Error Propagation
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Күн бұрын
@katmudak 4 жыл бұрын
Thank you. You are the only one who explain error propagation the way my lecturer wants in exams.
@yujingzou1826 3 жыл бұрын
the beginning is like how uncertainty propagates
@attilioc238 3 жыл бұрын
You are a life saver, thanks!
@sisundal3317 3 жыл бұрын
My life saver
@JMissEscobedo Жыл бұрын
I'm not understanding how you got e^-1 when you took the partial with respect to x of e^-y... wouldn't the partial of e^-y with respect to x be 0?
@dajaco81 11 ай бұрын
We took the partial derivative of xe^-y with respect to x. Therefore, we treat e^-y as a constant multiple of x resulting in just e^-y after differentiating (like how 2x differentiates to 2). Then we substituted the values x=20 and y=1 resulting in dq/dx = e^-1 = 0.3679 at the point of interest.
@aqsaamin96 6 ай бұрын
Why did you divide it by 1/3 after you calculated delta q in the first example calculation? Is it because you are adding three quantities to calculate the average?
@aqsaamin96 6 ай бұрын
Should we always divide the uncertainty after squaring and rooting it with the number of quantities involved?
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