Resonant coupling - Transformer Impedance matching (2/3)

  Рет қаралды 6,959

FesZ Electronics

FesZ Electronics

2 жыл бұрын

#150 In this video I look at how transformers can be used to interconnect circuits of same or different impedances, by looking at what can be done when the coupling factor is non ideal. So even though in real life you can't have perfect coupling, there is a big difference in-between an almost ideal coupling and a proper weak coupling.
Related topics:
Resistive matching: • Electronics tutorial -...
Lossless matching part 1: • Lossless Impedance Mat...
Lossless matching part 2: • Lossless Impedance Mat...
Transformer matching part1: • Wideband coupling - Tr...
Transformer matching part2: • Resonant coupling - Tr...
Transformer matching part3: • Coupling experiments -...
Current probes: • About Current Probes a...
Further reading and documentation:
slideplayer.com/slide/15025380/
sietkece.com/wp-content/upload...
en.wikipedia.org/wiki/Double-....
Special Thanks to all my supporters on Patreon! Especially @afiskon, Ralf B., Paul Pr. Richard and Jonathan Alvarado!
If you liked this video be sure to check out my other videos and you can also subscribe to be up to date with all the new ones!
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Пікірлер: 21
@alfonsea3bfl869
@alfonsea3bfl869 2 жыл бұрын
Just another beautiful Sunday, a cup of coffee and a Fesz vid.
@avijitbanik531
@avijitbanik531 2 жыл бұрын
Awesome educational material for theory and practical. My friend also likes this so much. 🙂
@curtstacy779
@curtstacy779 2 жыл бұрын
Thanks Fesz! just what I need.
@AndreasSpiess
@AndreasSpiess 2 жыл бұрын
Perfect presentation! Congratulations for your channel. Are you (already) a HAM Radio operator?
@FesZElectronics
@FesZElectronics 2 жыл бұрын
Thank you for the kind words! Honestly, I've never gotten a Radio license since I am more interested in the electronics behind it rather than actually transmitting and receiving; but who knows, maybe in the future.
@AndreasSpiess
@AndreasSpiess 2 жыл бұрын
@@FesZElectronics A lot of us also are experimenters. Just with the possibility to test what we build (legally)
@FesZElectronics
@FesZElectronics 2 жыл бұрын
@@AndreasSpiess I guess this is relative. Half of being a HAM operator is receiving signals, and there is no legal requirement there from what I know; but the same principles of emission/filtration/signal processing can be used in multiple other areas of electronics - particularly in handling EMC compliance - its quite the opposite of being an radio operator, there you want to make the worst possible antenna :D
@ashishderhgawen
@ashishderhgawen 8 ай бұрын
Great video
@--JYM-Rescuing-SS-Minnow
@--JYM-Rescuing-SS-Minnow 2 жыл бұрын
YUP! this is so important! even though com-chip companies, R making chips now. that process a huge combination of com error's. I believe this is the best way 2 go!! get it right the first time. no need for an error chip!! great tutorial !! U layout electronics with skill !!
@BIGRIP87
@BIGRIP87 2 жыл бұрын
thanks 👍👍 this is really interesting.
@thomassorensen7907
@thomassorensen7907 2 жыл бұрын
Hi In 10:54 and onward you show two equations in the lower left corner calculating the resonance frequency. How are these derived? Any paper/text/website you can refer too? Thank you for some very nice videos.
@FesZElectronics
@FesZElectronics 2 жыл бұрын
Its the generic formula for the resonance frequency of any LC circuit; I'm not sure if there is any special paper on it; but you can derive it by finding the frequency solution for Xc=XL (Xc=1/(2pi*f*C) (XL=2pi*f*L)
@thomassorensen7907
@thomassorensen7907 2 жыл бұрын
@@FesZElectronics Thank you for the answer. I think I was not specific enough. It was more how the couplings factor appear in the resonant equation. So we can see in one case the change in coupling does nothing for the resonant frequency and in the other it changes due to (1-k) factor.
@FesZElectronics
@FesZElectronics 2 жыл бұрын
I will be honest, for the parallel resonance, that is the formula I could find (like in the documentation links in the description) - I guess that with or without coupling, you are resonating with the entire inductor (or the magnetizing inductance which is fixed); for the series resonance, I don't remember finding the formula, but rather I saw what fit to the simulation results. The "L(1-k^2)" term represents the uncoupled inductance of the transformer (the one with which you are resonating away using the capacitor).
@thomassorensen7907
@thomassorensen7907 2 жыл бұрын
Hi How can we intuitively explain that we can get the same output power for k=1 and k=0.1, with for example series resonant coupling? I could maybe understand if the efficiency went down and the k=0.1 case used more input power.
@FesZElectronics
@FesZElectronics 2 жыл бұрын
Hello! Well, the equivalent model of a transformer with less than ideal coupling can be built with an ideal transformer (that contains the coupled inductance) and a series inductor (with the uncoupled part); with resonance, you are canceling out the uncoupled inductance, hence you are left with the ideal bit only.
@stevenbennett6123
@stevenbennett6123 2 жыл бұрын
Excellent! How do you display the µ symbol in LT Spice, I can only add a u ? Thanks
@FesZElectronics
@FesZElectronics 2 жыл бұрын
On my side, when I add, "u", after I close the parameter edit window, it automatically changes to "µ"; does it stay as "u" on your side?
@stevenbennett6123
@stevenbennett6123 2 жыл бұрын
@@FesZElectronics Yes it does stay as a u, there must be something different between our machines, but presumably not an LT Spice issue? However I discovered that typing ALT + 230 inserts a Mu character, µ as I just did here, maybe you have set up some automatic u to µ conversion in Windows?
@troy6882
@troy6882 2 жыл бұрын
Try light.????we use a 555 set with that flyback resistor, led and director but when in curcit the director stops the curcit and gives a relay curcit cut but a resistor led the curcit runs perfect the issue is due to a IR and the stable factor there! As if you remove the led gose crazy????.😁may help stable those peck's.
@y_x2
@y_x2 3 ай бұрын
A bit of confusion with all these lines on the same graph.
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