I am inherently good at quant and got a Q51 in an official mock. However, I did not know around 80% of the techniques used in this video. Proud to say this webinar was useful for me and I am sure would be for everyone.

Answer to 700 ( last question ) is both conditions are sufficient. On solving the given equation, we will get two solutions x=y or x+y=-4 (remove the mod and solve by type3). To remove x=y solution, we need a statement to say x and y are not equal. XY2, Y

This man is a legend! Makes things so simple, even though my quant is already good, I learnt a lot

Aditya out here dropping straight knowledge. No messing around. Well structured and concise. MVP!

Aditya you're doing God's work. I'm watching this way 2 years in the future and this is absolutely incredible. Thank you for the work you are doing.

@59:00 Type II, @1:01 Type III & Type IV @1:06 Type 5

Wow, I am speechless after watching Aditya’s inequalities and absolute value sessions. No one (I mean it… absolutely “No One” 😊) could have explained these topics better than him. MUST MUST WATCH, if you really want to understand these concepts !!

Wow Aditya Kumar is brilliant at breaking down and explaining complex problems.

This was an amazing session, really recommend going through it

No side hustles, straight to the point. Awsome Aditya. Very helpful. Im struggling on accuracy of Absolute values. This is saver for me :)

Thanks for really breaking things down to the very basic level and making to more interesting to learn these concepts 👍

Another gem of a video. Here is to more content from you sir! GMAT club are you listening!

The most important video on GMAT Quant on youtube.

I have never dreaded a topic more than this. Thank you so much for making it a cakewalk!!

Thank you so much, Aditya! Wonderful lesson! Thank you also to the GMATClub

Thank you so much Aditya. I have been struggling with Absolute Value since long. It used to haunt me like anything. You just made it approachable for me. Thanks a ton

The problem in 37:55 is wrong I think. X>|y| this should be the case. only X>0 and X>y will not solve the equation. Ex: X=1, Y=-2

It think there is mistake @38:26.......The answer will be "E" for the first question. Because the right condition we need to satisfy would be x > |y|, not just "x > y". For example, consider, x = 4 and y = -3, this makes the question true. However, we consider x = 4, y = -6, then it negates the above equation, while both cases are complying with the two options i.e. x>0 and x>y. Hence I am saying that the essential condition is x>|y|, and not x > y.

This was brilliant. I was struggling a lot with absolute values with inequalities and found the video incredibly helpful

Thank you so much for this video - Aditya and GMAT club! I've been struggling with inequalities since the beginning of my prep, and I'm so glad I found this video. FINALLY, I feel like I have an idea of how to approach these questions. How you've managed to make even this topic seem easy is beyond me.

By far the best video I have seen on this topic

Reach out to Aditya Kumar on LinkedIn www.linkedin.com/in/aditya-kumar-a29a6779/

why was the 700 question cut off?

Thanks a lot Aditya. Both Inequality and Abs value videos are very helpful and packed with concepts :).

In the question is x|y| > y^2 along with conditions x > 0 , x > y we can also add one more that is y < 0 bcz in the equation y is inside mode on the L.H.S and getting squared on the R.H.S where it converted into postive both the sides .

@Aditya Kumar You are truly quant master. Learnt so much...Thanks a tons

Thank you so much for these amazing sessions on inequality and modulus!

I has alwyas been a pleasure getting into your quant sessions...just loved it..

Wonderful video - thank you Aditya and GMAT Club

The question around minute 38, I think the question should be is x>IyI? and not is x>y. Therefore, the answer to the question should be E and not C. For the second case where the conditions are y>0 and x>y, yes the answer is C. Please correct me if I am wrong. Thank you very much for this very insightful video.

Aditya is a hero

Aditya thank you so much. You're an amazing teacher! Made this complex topic soo soo easy and really made us understand that how incorrect rather time consuming the plug-in approach is.

Very good explanation of concept & beautiful sample questions to build the right & easy understand. Hope to have more videos like this on other topics as well.

so happy i found this session! thank you aditya

Really Awesome Explanation Aditya Kumar Sir ! You have great sense of explaining.

Thank you Aditya, I’ve atleast watched this 4 times now!

Wow.. Thank you. You make things sound so simple

That was mind blowing! Thank you.

the answer should either be E or changed question: prompt: x|y|>y^2 ? 1. x> 0 2. x> y you don't know if y >0. statement E. or change question to "x|y|>y^2 ? if y > or < 0" then answer is statement C

Legend in gmat quant !! Thank you !!

