Gravitational Fields - A Level Physics

  Рет қаралды 203,856

DrPhysicsA

DrPhysicsA

Күн бұрын

Continuing the A Level revision series covering, fields, the gravitational field, the gravitational constant (G), gravitational potential energy, gravitational potential, the velocity and period of masses in orbit, geosynchronous satellites, Kepler's laws and escape velocity

Пікірлер: 256
@ozlemkoc4960
@ozlemkoc4960 8 жыл бұрын
"It is terrible to do so but I have blocked out the sun" haha I love your videos you're awesome thanks! :)
@ppuckk
@ppuckk 5 жыл бұрын
i heard he watered out the sun lol
@sherlockholmeslives.1605
@sherlockholmeslives.1605 3 жыл бұрын
This is far more intelligent than A-Level students! All the A-Level students I knew at school were thick!
@ExcitedxTurtle
@ExcitedxTurtle 6 жыл бұрын
My physics teacher is crap, so i have to teach it all to myself and this really helps, cheers man!
@rishadbari3177
@rishadbari3177 3 жыл бұрын
Same bro, how did your exam go?
@cerlynieee
@cerlynieee 5 жыл бұрын
thank you for making physics less intimidating, i have you to thank for if i score well in my upcoming A levels :)
@DrPhysicsA
@DrPhysicsA 5 жыл бұрын
Celyn Tan Thanks. All good wishes for the exams.
@DrPhysicsA
@DrPhysicsA 11 жыл бұрын
At 8:30 the gravitational potential energy is the work done to bring a mass m from infinity to a distance r from a mass M. That is obviously negative since PE reduces as you get closer to the mass M. But PE increases as you move away from the mass M.
@xubarney1326
@xubarney1326 Жыл бұрын
what surprised me was you took the time to explain mv2/r. it was taught a long time ago to me and certainly I forgot and didn't understand this when I was watching you. Every aspect of your video revolve around the student and that is why this is so great, clear, engaging and easy to understand!
@DrPhysicsA
@DrPhysicsA 11 жыл бұрын
Sometimes its the tumble dryer.
@haramboy6932
@haramboy6932 8 жыл бұрын
if only there was a drchemistryA level
@yousseftarkhan9210
@yousseftarkhan9210 7 жыл бұрын
Did you find any ? I'm struggling to find one myself. I did for the record find a channel called allery chemistry but I didn't really watch it's videos yet.
@josephmurphy3298
@josephmurphy3298 7 жыл бұрын
Niket try a guy called E Rintoul
@haramboy6932
@haramboy6932 7 жыл бұрын
Thanks
@regisseng5483
@regisseng5483 7 жыл бұрын
Allery chemistry, clearly the best!
@AmbieWolfie
@AmbieWolfie 6 жыл бұрын
E Rintoul
@Shariqwaseem
@Shariqwaseem 9 жыл бұрын
Sir you're the best! I wish there were more teachers like you.
@DrPhysicsA
@DrPhysicsA 11 жыл бұрын
I may not have followed the point you are making. But if you square both sides then you will indeed get an expression without the square root. But then the left hand side will be T^2. Or have I missed the point?
@SorryCrane16
@SorryCrane16 10 жыл бұрын
Washing machine in the background
@Sal-zi4tu
@Sal-zi4tu 8 жыл бұрын
+John Fletcher or a work against gravity....
@jpanonymous892
@jpanonymous892 8 жыл бұрын
+John Fletcher i kept thinking it was mine
@abeel.goraya
@abeel.goraya 7 жыл бұрын
I thought it was a kettle
@meanqueen0024
@meanqueen0024 6 жыл бұрын
There was also a cow....
@comic4relief
@comic4relief 6 жыл бұрын
Abeel Goraya sounds like at around 6:00
@ChrisTheFishGill
@ChrisTheFishGill 10 жыл бұрын
Very well explained. Will check out your other vids. Thanks for uploading!
