Hooke's Law and Elastic Potential Energy

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Күн бұрын

This video provides a basic introduction into Hooke's law. It explains how to calculate the elastic potential energy and how to determine the amount of work required to stretch a spring.
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@TheOrganicChemistryTutor 2 жыл бұрын

Physics PDF Worksheets: www.video-tutor.net/physics-basic-introduction.html Full-Length Videos & Exams: www.patreon.com/MathScienceTutor/collections Direct Link to The Full Video: bit.ly/3GbVTem

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@dotnask0001 3 ай бұрын

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@assaineindustries 3 жыл бұрын

Provided the elastic limit is not exceeded, the extension in an elastic material is directly proportional to the load or applied force. (Hooke's law)

@SarcasticLampr4y 3 жыл бұрын

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@keylime6 3 ай бұрын

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@user-dw8lv6sy2y 3 жыл бұрын

일반적인 이해를 위해서는 어떠한 물체의 운동을 설명할 때 이 물체는 어느지점에 있다. 여기있다. 저기있다. 등의 설명을 필요로 하지만 이 영상에서 소개하는 훅의 법칙을 통해 진동하는 물체의 위치를 기술하는 방법에 대해서 또 한가지 알아갑니다. 감사합니다.

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@AnimeFun4ever Ай бұрын

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@jay-koh-sahn Жыл бұрын

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@attataqi923 3 жыл бұрын

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@markbooe205 3 жыл бұрын

Elastic Potential... pretty cool 🙂

@R4G3L3GiTSn1PZ 3 жыл бұрын

Just got our "specific topics" for Wednesdays exam. You got the first 2 out of 8 so far lol

@MrYahya0101 2 жыл бұрын

x and delta x have been used interchangeably in the video, which makes it confusing. If x is assumed to be the distance between ends of spring, then F=-k*(delta x), W=-1/2 k*(delta x)^2.

@understandingart9961 2 жыл бұрын

Yes very confusing part because x is usually the strain caused by the stress so how they can be used interchangeably. If x is total length then using ∆x makes sense

@chongongonga3271 3 жыл бұрын

Thank you

@mulubelay4481 3 жыл бұрын

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@imqr 2 жыл бұрын

not really, whenever you get to nuclear physics and quantum mechanics it becomes pretty difficult for most people

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@Lisa-ux1hr 2 жыл бұрын

I love how he says length. “Lenf”

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@osmanaltanyuksel1884 7 ай бұрын

17:57 dont we define the change in X as Xf - Xi ? when we make (Xf - Xi)^2 , doesnt it have to become Xf^2 +Xi^2 -2Xf.Xi ?

@samuelogunsina9191 2 жыл бұрын

I'm a bit confused abt the last part involving the Work done by the restoring force, I mean initially when the applied force is stretching or compressing the spring to a certain, I have the belief that only the applied force is stretching the spring, not the restoring force, I hqve the believe the restoring only acts when the spring is returning to its natural position , and then the displacement (opposite to the stretched displacement) and the restoring force are in the same direction, so I'm confused how it's work done by the restoring force is negative, to me it feels its should be +ve.

@frossbyte1292 2 жыл бұрын

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@williamsojah8402 4 ай бұрын

Thanks so much, am having exams on strength of material tomorrow

@fitzgeraldgerundio8123 Жыл бұрын

How will you find x if the only present is the mass?

@understandingart9961 2 жыл бұрын

If k is a constant how it's value can change from spring to spring

@mulubelay4481 3 жыл бұрын

U saved my ass again.

@onelaperera7936 3 жыл бұрын

at 16:17 I can't understand how when the acceleration is 0, the work done is equal to the potential energy change, can someone please explain ?

@yuvalkoren4070 2 жыл бұрын

It has nothing to do with acceleration, there are numerous ways to calculate the force exerted that don’t include acceleration. If work is equal to force times distance, then the force is equal to the work applied divided by the distance.

@onelaperera7936 2 жыл бұрын

@@yuvalkoren4070 Thankyou !

