How To Find The Value of Absolute Zero Temperature

Рет қаралды 11,010

3 жыл бұрын

Is there a limit to how cold things can get? Absolute zero is the temperature at which a thermodynamic system has the lowest energy. But how do we find its value?

Пікірлер: 27

@sarafathossain6212 3 жыл бұрын

why this channel is so underrated?

@foodplanet120 3 жыл бұрын

Only three videos are there

@NaN_000 Жыл бұрын

@@foodplanet120 🗿

@lit1041 11 ай бұрын

I'm sure if there were more videos on it, it would become popular.

@resonatedvirtue8746 2 жыл бұрын

Thank you so much sir! Your videos solve all the doubts my teachers couldn't solve. Just Great job!

@TaufikAngga-xk6ej Жыл бұрын

wow your video is very clear all 3 video is good video thanks for share this, Im from indonesia. Just good job sir.....

@mumbaiverve2307 11 ай бұрын

Beautifully explained !

@patboily300 11 ай бұрын

Very good, and most likely 100% correct, but would you need many more measurements, especially at colder (sub-zero Celcius) temperatures to make sure that the relationship is not asymptotic?

@jialixx 2 жыл бұрын

Awesome video. I subscribed to your channel even thought there are only three videos. Keep up with the good stuff!

@superbaddctv 2 жыл бұрын

Only 3 vids and I'm impressed. New Subscription. We need more

@vivekthumu8992 3 жыл бұрын

Super videos brother...... Very understandable.....

@dwilley8 Жыл бұрын

Great job.

@rajeshmondal7134 3 жыл бұрын

Good work,

@TakuTJuly 3 жыл бұрын

We love your videos. Please upload more frequently😖😊

@NoCantsAllowed 9 ай бұрын

Don't you think the portion of the beaker exposed to ambient air will affect that of the submerged portion containing the helium?

@ravindrabhamre4254 3 жыл бұрын

Good video

@omsingharjit Жыл бұрын

Keep continuing your work on physics experimental setup.

@ArunKumar-zd4ue 3 жыл бұрын

wow awsome dude , upload more videos please

@shrawankhaling8892 3 жыл бұрын

Absolutely enlightening!

@stardust5169 3 жыл бұрын

Yupp!

@thomasolson7447 11 ай бұрын

Why not use this with arctan instead of a ratio with 2pi in e? I eyeballed the tangents. (760/7463+1240/7463)/(1-1240/7463*(760/7463))=14926000/54753969≈0.2726012428432. He is approximately 0.280048237974... He might be 7/25, which is actually a rational triangle 7^2+24^2=25^2. MORE NOBLE GASSES PLEASE! Err, the slope is [L]^3/E or [L]*[T]^2*[M]^(-1)?