For those who wonder how R4C4 is not a 2, here is how i found it out. If you advanced enough in the puzzle you know there is a 2 in R6C3 and there is a virtual 24 pair in C9. Therefore if ou check box 6 you will see that 2 can you be in either C7 or C8, no matter where it is it will be in box 9 in only row 8 and 9. We also know that 2 can also only be in row 8 and 9 in box 7 from previous deductions. This means that the 24 cell in R7C4 can only be a 2 and therefore the 2 cannot be in R4C4 and has to be in R5C6.

YES! I was so worried that Fog of War was over with the new series, even though there was no reason to think this

Solving Hint : color 2-4 pairs and 3-5 pairs and then note how they relate when adding up to 7 in rows 1 & 9 and column 4. This eliminates a lot of candidates and makes a lot of 6-7-8 triples around the grid.

this was one of my favourite FOW so far, really cool.

IS 2 not also an option for r4c4? at kzfaq.info/get/bejne/mMedd7qF39GYj6M.html

At 4:41, how do you rule out a 2? My solve path there was to fill the sums in R8 and R9, allowing me to fill R7, and then from the dot, placing a 7 in R7C2. I finally got the 2 when you were at 9:50.

39 min solve, enjoyed that!

At about minute 5 how did you discount the 14-sum being a 2+5+7? Rather handy the way it gave you your second digit, a 2, out of seemingly nowhere.

43 for me and happy with that.

I don't understand the placing of the two 3-5 pairs at 14:12. That seems to come out of nowhere.

49:42 but I got to a point where I couldn't disambiguate. Had to make a wild guess on a 2/4

How did you get the 1-9 r2c7 at 1:05? I can't work out why it could be a 6 in column 9

i'm amazed i solved this.... 90 mins though