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Introductory Fluid Mechanics L2 p5: Example Problem - Wall Shear Stress

  Рет қаралды 115,260

Ron Hugo

Ron Hugo

9 жыл бұрын

Пікірлер: 32
@diegoperez3526
@diegoperez3526 3 жыл бұрын
You explained this incredibly well. Coming from an engineering student studying from home during the pandemic, your videos are a lifesavers. Thank you very much!
@beoptimistic5853
@beoptimistic5853 3 жыл бұрын
kzfaq.info/get/bejne/jrZzmqqFnqjQooU.html 💐💐💐💐
@hajamariole3586
@hajamariole3586 7 жыл бұрын
Thank you! It's really helpful to watch someone go through the motions.
@juanjosegalindoramirez9417
@juanjosegalindoramirez9417 Жыл бұрын
Gracias, tus videos también ayudan a gente que habla otro idioma
@mithunroy65
@mithunroy65 5 жыл бұрын
Thank you so much sir. Your concept is very clear. You are great.
@alienmoondudes8071
@alienmoondudes8071 4 жыл бұрын
I came looking for how I can understand the sign of the answer and I got it plus an explanation for why that is. Great content :)
@beoptimistic5853
@beoptimistic5853 3 жыл бұрын
kzfaq.info/get/bejne/jrZzmqqFnqjQooU.html 💐💐💐💐
@yunus-ff2mw
@yunus-ff2mw 5 жыл бұрын
Perfect language. Thank You Sir!
@ronhugo6225
@ronhugo6225 9 жыл бұрын
You are correct - if you look at the coordinate system that I draw at 1:42 you will see that the y-axis has a zero value at the center line of the channel.
@AJ-et3vf
@AJ-et3vf 2 жыл бұрын
Thank you for this sir. Very helpful!
@thenineminus1
@thenineminus1 9 жыл бұрын
My only question is that the "y" in your formula represented the distance between the plate and where Umax is located? Thank you for showing this example.
@tamiljazz7031
@tamiljazz7031 6 жыл бұрын
Sir, when will fluid flow at any value of shear force or it should be greater than the viscosity of fluid?
@sfjgqremwfng8613
@sfjgqremwfng8613 6 жыл бұрын
can you please tell me where does 0.25 came from? ... I mean the y in last equation
@ronhugo6225
@ronhugo6225 6 жыл бұрын
The coordinate system is defined at the centerline of the channel. The y in the last equation is the y-location of the upper wall - so half the channel width.
@kaistmechanic
@kaistmechanic 4 жыл бұрын
Thank you. It's a really good explanation. But could I ask a question? what about the shear stress of the lower wall? if y= -0.25, then tau on fluid is positive,on the other hand, tau on wall is negative, so shear stress of the upper wall and lower wall are opposite directions. it's really confused.
@MajPirate
@MajPirate 3 жыл бұрын
Did you get an answer for this? I have the same problem in understanding. Cheers
@christopherraris8667
@christopherraris8667 3 жыл бұрын
Where the Y value is coming from?
@daniyalraja3453
@daniyalraja3453 Жыл бұрын
How did u get value for y? Is it given in question?
@constructofeternity
@constructofeternity 5 жыл бұрын
won't Shear stress equal - of viscocity * velocity gradient
@saucegod7322
@saucegod7322 7 ай бұрын
Where did the value for y come from?
@airplaneking
@airplaneking 2 жыл бұрын
This velocity profile doesn't make sense to me. The velocity is moving backwards at the wall (y= +/- h)?
@gutierrezgutierrez5901
@gutierrezgutierrez5901 7 жыл бұрын
how is 0.5mm equal 0.005 m, it would not be 0.0005?
@ronhugo6225
@ronhugo6225 7 жыл бұрын
h in the denominator is 0.5 X 10^-3 m which is 0.0005 m
@rubentuting525
@rubentuting525 2 жыл бұрын
y = 0.25 ×10^-3 where did that came from sir?
@ThriveMentalityHub
@ThriveMentalityHub Жыл бұрын
it is the distance from the umax, (center) to the top
@snoberzulfiqar5911
@snoberzulfiqar5911 4 жыл бұрын
How value of mew is calculated?
@claramelb7476
@claramelb7476 4 жыл бұрын
I think it came from interpolating the values from the table A.1 I interpolated and got 0.001155 so I guess it's about right with different tables and slightly different numbers
@beoptimistic5853
@beoptimistic5853 3 жыл бұрын
kzfaq.info/get/bejne/jrZzmqqFnqjQooU.html 💐💐💐💐
@aryaahmadamiruddin3957
@aryaahmadamiruddin3957 9 ай бұрын
why the result changed from -3.12 N/m² to +3.12 N/m², please explain 🙏
@funnygrtv5689
@funnygrtv5689 3 жыл бұрын
For y=h τ=μ*(du/dy)* (π/2) = 0.0013*(0.30/(0.00025) *(π/2)= 2.449 For y=-h τ=-2.449
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