Were you solving bartleby

Yep that way he finds the equilibrium point solving for F. If the applied F is just slightly greater then the tire will climb up

Good question. I will get back to you on this one.

@@PhysicsNinja Thank you so much sir for acknowledging the comment. I kinda got the answer on a stack exchange question though. physics.stackexchange.com/questions/338644/sphere-rolling-up-a-step What I gathered from the above was that we need to conserve the angular momentum about the pt of contact...and the kinetic energy just after collision (which would be purely rotational, assuming the object never leaves contact with the curb) would provide the necessary increase in the gravitational potential energy i.e. mgh This would lead to 2 equations which can then be solved with not much difficulty Is that the right approach? Thanks in advance sir

not possible for a horizontal force. The force would need to have a vertical component.

@@PhysicsNinja thank you very much for this, I appreciate it alot. I hope it was not a silly question, I just noticed that the formula for part 2 seemed to allow for h>=R whereas part 1 didn't

Dude youve been given the tools to work that out

Determine what your max force is (100N?) then make the radius your variable.

If you then wanted to find how fast it goes up ( the angular acceleration) then you would need to know the moment if intertidal of the wheel. Sum of the torques = I*alpha

@@PhysicsNinja Thank you sir. It was really helpful

Not sure i understand your question. Why wouldn't they be concurrent?

@@PhysicsNinja sir if at the point when the wheel is on the crub the reaction R will be having two components right?? One radial component and one tangential component so when the surfaces are smooth which component can balance this tangential component??

@@PhysicsNinja i am asking like is there any proof stating that the forces are concurrent at the point

@@varshavarsha5790 You can calculate the components of reaction forces as a function of the applied force and the weight of the wheel. I've never done this but it should have both components. You'll probably find that one of the components (or both) will vanish is some limiting cases. I think in the limit where F=0 the reaction force should also be equal to 0 and when the wheels starts to lift (N=0) the reaction force should only have a horizontal component. Hope this helps.

@@PhysicsNinja yeah sir I could get you but what force could balance the component which the R has with applied force?? Or please correct me if I am going wrong in my understanding

Yes no problem

Ana Lucia Benavente Luna the contact force is 0 only if the height of the step is 0 - no step. The normal force is 0 because the wheel will just begin to lift.

Thank you :)

Just substitute values

@@jeromecancino5261 NO KIDDING !!!

Multiply that by 9.81 so you will find weight.

@@jeromecancino5261 Either I don't know what you'r talking about, or you don't know what I am talking about!!!! I meant to ask him to calculate the amount of Kilogram-Force needed to pull a 30kg wheel up the step!!!

Sure but that’s where the pivot is so no torque

Kaan Apan you’re welcome!

Physics Ninja I didnt want to offend you but it is way too long i looked for this kind of problems but you explained whole topic man. Maybe shorten this videos and make another one for entire topic

Wow

@@PhysicsNinja Well I appreciate the extra explanation even if I am familiar with the topic already. Also if he/she is so good at physics why'd he/she need a video?

@@kaanapan1183 If you didn't know any better... you're basically telling us you're too stupid to understand the video. lol Asking him to make it simpler is like asking him to change the law of physic. This is pretty simple as you're gonna get. Bet you weren't expecting to see this old comment, huh? Fool.

Thanks for watching. My channel is about helping students set up problems and apply basic physics to solve problems. Many of the problems i present are 100's of years old, including this one. I try to put my own spin on it and present it in a way that is easy to understand. I often get to a final equation and don't plug and chug number into the problem. Instead i try to take limiting cases to make sure the results makes sense. Putting numbers into a final equation to get another number is less educational, even a child can do that.

@@PhysicsNinja I suggest you try it once for each video, else, people may thing you do NOT know what you are talking about, but that you are just copying texts of others!!! Only when you utilize numbers, you'd be able to see how close your approach is to reality. For instance, a much acclaimed online-physics-professor (Von Bizen) comes up with rocket-launch-acceleration of, something like 2m/s/s, which is impossible for a rocket to lift off earth!!! Worse yet, a TWR==1.2, because he believes, as you probably do, that a TWR>1 would lift any rocket off the earth!!!!

@@PhysicsNinja More clarification::: Assume you are pulling up a 30kg wheel up the stair; you plug in your numbers and come up with a required force of over 30kg-force to pull up the wheel. Only then you'd know that your formulation is wrong somewhere, and the you could try to fix the mistake; else, students may continue finding that forces above the actual wheel-weight, which makes no sense at all, because the whole physics behind using wheels is to reduce the amount of force needed to carry the load, on a flat surface, or up slopes, or up the stair!!!

wow, I sometimes forget how psychotic ppl on the internet can be

dude is being just straight-up lazy and ignorant...

Bartleby