wow ... that moment when you realize that a 13 mins vidoe is 1000 times better than a 2 hours long lecture at the university. thank you so much Phil keep it up!

Mate you are a legend. Very well explained. Thank you so much.

Thank you so much Phil! I am enrolled in an intro course to Geotech right now and my professor goes way too fast when explaining concepts. Your explanation is spot on and clear. Thank you for sharing!

It is the circles, guys. You have to have 4 tangent lines surrounding a circle. 1. You start with the equipotential lines at the ground level and impermeable layer 2. Then you draw flow lines than are parabolas that end perpendicular to the ground equipotential line. You can make how many you feel is right. (The fewer lines the bigger the circles you'll imagine later are going to be, the more lines, the more circles you'll have to draw but it'll be more accurate) 3. (The most difficult part.)Draw parabolic equipotential lines that are (1) perpendicular to all flow lines they cross and (2) a circle can be drawn in the resulting inner area that all sides touch the surrounding lines at one point (tangent lines to the circles) 4. Count-out flow channels and drops. I'm just a student btw, this just what I got from the video.

Thanks from India... Very helpful... Demonstration

Thank you from Saudi Arabia

Thanks a lot , you saved a lot of time of us . We appreciate it!

Thank you Phil..... Lots of love for you .....

Much love from RIPOSE LECTURES

Im having a hard time concentrating on your lecture wondering how you wrote it backwards and explain it at the same time 😅😅.. That's just wowwwwwww👍👍👍👍👍👍

Are you writing backwards?? My mind is blown!

Thank you man, much appreciated from Kenya. (student)

Good explanation sir👍👍

you're great, i could easily grab this topic onto my head

Thank alot for sharing about soil mechanics

Massive help, thanks!

thank you sir for clearing our concept

An example of unconfined flow with a sheet pile driven halfway into an aquifer is shown in Fig. 7.19(which is same is the figure you have drawn.). The flow net is horizontally symmetrical, providing that the top and bottom flow lines (borders) are parallel and the penetration of the sheet pile is exactly one-half the depth of the aquifer. Note that the number of flow channels Nf is 3 and the number of equipotential drops N dis 6. Regardless of how many flow channels you use, the Nf!Nd ratio, or the shape factor, will always be 1/2 for the geometry of this example! any comment on this?

Thank you so much for clear explanation.

Beside of anisotropic condition can flow net change due to other reasons like head, permeability etc

Step by step video solutions of civil engineering questions

Thank you

Thanks from Bangladesh

You are awesome!

It is actually 12,622.78 liters per year sir. That 35 liters is per day.

Thanks.

I often see values of 5.6,6.5,4.5, etc. when calculating Nf. How on earth is this possible if calculating the #of flow paths? Shouldn't this always be a whole number? Or does this only apply to anisthropic materials?

Phil how do you know how many flow lines and equipotential lines you need? I've read everywhere and no one gives me a straight answer or an equation to follow. Thank you!

thanks

Question sir. How do you find the pore pressure of a certain point if it is located at the very center of equipotential line? We know that pore pressure = 9.81(H + h - mH/nd) Where H = head of water h = height of saturated soil above the point of interest m = number of equipotential drops from zero to point of interest nd = total number of equipotential drops. So how would you know the value of "m" in that case?

Thank you I love you

tq 🙏

thanks, this helped me :)

cool

Yo, isn't the differernce between the 2 hights 7m, on the diagram.

How does he write upside down?

Thank you so much this helped a lot

Wouldn't (4x10^-7 m^3/s) = (0.03456 m^3/day) = (12.61m^3/yr) = (12,600 L/yr) ? I think the value you calculated was the daily value and not the yearly. Although it seems like too large a value

Very helpful video. I have a question about the units. I realize that flow is expressed in volume per time, but if K is in (m/s), and H is in (m), should Q be in (m2/s)?

pls consider wearing dark shaded shirt

thank you :D

Thanks! I'd say that it would be better if you wore dark clothes so that we could see the light lines and words on the board

The result should be 35 liters per day not per year

Hi I i thought H was 8m -1m??

should't the H be 7 m instead of 1

Nice video, thanks sir!