Inverse Functions

Рет қаралды 81,630

6 жыл бұрын

We know about functions, so what are inverse functions? Let's find out!
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Пікірлер: 50

@robintay1449 7 ай бұрын

Thank you so much! You made inverse functions easier than my professor did.

@jaineilsart1528 Жыл бұрын

Finally a channel that teaches quickly and effectivly without any inconvenience.

@kenjo9885 6 жыл бұрын

Nice one PROFESSORI!!!

@simplifiedscience7497 2 жыл бұрын

Amazing explanation!! Hats off

@aprendacompaiva 3 жыл бұрын

Congratulations for the video! Compliments from Brazil

@chaynhungkhongkhet833 2 жыл бұрын

Amazing explaination .Thanks sir

@Cube_Box 2 жыл бұрын

wow, you're so straight forward I understood the whole thing from the thumbnail itself!

@maximchowdhury6203 4 жыл бұрын

Thanks for this

@DrLiangMath 2 жыл бұрын

Concise and understandable. Excellent!

@theocean6102 7 ай бұрын

The one thing I just don't understand is when in your example of x+2 and x-2 (when x =3) that the 5 you get from adding 3 and 2 can just be substituted back into x-2 like this (5-2) to obtain the 3 when this 5 is a y value.

@Beingsprout 3 жыл бұрын

Thank you ♡♡♡♡

@tGoldenPhoenix 2 жыл бұрын

Done this lesson.

@leftenanalim 7 ай бұрын

What about the squared of a negative number? The reverse operation should return back a negative number. So sqrt could should return either a positive or negative value

@olibirdoliver9847 5 ай бұрын

Square function does not have its inverse function because its not a one on one function and it wont be a function after it is inversed

@science-y9209 3 жыл бұрын

Thank you ❤💙💛💜💓💕💟💗💖

@zilog1 2 жыл бұрын

this is interesting because this has to do with my cryptography class for CIT. if a function generates a hash, undo that...

@wongcheehen-un7dr 6 ай бұрын

But I have tried with with multivariable functions (e. g( x^2 / 7)+( 3(x^2))/5 ) and end up getting some y=uy with looped functions is it normal?

@melanietoussaint2130 3 жыл бұрын

Why is important the study of inverse function in the study of function?

@bh-tabz5134 7 ай бұрын

Idk

@0og 7 ай бұрын

@@bh-tabz5134why wpuld you answ3r a 2 year old question with "idk"

@thatomofolo452 3 ай бұрын

Not really

@Gd_Monsterforce 2 ай бұрын

Maybe he/she meant real world applications

@swxqt6826 2 ай бұрын

At the end, isn't 1/3(x + 3) simply equal to 1/3x + 1?

@satbirsingh7269 6 жыл бұрын

thanks sir

@ChromeandClean 9 ай бұрын

Professor , could you please explain the 4th comprehension question , (2x+1)/4, and how you got your answer

@saramrad7822 8 ай бұрын

firstly you swap the x by y so y=2x+1/4 then x=2y+1/4 after that it's 4x=2y+1 so y=4x-1/2 and this is the inversed function's answer. I Hope that u could understand

@pradyumnamishra4810 4 жыл бұрын

Sir , in the first comprehension ...how did you solve ...when (x-1) is in the brackets . I mean what to subtract from both sides ...I didn't get it ...I don't get it when there are brackets

@ProfessorDaveExplains 4 жыл бұрын

just turn f(x) into y, then swap x and y. then solve for y. divide by two and then add one.

@estherntoshya1259 Жыл бұрын

where did (x/2)+1, come from is it not x+1/2, am lost 😢

@Tusharplays69 11 ай бұрын

@@estherntoshya1259i guess you've already found the reason but if in case you didn't, lemme clarify it for you. f(x)=2(x-1) Now, let f(x)=y y=2(x-1) swap the variables for f-¹(x). x=2(y-1) Divide by 2 x/2=y-1 Since you're adding 1 after you have already created a fraction x/2, you've to add it to the whole fraction. Thus, (x/2)+1=y f-¹(x)=(x/2)+1

@davidt9747 10 күн бұрын

@@Tusharplays69 thanks, but for some reason when i see x=2(y-1), the most reasonoble thing seems to be x=2y-2, then y=(x+2)/2

@rubinamujahidah1040 Жыл бұрын

I am in 9th grade but my love for mathematics have brought me here

@camxanh2848 4 жыл бұрын

Shouldn't the answer to the first comprehension quest is (x+2)/2? May you check that again?

@ProfessorDaveExplains 4 жыл бұрын

divide by two first, order of operations

@camxanh2848 4 жыл бұрын

@@ProfessorDaveExplains Ah now I see. Both "(x+2)/2" and "x/2 + 1" are the same thing. "x/2 + 1" can also be written as "x/2 + 2/2", hence expressed as "(x + 2)/2" since the two fractions have the same denominator. Btw, thank you for making these quality content. It really helps me out.

@medotedo8410 4 жыл бұрын

@@ProfessorDaveExplains both of those algebraic form will yield same value

@khaledosama1836 Жыл бұрын

@@camxanh2848 The second comprehension quest could be also expressed as "x/3 + 1" but for some reason it was left in the form of "x+3/3" unlike the first quest. I don't know why

@diegomandragora4327 2 ай бұрын

@@ProfessorDaveExplains Expanding the bracket first and then do everything else works too( - won't break the rules of bidmas- ), and it directly leads to X+2/2. Which is actually equivalent to the answer displayed in the video. Only that it's a more compact algebraic fraction. Ps; Thanks for the fantastic content, and educating the world! 😊

@thatomofolo452 3 ай бұрын

It undoes the exponent

@Nishantmakadiya Ай бұрын

Only one day absence in school can ruined math after this video all makes sense now thanks

@whatdoyouthink2738 2 жыл бұрын

The functions that have square root,they don't have inverse.right?

@kchrome5796 Жыл бұрын

The inverse of a square root is a square (^2).

@science-y9209 3 жыл бұрын

👏👍🌌💐

@medotedo8410 4 жыл бұрын

4:06 undoes ???? undo better

@deankaraniya7422 2 жыл бұрын

I'd rather not take grammar lessons from someone who avoids using proper punctuation and copula.

@medotedo8410 2 жыл бұрын

@@deankaraniya7422 Thank you.

@zack_120 2 жыл бұрын

3:46 - The notation is chaotic. originally y=4x-5, and then it becomes y=(x+5)/4 !? How do you reconcile this obvious contra/error? Mathematicians should've come up with a better way to express inverse functions. Just like the inverse trig function where e.g. the inverse of sin(x) = arcsin(x), this UNAMBIGUOUSLY separate the two reciprocal functions. 0:40, f^-1 is the original notation for 1/f, e.g. 10^(-1)=1/10=0.1. why then here you subjectively disqualify the rule? This is not correct even it is used as such. This is one of the reasons why some math subjects are 'hard' to understand and misleading.

@kermitthefrog6147 2 жыл бұрын

Why are you angry at the inverse notation looking like an exponent but not at the function notation itself looking like a multiplication?