@DeFawk
@DeFawk 10 жыл бұрын
Thank you very much for this video. I honestly have learnt alot from this! Will be looking into more of your videos soon! :)
@DrPhysicsA
@DrPhysicsA 12 жыл бұрын
I take it you mean at 21:47 where I say r = 4.23 x 10**4 km. I haven't yet double checked it but could it be that you have calculated the value in m not km - in which case it would indeed be 4.23 x 10**7 m.
@leopardtiger1022
@leopardtiger1022 3 жыл бұрын
Excellent lessons. I am thrilled to have found these video lessons. Thank you. Thank you.
@DrPhysicsA
@DrPhysicsA 11 жыл бұрын
You can choose your own convention for signs. The one I am using assumes that potential energy becomes zero at an infinite distance away. Since potential energy increases as you go further away that means it must be negative in order to increase to 0. But as long as your signs are consistent it doesn't really matter what convention you choose.
@ozzyfromspace
@ozzyfromspace 4 жыл бұрын
A field doesn't do anything until you put something in. Like a temperature field that just sits there. Fields are capable of doing things, whether they do them or not. Put a block of ice in a temperature field and the ice melts. That's a brilliant start to the video! 🙌🏽🤯🔥🎊
@lunatic6320
@lunatic6320 4 жыл бұрын
Damn he provides a whole new perspective. Thanks sir.
@DrPhysicsA
@DrPhysicsA 11 жыл бұрын
Force is a vector quantity. It has magnitude and direction. The negative sign is an indication that it is an attractive force (ie the force is in the opposite direction to increasing value of r). You don't have to include the minus sign as long as you remember which way the force operates.
@kraftyay
@kraftyay 10 жыл бұрын
thank you very much i find your videos concise and extremely helpful !
@roycanning3665
@roycanning3665 4 жыл бұрын
Thank you for your videos. They are reviving my interest in Physics from 50 years ago when passing the exam was more important than understanding what you are doing I am a bit confused about what is the difference between Gravitational Potential Energy (about 8:05) and the more conventional mgh kg m²/s² as you mention in your Electric Field Video comparing the two (at about 11:34) Substituting values for the variables they certainly don't agree. Many Thanks.
@DrPhysicsA
@DrPhysicsA 11 жыл бұрын
There are so many books that I cant organise according to them all. I try to organise the videos in some logical order and hope the titles explain what they cover. I'm not sure what your Unit 4 OCR covers. Is it nuclear and particle physics? If so, there are videos on this in the A Level playlist - and more advanced videos on both in other playlists of mine.
@acanthe3
@acanthe3 11 жыл бұрын
Awesome stuff, such a huge help! I love all your videos.
@MelissaWxo
@MelissaWxo 10 жыл бұрын
Thanks so much DrPhysicsA, your videos are so helpful! :)
@n.kmoore4420
@n.kmoore4420 9 жыл бұрын
Thank you, your videos helped a lot! I take IB HL physics but the topics covered are nearly the same ( from the videos that I've watched) so it helps a lot.
@hrshanhussain9317
@hrshanhussain9317 6 жыл бұрын
the vedio made me understand more stuff then i understood in the class so thank u sooo much
@Yizak
@Yizak 9 жыл бұрын
Sunny? In the UK?!
@nethumsapukotana475
@nethumsapukotana475 4 жыл бұрын
I learned the whole topic and more in 30 min than my school teacher who teaches us for a week and i learn 0 from him. Please make more.
@sunidatheshorty
@sunidatheshorty 11 жыл бұрын
Good Luck on your IB physics exam tomorrow! I'm taking the same exam and I agree, these videos are indeed very helpful! Thanks DrPhysicsA! :)
@liiamra99
@liiamra99 9 жыл бұрын
you sir, deserve a medal! cheers
@seny3053
@seny3053 2 жыл бұрын
Wow ! The best physics teacher ever ❤️
@yokeming311
@yokeming311 12 жыл бұрын
i LOVE this, the explanation is good and easy understand.TQ so much ^^
@mohamedshakir408
@mohamedshakir408 5 жыл бұрын
such a wonderful explanation, thnqw
@DrPhysicsA
@DrPhysicsA 11 жыл бұрын
I am delighted to hear it. Well done.
