I took physics 2 in my second semester, but last semester, the third semester, when I started to be a physics tutor, I almost forgot all I learned before! I'm physics major. This semester I'm a mentor of physics 1 and tutor as well, I really need something like this that combines all the concepts just by one shot to refresh! Thank you very much!

Ahhh finally I found you... thank you 😊 very much, you saved me.

Thanks. You helped me with a quiz I had to do

Great video thanks!

How to find induced EMF in a circular coil moving with velocity v=5m/s in a uniform magnetic field of B tesla. The field region is rectangular extended to length 10m and and the radius of coil is 2m.

the magnetic force is upward by using left-hand rule (3:09). Or if not can you explain "why"?

awesome video

Liked the explanation

Super Helpful!!

6:29 how does the formula for the Force F_B change if instead of a square loop, we had a rectangle , lets say the bottom and top where twice the size of the 2 sides.How hould that change the formulas?

What if it's moving with a constant acceleration?

3:09 the direction of force on electrons is upward Isn't it?

Professor, could you help me? I think that the answer of this question is zero, is it correct? Two metal rectangular conducting spires, named a and b move at constant speeds to a region where there is an uniform magnetic field B pointing out of the page, orthogonal to the spires. Use Faraday’s law to show how the electromotive force in the spires a and b relate to each other when their whole areas are immersed inside the magnetic field B. Consider that the spire areas (Aa and Ab) are such that Ab = Aa/2. Thank you a lot you teach very well and your english is easy to understand! Congratulations!!

Thank you!

What if the coil is circular ? I got (2*pi*v*L*(N^2)*(B^2))/R If it was circular.

Excellent. Video. BETTER THAN MY BOOK

Nice explanation

What if I am asked to find the terminal velocity for that loop of mass m allowed to fall under the action of gravity leaving the magnetic field?

Dr, consider you have this square loop stationary on the horizontal xy plane same as this example, then you brought a bar magnet with the south side closer to the loop, letting the bar magnet pass by the loop along the +x axis, will there be induced current in the loop, if so, can you help it out with solution showing B vectors and any other details we need to know that there will be induced emf or not. Most teachers are saying there is no emf but am not convinced. Appreciate it

According to my textbook, "if the bar has some resistance , this resistance is like the internal resistance of any other kind of battery, and V=vBL-R(internal)I". If this is the case, why isn't the current I=V/R=(vBL-RI)/R => I=vBL/2R ?

What if this loop was on the top of the magnetic field? What emf and current would that produce? I.e. the square is halfway outside of the magnetic field on the top, and has a velocity to the right

3:28 How do you know the Force is downwards? Is it because the Magnetic field points into the screen?

Awesome

Actually the question is.. " A square loop of side a is so placed that its top side is in a uniform horizontal magnetic field B normar to the plane of the loop and the lower side is outside the field and horizontal. The resistance of the loop is R and mass is M ...then what is the terminal velocity if the loop is allowed to fall under the action of gravity?

Well here is a physics question how did the loop move inside the 'x' field region did you push it ?

Thanks for the video. However, nobody explains why we only need to look at the flux, meaning the field inside the loop. Even if the loop is not inside the field, the magnetic field produces an electric field in the loop. or not? And even when we're the field-region, why are we only looking at the field inside the loop? --> Please don't answer with "because of Faraday induction" or "because of Lenz's rule". I know those rules. I want to understand the physics and how to see that the electric fields created by the magnetic field lines outside the loops aren't relevant.

really superb

Bro, your handwritten phi and zero look identical. This has never caused an issue for you before?

I have just built a table top demonstrator? I can change the 2 pole magnet:- I can also change the coil configuration etc. Who can I sell this clever bit of kit too ????

how much is work done to take in magnetic field

Ok thank you

Faraday’s law is very general and any change in magnetic flux, whether due to a change in magnetic field or, a change in area, produces an emf equal to the rate of change of flux. In fact, both may be present simultaneously, as when you drag a metal bar along metal rails with one end of the rails bridged by a resistor and there is a uniform magnetic field in the area between the rails and bar and resistor. Assume, the magnitude of the uniform magnetic field is increasing. The flux is BA, where B is the magnetic field and A the area enclosing it, and the rate of change of the flux is due in part to the change in the magnetic field, and in part to the change in the area enclosed by the changing path. The resistor will heat up! The equation of the rate of change of flux....without the details of the derivation are = (dB/dt) A + BLv (Change of B, fixed path) (Change of path) The calculation is a bit mysterious. Physically, where did the emf represented by BLv come from if it is not associated with a changing magnetic field? Befire we provide an answer, it would be instructive to understand Current, the conduction process and Voltage at the fundamental level. Electrostatics and circuits belong to one science not two as in the following two videos: i. kzfaq.info/get/bejne/iKujiseVnJzVqJc.html and ii. kzfaq.info/get/bejne/bqiBgMKp3Ji2lqM.html Now, returning to the experiment of the moving bar on rails, we see that we have a conducting metal bar and we are moving it. Note carefully that we are moving the jumpy energetic conduction band electrons in it as well. As a result of the magnetic force (due to the presence of the uniform magnetic field), the free electron sea shifted, and the bar polarized and a Coulomb electric field develops and that is how an induced emf is produced. It is not possible in this post to discuss in more detail the process of polarization and the consequent production of an emf. The last frame References in video #1 lists textbooks 3 and 4 which discuss these topics in more detail using a unified approach and provide an intuitive understanding of the generation of an emf in generators and motors.

15:51

thanks adam sandler

Kindly...u didnt explain well the direction of the magnetic force