Dimensional Analysis in Detail

Dimensional Analysis in Detail | Physics

Рет қаралды 6,784

Күн бұрын

This video covers Dimensional Analysis in more detail including how to derive equations and check equations that you have transposed. I also run through 2 problems at the end of the video to cement these ideas.
📺 MORE ON DIMENSIONAL ANALYSIS - • Dimensional Analysis |...
📄 Practise Exam Questions 👉 • Dimensional Analysis: ...
TIMESTAMPS:
00:00 What's dimensional analysis for?
00:48 Checking transposed equations with Dimensional Analysis
06:56 Deriving new equations with Dimensional Analysis
17:41 Problem 1
22:08 Problem 2
#physics #physicslearning #dimensionalanalysis #highschoolphysics #collegephysics

Пікірлер: 22

@PhysicsTutoringHub 5 ай бұрын

If you want a quicker overview of Dimensional Analysis, I have a 5 minute video here 👉 kzfaq.info/get/bejne/Y5p3Y6yTlrC6gas.html 📄 And Practise Exam Questions 👉 kzfaq.info/get/bejne/fLV5eJqbxp-aXYE.html

@aslanglimpse- 9 ай бұрын

Thank so much sir it is definitely beautiful explanation

@PhysicsTutoringHub 9 ай бұрын

That's really kind of you Aslan. I'm glad it has helped you ☺

@alhamdulilah6892 9 ай бұрын

Thanks man, very well explained 💯

@PhysicsTutoringHub 9 ай бұрын

Brilliant, I'm really glad it's helped ☺

@heytherehi7674 8 ай бұрын

Thank you so muchhh

@PhysicsTutoringHub 8 ай бұрын

You're welcome. I'm glad it's helped ☺

@naren5312 13 күн бұрын

Hi sir at 15:48 when we square both sides we would end up with t^2 = R^2 ( h/g)

@PhysicsTutoringHub 13 күн бұрын

Hi Naren yes you're right, I made a mistake there.The point I was trying to make here, though, was that this dimensional analysis was able to help us come up with one of the equations of kinematics. The constant at this point is an unknown value which we can only obtain through experimental data or geometric reasoning. So, K here is really just a placeholder for an unknown non-dimensional value. Hope this helps.

@adityanshuraj2963 2 ай бұрын

Sir, let there be a physical quantity X raised to the power of another physical quantity Y. In this case my teacher taught me that Y being a number is dimensionless quantity which i aggre with but also he said X is dimensionless for which he doesn't has any explanation...Plz sole my doubt . Is he right?

@user-lg8dl4bm5q 2 ай бұрын

sorry sir ,if i may ask ,how did we drop r and p from being endices whilst our bases are not the same?

@PhysicsTutoringHub 2 ай бұрын

@10:18 we isolated the bases on both sides of the equation. On the left hand side we have L^0 and on the right hand side we have L^p * L^r. When we multiply indices (exponents) with the same base, the indices add together. So, we get: L^0 = L^(p+r) Because we can treat the base L like an algebraic quantity, we can cancel the L on both sides of the eqn, leaving us with: 0 = p + r

@lost_cloud_0_ 28 күн бұрын

Thank you soo much for this, this really helped allloooooottttttt ❤❤❤❤ You just gained a new subscriber (ﾟ▽＾*)☆

@PhysicsTutoringHub 28 күн бұрын

I'm really glad it has helped 😁- Brilliant. Take care.

@SyethembaMyeni 4 ай бұрын

The video is helpful thank you but i need more assistance, can i email you ?

@PhysicsTutoringHub 4 ай бұрын

I'm not providing a one-on-one tuition service at the moment. But, you can post questions here in the comments and I'll try and answer them as best as I can.

@SyethembaMyeni 4 ай бұрын

V^2 = Vo + 2b( X - Xo). Here , they want me to find the dimensions of b V^n=ka^iX here, they want me to find number n and I would be to make equation dimensional correct

@PhysicsTutoringHub 4 ай бұрын

If this is a homework question, I can't just give you the answer, But, to answer these questions you need to make sure what these variables represent: V and Vo are velocities, X and Xo are distances. and this equation above is a 1D kinematics eqn. and the Vo should be raised to power of 2 -- V^2 = Vo^2 + 2b( X - Xo). You need to convert these variables into dimension of Length or Time (i.e. Velocity is L/T) and there must be the same dimensions on both side of the equal sign. You're asked to find b, so rearrange the eqn to make b the subject and convert all the known variables into their corresponding dimensions. Remember these dimansions can also be manipulated like normal algebraic expressions. Goodluck with your homework 😁 @@SyethembaMyeni

@SyethembaMyeni 4 ай бұрын

@@PhysicsTutoringHub thank you sir I really appreciate it. But it wasn't a homework I just came across with it when I was studying. Thanks a lot

@SyethembaMyeni 4 ай бұрын

Sir I think it would be a good idea if you can open a live class where we will be able to ask questions based on that topic