@mujistic
@mujistic 9 жыл бұрын
This video really helped MR thanx!!
@ANSKHALID1
@ANSKHALID1 9 жыл бұрын
Thankyou So much SIr you explained really in great manner :)
@wakilurrahman1536
@wakilurrahman1536 5 жыл бұрын
this channel is too good
@DrPhysicsA
@DrPhysicsA 11 жыл бұрын
Yes, from the centre of the earth to the centre of mass of the man. But I was ignoring the extra meter or so in 6400km.
@bekaemery2918
@bekaemery2918 6 жыл бұрын
This really helps. THank you so much
@DrPhysicsA
@DrPhysicsA 11 жыл бұрын
Yep. Its a cuckoo clock with a cow instead of a cuckoo.
@moomoo7740
@moomoo7740 4 жыл бұрын
Thank you so much! these are very useful!!
@fly.god.infinite1626
@fly.god.infinite1626 7 жыл бұрын
if you listen very closely you can hear your brain frying
@ibrahimgamingbro783
@ibrahimgamingbro783 6 жыл бұрын
You need glasses.
@the0123x
@the0123x 11 жыл бұрын
These videos are so helpful!
@Guitarman0
@Guitarman0 11 жыл бұрын
Great videos, thank you!
@jessijoe7804
@jessijoe7804 11 жыл бұрын
ur video is really a good tool for revision thank u :)
@yeshadevanallee678
@yeshadevanallee678 4 жыл бұрын
Hi sir woaaahh just wowwww i really love physics and you have deepen it
@Tessalovesbirds
@Tessalovesbirds 6 жыл бұрын
Love your videos!
@wateen914
@wateen914 7 жыл бұрын
Thank you, It was very helpful.
@paulg444
@paulg444 3 жыл бұрын
Fantastic videos.
@abhishekdutta8968
@abhishekdutta8968 9 жыл бұрын
Ur video rocks Very helpful
@jasperdahil8264
@jasperdahil8264 7 жыл бұрын
6:42 - It sounds like there's a rocket preparing to launch.
@DJpiya1
@DJpiya1 3 жыл бұрын
Thank u v much for the content. Just one clarification though, If the total energy = KE + PE, when the object moves to infinite distance (r=infinity) both become KE=PE=0. However when r 0, Infinity and make it equals to (mv^2)/2, then I can get the same escape velocity. But still cannot understand what happened to all PE. If somebody can help me, really appreciated. Thanks.
@godzillazumagod9146
@godzillazumagod9146 6 жыл бұрын
What is the speed falling from space to earth with a changing gravity strength. Do you do a video about this?
@Thelightsaver1
@Thelightsaver1 8 жыл бұрын
That's interesting... correct me if I'm wrong, professor, but considering that the centripetal force on the object is F=mv^2/r, does that not mean that the kinetic energy of a rotating body is F*r/2? That is an amazingly cool way to find that.
@avinashpradhan8932
@avinashpradhan8932 3 жыл бұрын
Amazing videos.
@adnansakeeb739
@adnansakeeb739 Жыл бұрын
This was posted 10 years ago but my God you are good....
@williamholm-mercer8799
@williamholm-mercer8799 4 жыл бұрын
Drops lid whilst talking *oops* continues btw thanks so much for these videos, it has helped me understand mechanics a lot better than how my teacher explained it.
@samarthsai9530
@samarthsai9530 7 жыл бұрын
Sir, it would be helpful if you could tell me where I can find the video on electric fields. Its not there in your classical mechanics playlist.
