheorghe at every point there is a vector that points in the direction of greatest increase (with the length denoting how much that increase is). So instead of the colors, you could imagine all of the arrows everywhere but sometimes that might be more difficult to do/read from. Try googling 'gradient field' and looking through the images. You can find some examples of what I'm talking about. I hope this helps!

You turn the magnitude of each partial derivatives of z with respect to x or y into vectors, then add the vectors. The magnitude is the slope (the derivative), and the direction is negative or positive depending on the slope. I got confused thinking about how you would add negative or positive vectors if the slopes were different signs, but in smooth functions, there is a gradual change, and if the function is all in the quadrant were x and y are positive, then only the change in z will be positive or negative. So this is easy to visualize. The gradient is just the vector sum of the partial derivatives, and this gradient vector points in the direction the combined maximum amount of change. The hypotenuse of the triangle. The colors in the video graphs only represent if the change in z is positive or negative with respect to x or y.

Partial derivatives indicate the slope ( of z w.r.t y ) with x kept as a constant at some particular point . Now , how are we sure that the slope is maximum at that point ? Because , to construct the direction of the del operator, we need maximum change of z w.r.t y and not just any change... So , if dz/dy (x contstant) indicates the slope w.r.t y at some point and similarly dz/dx (y con) indicates the slope w.r.t x at the same point , then , does the gradient indicate the maximum change of z still , or should we choose that point at which the slope (of z w.r.t x and y ) are maximum ?

@@abhishekkj3662 I too have this confusion and I thought someone would have answered you in these years. Miller told almost the answer usually written in books but with a caution that one can conceive a function for which gradient may not point in the direction of maximum rate of change (and poor me, I cannot either conceive such function 🤣), but I am still searching these videos and comments for the same answer. One guy above who proved mathematically seems quite good and hope he answer from intuitive point of view.

+StarFury2, Thanks for the compliment.

Thanks. I am glad you liked my video.

Now compare this ratio with all the other videos and find the derivative of the ratio of likes in terms of time.

Thanks. Glad you liked my video.

Thanks.

Glad my video was helpful. Thanks.

Thanks for the compliment and I am glad my video was helpful.

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Thanks.

Thanks for the compliment. I am glad you like my videos.

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Glad to hear my video was helpful. Thanks.

+12sandy345, thanks. I am glad that you liked my video.

kzfaq.info/get/bejne/jrd5ldFjnMqzmnk.html 💐

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Thanks for the compliments.

Thanks for the compliment. I am glad that you liked my video that much.

Thanks for the compliments.

Thanks for the compliment.

Thanks.

Glad to hear that.

Thanks for the compliment about my graphical way of presenting these topics in my videos.

+Mark G, I am glad that you like my explanation, and my graphics. Thanks.

Thanks for the compliment and I am glad that my videos have made a difference. More videos are on their way.

Thanks for the compliment. I am glad you liked my explanation.

Thanks.

I am glad my video was helpful and thanks for the compliment.

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Thanks. I am glad you liked my video.

+colorado wilderness, thanks.

Thanks.

Thanks for the compliment about my explanation.

Thanks.

Thanks for the compliment.

Thanks.

More videos are on their way. Thanks.

Thanks.

Thanks. Glad to hear that,

I am glad that my visualization was helpful. Thanks.

Thanks.

+SHIFTKICK, thanks for the compliment about my graphics.

Thanks. I am glad you liked my video.

Thanks for the compliment and I am glad to have you as a subscriber.

I am glad you liked my video.

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Thanks.