@maerincy1836 2 жыл бұрын

Thanks😊 But it would be better if you had given an example of spring being compressed vertically😊

@Wendoc 4 ай бұрын

can the same theory be applied if we press the spring ?? How ever as everyone else say you are truly a life saver

@joanangelam.aguilar3379 Жыл бұрын

Me after seeing this video again after years: "Why haven't I subscribed to this guy yet?!"

@maryamalsuhail7932 Жыл бұрын

On #4 can someone explain why we multiply it by 0.5 and what does the triangle have to do with out problem in the first place?

@Beauty_lord1 Жыл бұрын

The 0.5 is just the ½ in decimal. It makes it easier to multiply and we need the triangle because the force is varying.

@tenewn7624 2 жыл бұрын

How can I be your member

@user-zl6lg3uz3r Жыл бұрын

I have one small question: Why doesn't work done equal to the negative change of potential energy, which is represented by W=-deltaPE. I remembered that this is what my teacher taught me.

@njelekaharriet6107 2 жыл бұрын

I always fail to understand why you are so good when ever am watching your videos.i have a question, why is a spring balance used to measure weight but not mass?

@iasserz 10 ай бұрын

bcuz it is related to force

@njelekaharriet6107 10 ай бұрын

@@iasserz 🙏

@imbisatfajjar 7 ай бұрын

nice vedio i have been watching since i was in grade 6 and i am in nineth grade

@emekaamadi8450 3 жыл бұрын

at 16:15 why isnt the force negative? isnt it 1/2-KX^2?

@AMLennon 3 жыл бұрын

Elastic Potential Energy (PE) = 0.5kx^2. The unit will be N/m • m^2 = Nm = joules. Energy is measured in joules. Note: 1 joule = 1Nm. However, the restoring force, F is measured in N.

@memt3442 2 жыл бұрын

its not in the same direction with force thats why it is positive

@canelaflorin2844 3 жыл бұрын

So for problem nr 7 (which we see a glimpse of it at the end) i got: a) 490 N/m; b) 6.272 J; c) -12.544 J; d) 40 cm. How far was i?

@sarahnaji7563 2 жыл бұрын

c should be 11.392 i think because we use the formula Ug=mgh how did u solve d? i hope u still remmber after 5 months

@nadahosny3595 2 жыл бұрын

@@sarahnaji7563 lol

@bonganimathokgwane9642 2 жыл бұрын

Springs in parallel and series plz

@dritanmuslia6922 5 ай бұрын

At minute 22:58 why is ΔX² = (Xբ² - Xᵢ²). I don't really understand the logic behind it, it seems more plausible for it to be (Xբ - Xᵢ)². Can someone please explain?

@DO_CHE 5 ай бұрын

16:51 doesn't work equals the change in kinetic energy and not the potential energy ? So it would be W = PE = 1/2 F x

@derrick8044 3 жыл бұрын

23:29

@michaelgeorge1119 2 жыл бұрын

Every time he says hookes law I hear it as cole slaw Hooke slaw 🥰

@hike8932 10 ай бұрын

for 4th question just do fp=kx then w/2 = fs where f=fp and s = x so fp= kx == 250x0.75 == 187.5 187.5 x 0.75 = 140.625 / 2 therefore work required = 70.3125 J or 70.3 J

@Adembtr6704 10 ай бұрын

16:52 what if acceleration is not 0, I wonder if f net is always 0 in this law?

@Adembtr6704 10 ай бұрын

if the acceleration is not 0, does the total work equal KE + PE?

@Adembtr6704 10 ай бұрын

if it is equal how do we find KE?

@yeisonsamayoa6081 Жыл бұрын

Molto Gracie

@ali32bit42 2 жыл бұрын

soo funny thing ... i dont actually need this for school. it feels strange to come back to the physics we learned at school because we have found a practical use for them ! normally as a kid youre like "this is useless i am never using this in real life !" but now its completely differant . i genuenly need this for something ! . i am currently programming a car physics system for a video game and cars have springs for their wheels. in order to simulate car springs i need to know exactly how those physics work and implement the math into my programming. i wish school was able to teach us about practical uses of math and physics like this more often. that way we at least care about what we are learning because we know what we want to use it for . but no its always vague and abstract boring concepts that we dont know how to use.