@user-hs3dg8jy3t
@user-hs3dg8jy3t 6 жыл бұрын
kzfaq.info/get/bejne/fap2o7eWy9aofXk.html
@trafalgartorao9299
@trafalgartorao9299 2 жыл бұрын
WE NEED YOU PLEASE COMEBACK, IT VERY USEFULL IN PANDEMIC (2022)
@DrPhysicsA
@DrPhysicsA 11 жыл бұрын
Calculate the force on the 3rd due to the first and then the second using F = GMm/r^2. Since the forces will be in opposite directions the net force is one minus the other.
@hamsalekha1232
@hamsalekha1232 11 жыл бұрын
Thank you so much. This video is very useful for me :)
@DrPhysicsA
@DrPhysicsA 11 жыл бұрын
It is the mass of the earth. The mass of the satellite cancels out at an earlier stage so does not feature in the equation here. Thanks for kind comment.
@technoshrink
@technoshrink 6 жыл бұрын
Question: In the video, you say velocity, v, is a vector, but then you say it's speed at 12:32. How do you convert a vector to a single variable like that?
@itsnotallrainbowsandunicor1505
@itsnotallrainbowsandunicor1505 7 жыл бұрын
For escape velocity, assuming a conservative system where we end up with the kinetic and potential energy of the system as: K_f + Ep_f = K_i + Ep_i, where sub 'f' is final and sub 'i' is initial, should we not set up the equation where the left side is 0. The final kinetic energy and the potential at infinity would be zero. That leaves us with 0 = 1/2mV^2 -- GMm/r. This rids the (--) as shown in 26:31 when we rearrange to get 1/2mV^2 = GMm/r.
@pyotr_sky7431
@pyotr_sky7431 7 жыл бұрын
in my book says ' the magnitude of minimal velocity of a rocket in order for the rocket to be able to escape from grabity is = square root of 2g× m over r. is that correct ?. there was one similar except it doesnt have a square root
@999Tutorialz
@999Tutorialz 6 жыл бұрын
15:26 Moooo!
@NicolasGreg
@NicolasGreg 10 жыл бұрын
What a great teacher you are. Thank you for your videos. Could you make one describing the simple two bodies system and the equation that follows ?
@DrPhysicsA
@DrPhysicsA 10 жыл бұрын
There is a video in the A-level playlist which looks at momentum in two dimensions.
@NicolasGreg
@NicolasGreg 10 жыл бұрын
DrPhysicsA Thank you for the reply. An interesting video indeed. But in fact i was thinking of the two bodies problem in the planetary context. I have read something with a reduced mass to write the exact equation of the movement of a satellite which ends with this r = K²/(GMt( 1 + e cos θ )). I didn't understood how to arrive to this result. I was hoping you could shine some lights. (Sorry for poor english)
@alex123455876
@alex123455876 9 жыл бұрын
Thank you so much.
@maxharrison9918
@maxharrison9918 5 жыл бұрын
I was in year 6 when this was filmed...
@ladislousfarawadya5115
@ladislousfarawadya5115 6 жыл бұрын
yh sure my teacher is a no brainer, n wif vidz lyk thez lyfz made a lot easier......................anks a lot man, u da best
@xubarney1326
@xubarney1326 Жыл бұрын
great video, very clear and engaging. Thank you sir.
@xubarney1326
@xubarney1326 Жыл бұрын
as well as logical
@ajsomething
@ajsomething 9 жыл бұрын
Do you have a video on the gravitational potential graphs etc. please?
@bp56789
@bp56789 10 жыл бұрын
Thanks for the derivation of T.
@comic4relief
@comic4relief 6 жыл бұрын
At 21:13- Period of geostationary, orbiting body: one sidereal day, 86,164 seconds.
@ThomasJohnHyde
@ThomasJohnHyde 9 жыл бұрын
Great videos! P.S. Your voice reminds me of Mark Halliley (The Apprentice Narrator).
