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Пікірлер: 34
@NadiehFan24 күн бұрын
A different approach which does not require a substitution and which does not require having to deal with fractions starts by multiplying both sides by (x − 3)² to get rid of the fraction. We can then proceed as follows x²(x − 3)² + 9x² = 16(x − 3)² x²(x² − 6x + 9) + 9x² = 16(x − 3)² x²(x² − 6x + 18) = 16(x − 3)² (x² − 3(x − 3) + 3(x − 3))(x² − 3(x − 3) − 3(x − 3)) = 16(x − 3)² (x² − 3x + 9)² − 9(x − 3)² = 16(x − 3)² (x² − 3x + 9)² − 25(x − 3)² = 0 (x² − 3x + 9 + 5(x − 3))(x² − 3x + 9 − 5(x − 3)) = 0 (x² + 2x − 6)(x² − 8x + 24) = 0 x = −1 + √7 ⋁ x = −1 − √7 ⋁ x = 4 + 2i√2 ⋁ x = 4 − 2i√2
@laurentbeyer245823 күн бұрын
I would have done same 👍🏻
@TapanDas-ei3lw16 күн бұрын
You're also a great genius ❤❤❤
@michaelhuppertz673827 күн бұрын
Nice solution specially how got the (x-3) out of 6x^3+18x^2, neat trick.
@ajmiller710219 күн бұрын
Excellent. Straight to the solutions. Well done!
@NadiehFan23 күн бұрын
Yet another method is to note that (x − 3)² = x² − 6x + 9 and therefore x² = (x − 3)² + 6x − 9 so we can rewrite the equation x² + (3x/(x − 3))² = 16 as (x − 3)² + 6x − 9 + (3x/(x − 3))² = 16 or (x − 3)² + 6x + (3x/(x − 3))² − 25 = 0 Here (x − 3)² + 6x + (3x/(x − 3))² is a perfect square because 6x is twice the product of (x − 3) and 3x/(x − 3) and we also have 25 = 5² so we get ((x − 3) + 3x/(x − 3))² − 5² = 0 which gives us a difference of two squares at the left hand side whereas the right hand side is zero. This allows us to factor the left hand side using the difference of two squares identity and then apply the zero product property. However, before doing so we first multiply both sides by (x − 3)² to eliminate the fraction so we get ((x − 3)² + 3x)² − (5(x − 3))² = 0 (x² − 3x + 9)² − (5x − 15)² = 0 (x² + 2x − 6)(x² − 8x + 24) = 0 x = −1 + √7 ⋁ x = −1 − √7 ⋁ x = 4 + 2i√2 ⋁ x = 4 − 2i√2
@michellewelchman924527 күн бұрын
I enjoyed your work and your explanation. Excellent and well done! These problems can be long and it took nearly three pages for this one! Lol Sometimes it feels like you're going down a math rabbit hole with no end but in the end when you do reach a solution (s) it's all good.
@peterbyrne639415 күн бұрын
Thank you. very nice solved equation.
@TapanDas-ei3lw16 күн бұрын
Never ending marathon mathematics and brain 🧠 puzzled stories ever. Einstein newton and all superb mathematicians brain to be needed to understood not like me the stupid one..not getting any sweet juice extract from your mathematics, all energies i have lost to get it understood sir .really sir you've the genius brain and you're great.❤❤❤after this life i shall pray to God ,make me genius like you.❤❤❤❤❤
@lenchorivera85433 күн бұрын
Me estoy acordando de mis clases en la prepa…
@oxfordmathseries21 күн бұрын
I prefer to get rid of fraction first, then solution will be of 2 minutes only
@Ron_DeForest20 күн бұрын
Would have been way faster and easier. So much less time to multiply through then gather terms.
@user-cc4zk1ec8c19 күн бұрын
It can be solved by converting x to a trigonometric function. (x/4)^2 + (3x/(4(x-3)))^2 = 1 x/4 = cos 3x/(4(x-3)) = sin 16(cs)^2 - 18cs - 9 = 0
@ahadjonxamidov894024 күн бұрын
Zo‘r
@mahmoudibra582217 күн бұрын
Beautiful
@learncommunolizer16 күн бұрын
Thank you very much
@martinreichard324324 күн бұрын
I prefer to take the square root first and then expand with x-3. This is faster.
@user-ix3lv9qz5b19 күн бұрын
It's a troubled solution.
@spelleg1128 күн бұрын
Great.
@samswift492123 күн бұрын
C 1.4 hrs or 84 minutes.
@mohamedsalah552528 күн бұрын
4-
@tamarshahverdyan272312 күн бұрын
# 30 #
@TheTeller201217 күн бұрын
X-x/3-1=0
@user-vo4qp5bm7p17 күн бұрын
Почему в ответе Вы сократили на 2..???? Так нельзя!!!
@rajanisarmah630716 күн бұрын
Aare vaai itni si sota math aur kitna lomba korega??
@tatyanasnisarenko162716 күн бұрын
Х=2
@bandoubenamar28024 күн бұрын
I no 😂
@divineinspiration334223 күн бұрын
Spreco di carta
@jamielunes184125 күн бұрын
I want to hear a German 😂
@Limited_Light20 күн бұрын
Warum sagen sie das?
@anuarsalomao974822 күн бұрын
COMPLICADO
@anuarsalomao974822 күн бұрын
MAS É ORGANIZADO
@VikasKumar-bj3ruКүн бұрын
Kya bakwass hai yo seedha asnwer ara iska binomial se