Brilliant session.

Thank you so much Aditya!!! ✨

amazing video. Thanks for clearing so many concepts.

37:38 - 2nd condition should be x>|y| -------> eg. nos to solve this, x=2, y=-3 ----> x|y| = 6, y^2=9, LHS

man this was a brilliant explanation - good stuff @Aditya

Great.. Simply brliant

Super helpful, thank you!

Great teacher

Really made things simple for me. Thanks.

Hello, wouldn't we need in the problem "x * IyI > power(y , 2)", the information confirming that y != 0? This is given in the second instance of the problem, where y > 0 and x > y, but not in x > 0 and x > y. Therefore, I would think the info from both last statements to be insufficient. Thank you for your time. I hope to get an answer, please.

Had to write this...you are Bond...James Bond WOW !

Fantastic class sir! But where is the last question you just mentioned at the end (700 type question)?

Excellent teaching Aditya

this is such a game changer - thank you!

Amazing session!

In 43:20, why do we make the sign of the entire absolute variable be negative, and not just the variable? Meaning, if we are plugging in the variable x, wouldn't we only change the sign of the X?

sir the session was so helpful thanks a lot. awesome class

Hello aditya, great work but help me umderstand why in 33:44 a and b cannot both be negative because |-2+ -3| which is |-5| is not < |-2- -3| which is |1|

Thank you so much guys!!! This was so so helpful 🔥

Very well explained , thanks !!!

In the question ‘what is the value of y?’ Can I directly say that 1 will give me 2 values of x coz degree is 2 which means I can’t find y directly. Moving on to 2 gives me 2 possibilities which when I check in 1 show that y will be imaginary if x is -8. Giving me my answer c and y=14. Please tell me if this is the correct way to see this?

Great video, Thanks Aditya

Incredible. Thanks a lot!

This is awesome, thank you!

Is there some link where I could find the whole video? I would like to check the last excercise, but it seems that tha video was cut at the last part.

perfect. thank you for great explanation

absolutely brilliant 👍

These questions absolutely fried my brain lol.. but i thank you for the absolutely excellent explanation… it’s frustrating to know how absolutely useless these questions are in the real world..

hi gmat club for type 4 absolute values in 1:05:50 why not take the roots like in the case of type 3 and have x and y to be less than 0? please help. I cant seem to move forward from this

Thank you so much sir. Really helpful 🤗

such a great video thank you!

Thank you so much! Amazing vid

Was the last 700 level question cut off from this video? I felt like it ended abruptly.

In the type 5 example at roughly 1:14:00, why do we just have to know whether x

|3-y| also means y

Thanks for the video

@aditya kumar: can you plz upload vedios of number system?

Thank you very much

In 38:56, Shouldn't the answer be E instead of C? Don't we need |x| > |y| (instead of x > y)? If x = 2 and y = -3, then LHS is 6 and RHS is 9 : then x|y| < y^2 If x = 4 and y = -3, then LHS is 12 and RHS is 9: then x|y| > y^2

Could I please get the link for the inequalities webinar?

38:25 I have a doubt, wouldn't it be 'not sufficient' "Option E" as the conditions given doesn't clarify y>0??

At 37:27 in the video there must be one more condition Y>0

9:00 Variable cancellation

if u r some one who has not studied maths in 11th /12th should watch this video.

Hi, this was a great session. However, i do have a question on the general form for greater than. I tried applying the same to the below two questions and couldn't get the correct answer: 1. |x+5| > | 3x-2| 2. |x+3| >= 4x would highly appreciate a response on this.

can the concept of 5 types be used for multiple equations as well? In our example, we had only one inequality in which there was only one parenthesis. can we use this concept if we have more than one parenthesis? If yes, please share an example

at 30:00 should n be anything except 0?

57:33 - how to create a range

At time 1.15.00 hr, in that particular problem why can't we solve the equation |x-5|=5-× by considering( x-5 )can be positive or -(×-5) .

at 38:30 wouldnt answer be E?

Please take a session on time and work, time and distance

You are incorrect for the question at 35:07 the correct answer is x > |y| for the equation x |y| > y^2 You have x > 0 and x>y However, to prove this incorrect. Use x = 4 and y = -5 These numbers satisfy your condition of 4 > 0 and 4 > -5 The do NOT satisfy the original equation. 4 x |-5| is not greater than (-5)^2

Do you offer tutoring? I think I need help!

thank you so much it s really helpful