@DrPhysicsA
@DrPhysicsA 11 жыл бұрын
Yes. If you think of the earth and the sun, the gravitational force from the earth to the sun is directed towards the sun whereas the distance vector from the sun is measured away from the sun. The key thing is not the minus sign but rather that you are consistent in your signing convention.
@paulebberson4884
@paulebberson4884 4 жыл бұрын
The arrow on the Gravitational field line points towards the larger mass. Always.
@KINGSOMALIA
@KINGSOMALIA 2 жыл бұрын
The minus sign is there as gravitational force is attractive. I get the distance in the opposite direction of the force, however that will just confuse students (why cant they measure from bottom to top etc.)
@DrPhysicsA
@DrPhysicsA 11 жыл бұрын
I assume you are referring to the section starting at about 11:23. You are right in all you say except "small v is the length". This is a vector diagram so v is velocity not length. See my video on adding and subtracting vectors for tail to tail subtraction of vectors. So v on both sides of the equation is velocity.
@jimdogma9890
@jimdogma9890 11 жыл бұрын
I had the same issue. If you square the whole expression, (2 x pi x r) / v, while substituting the root GM/r for the v, you get the expression you derived without the square root in the expression...
@sankaraneetjee1965
@sankaraneetjee1965 3 жыл бұрын
Hello sir. Very nice presentation.
@kurdman12345678
@kurdman12345678 9 жыл бұрын
Gravity is the curvature of space time. Objects are not pulled towards earth they are are essentially pushed towards earth because the earths mass bends the fabric of space around it. Most people say the suns gravity causes the earth to orbit the sun. But in reality the sun warps the space around it, which pushes earth towards the sun.
@dr.surinderkaur9220
@dr.surinderkaur9220 8 жыл бұрын
Mr genius every one knew it . but this is simple Physics IT DOES NOT INCLUDE RELATIVITY
@crunchynachos3922
@crunchynachos3922 7 жыл бұрын
kurdman12345678 The curvature of spacetime due to earth does not push objects towards the earth rather when a object moves near the earth it tries to move in a geodesic path (path between two points that has the shortest length) but due to the curvature of spacetime around earth those geodesic paths are curved which tend to converge towards the earth.
@gabrielavelar5218
@gabrielavelar5218 6 жыл бұрын
kurdman12345678 gravity is a force but doesn't bend space time because if it did you wouldn't age on the moon because it has less gravity
@steffenleo5997
@steffenleo5997 2 жыл бұрын
Good Day Sir, could you Show us how to calculate gravitational Potential energy at earth center?.... Thank you.... 👍👍... Very well explained Video Sir
@frederickambaritaa8057
@frederickambaritaa8057 7 жыл бұрын
technically gravity is just the result of the curvature of the fabric of space time and is not a pulling force. a large mass would curve or distort the space around it like rubber sheet being distorted by say a bowling ball. essentially other masses would "roll" towards the center of the distortion (like a marble rolling down the curve in the rubber sheet we talked about earlier made by the bowling ball). so gravity is not a "pull" but a "push. still like your calculations
@muzzammil217
@muzzammil217 12 жыл бұрын
Thanks a lot!!!
@mothelawn1
@mothelawn1 10 жыл бұрын
Thank you for videos, they do help me a lot. However, I am going through this video, and I seem to be confused that you have v^2 is negative for the escape velocity, also I thought that gpe+ke=0 when working out. Which might correct it?? Thanks M
@DrPhysicsA
@DrPhysicsA 10 жыл бұрын
You can choose any convention as long as you are consistent. In this case I am assuming that at an infinite distance the kinetic energy is zero and the potential energy is zero. This means that as an object approaches infinity its kinetic energy will reduce to 0 and its potential energy will increase to 0.
@halaimialamine1467
@halaimialamine1467 6 жыл бұрын
thin you for this explanation,doctor,but i have a question,in this forumla ,you h'avent considered ,,,the earth mouves in orbit of the sun,this mouves infulences ,the satelite mouves ,why can you expain this in the formula,frendly
@danhyde7501
@danhyde7501 6 жыл бұрын
you have helped a lot over the past few weeks of revision for me. got my first A2 exam in just under an hour. I will let you know how it goes in a couple of months time. (predicted A, although will be happy with a C). Fingers crossed I guess!