@jordansamuels7187 Жыл бұрын

Same boat bro, I'm currently studying engineering in game design, and a lot of physics is involved in games

@user-sh1fy9nf4m Жыл бұрын

I have an exam in less than an hour this saved my life thanks

@user-ht9mr8wq9i 10 ай бұрын

wow😻

@adnanhusain8532 2 жыл бұрын

what is "m" ????

@user-mp8ye9gw7o 3 ай бұрын

2024 best tutor ever😭

@dismaleclipse5587 Жыл бұрын

There is a mistake on question 6; you multiplied 1/2k by the difference of the squares of x rather than by the square of the difference of x. Cheers

@Mori_mee Жыл бұрын

@vihashah5975 2 жыл бұрын

Isn't work = - change in potential energy?

@vihashah5975 2 жыл бұрын

nvm he explains that in the end of the video lol

@martinsanchez-hw4fi 7 ай бұрын

How do you expand Deltax^2 as x_f^2-x_i^2? You are missing a term, aren't you?

@yavuzyukselyoyo 7 ай бұрын

senin allahına kurban

@YKSILK-zo3qd 6 ай бұрын

ahahsahdsa adam finallere çalıştırıyor bizi

@thatomofolo452 6 ай бұрын

Real talk 🤔

@thabisonzimande8718 Жыл бұрын

I thought w= change in KE

@kidus4087 Жыл бұрын

i didn't understand question number 4

@jayjo1378 7 ай бұрын

Just your voice motivates me to make discovers (⁠๑⁠♡⁠⌓⁠♡⁠๑⁠)

@ricaldoritchiebasketballvl651 3 жыл бұрын

Yo did not explain what k and the other formulas meant you were just saying them but not telling us what it really meant

@mandairaleo4190 3 жыл бұрын

Well its explained here... kzfaq.info/get/bejne/fqd8ldeqqbvOoGQ.html

@SweetSamaChild Жыл бұрын

Question 6 is incorrect 45cm is 0.45m not 0.045m. Therefore the answer is -14.6832J

@writersblock1016 Жыл бұрын

4.5 cm, not 45.

@user-kz2tn7yk9z 4 ай бұрын

How does the gravitational wave emitting from a planet differ from a rubbee band being stretched out maybe the gravitational field is stretching out some other force than elastic energy stretches out any ideas to prove or disprove this? I need all possible awnsers please no insults those are a waste of time im trying to learn and grow not hear little 2 year olds throw insults

@enriquesoler3150 8 ай бұрын

for question's 1 and 2, why is the formula: F=kx? Shouldn't it be this: F=-kx, that's what my textbook is telling me?

@idunuadefarakan6022 3 ай бұрын

To stretch a spring it’s positive and to compress it, it’s negative

@lohht7g 3 жыл бұрын

ولتعلمي يا فتاتي بأن الذنب لن يأتيك إلا مزينًا؛ فـ تارة تزينه اللذة، وتارة أخرىٰ تزينه سهولة خوضه؛ ووالله إن لذته تلك لتذهب سدىٰ بمجرد الانتهاء منه، فقط لن يبقىٰ منها سوىٰ ندبة سوداء وشمت بحرافية على جدار القلب؛ فـ إياك أن تسقطي وتكوني لقمة سائغة لشيطان رجيم، وإن حدث وسقطتي لضعف مسك، فـ لا تطيلي السقوط وانهضي سريعًا، وآوي إلىٰ ركن شديد، وقري بذنوب اقترفتيها ومنها استغفري، فـ والله إن لم نستوحش الذنوب ونبغضها من أول مرة؛ لاعتدناها وكأنها نعم، فـ لتعيذي قلبك الصغير من أن يألف ذنبًا، ولتعيذيه من شرور الدنيا وفتنة الهوىٰ؛ فـ تالله إن المرء لا يُصاب إصابة أشد من تلك التي تستبيح حرمة قلبه وتأسره.💙

@Mira-bi4ts 3 жыл бұрын

@vivansh و ما لغت الاستعمار هذه؟

@TDRM1989 2 жыл бұрын

In the first minute... K is what?

@zahidfaheem3233 2 жыл бұрын

A constant. Force increases linearly with length (more force is required to pull further) and the factor by which it increases is called k. So it's just the relationship between F and x.