@DrPhysicsA
@DrPhysicsA 6 жыл бұрын
Dan Hyde good luck. Hope it goes well.
@zarishahmed9356
@zarishahmed9356 6 жыл бұрын
I wonder if it went well.
@danhyde7501
@danhyde7501 6 жыл бұрын
Zarish Ahmed got a B so I was super happy. Completely forgot about that comment.
@yasminahiba2742
@yasminahiba2742 4 жыл бұрын
Thank you sir ❤🌑
@thil123456789
@thil123456789 10 жыл бұрын
Thanks so much. :)
@natureandchange
@natureandchange 8 жыл бұрын
Hey can someone how he got the m/s^2 from the other Equation?
@foolishgoon
@foolishgoon 11 жыл бұрын
yo man got a B in physics, and i thought id thank you if i did cuz i swear to god i didnot know a word 3 days before the exam. i actually had to the buy the text book then cuz id lost mine, your videos saved me. thankyou very much
@DocFrobnitz
@DocFrobnitz 5 жыл бұрын
Two weeks before midterm Statics & Dynamics exams my British professor said that we could skip the next week's classes to study for the exam, but suggested that we show up anyway because he would "revise everything we have learned thus far". I almost passed out... in American usage 'revise' means 'change what was previously looked at', so it sounded like he was tossing out everything we had previously studied and replacing it with something else.
@ednakanawila5527
@ednakanawila5527 2 жыл бұрын
So helpful
@noctavel
@noctavel 8 жыл бұрын
Sir, your videos are awesome ! but there is something i awalys wanted to know... and i didnt found it in your channel... can you explain how the formula E= -GMm/r² come? was it determined mathematically or experimentally? Thanks !
@LuccaTomazeli
@LuccaTomazeli 8 жыл бұрын
+Otávio Nunes Guimarães it was by empirical methods (experimentally)
@TheMegaAshok
@TheMegaAshok 11 жыл бұрын
In the first diagram you arrived at dᶱ = dx / r = vdt/r where r = radius and v is velocity In the second vector diagram You arrived at dV / v = dᶱ where dV= change in velocity and small v is the length When you equated dᶱ in both the equations dV/v = vdt/r where left hand side denominator v is length and right hand side numerator v is velocity And you have multiplied the length v lhs with velocity v rhs and arrived at v2 /r = dv/dt Could you please clarify or am I missing something. Thanks
@treadmill6089
@treadmill6089 11 жыл бұрын
Thanks! Unfortunately though, CIE tends to ask why there is a negative sign, and they don't accept the direction argument.
@infernosion9907
@infernosion9907 9 жыл бұрын
I am a little confused with the equation F = (-GM1M2)/r^2 Do the masses need to be in a certain order? As in is M1 the mass of the sun and M2 the mass of the planet for example? (As the sun is heavier than the planet). If that is correct then is that the same for the equation r1 = (m2*d)/(m1 + m2)?
@DrPhysicsA
@DrPhysicsA 9 жыл бұрын
Infernosion The order doesn't matter in the first equation. The formula tells you the gravitational force between any two objscts. You just have to remember which one is the m1 and which is m2.
@kellymaungwa3216
@kellymaungwa3216 6 жыл бұрын
ls it really necessary to put the negative sign on force
@jamesdavidmercer
@jamesdavidmercer 11 жыл бұрын
At 21:00 is M the mass of the earth or of the satellite? Thank you, very helpful
@yoyoyoc3po
@yoyoyoc3po 6 жыл бұрын
Isn't kinetic energy equal to (GMm)/2r ?
@rainbowrose675
@rainbowrose675 8 жыл бұрын
This guy is adorable!
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