Is Fermat true for the real numbers?

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Dr Peyam

6 ай бұрын

Пікірлер: 36

@Idtelos 6 ай бұрын

Great to see you back! We all miss your enthusiam for mathematics.

@etiennebasset7493 6 ай бұрын

Fermat would be proud 😂

@FerghusCameron Ай бұрын

Why is all the math I struggle with so simple when I find the teacher that can explain in my way? I will try to get up to Calculus by the end of 11th grade as i have never gotten to enter Middle school or High school due to payment issues and for my family having trouble with work thank you sir 🙏

@Happy_Abe 6 ай бұрын

Missing your videos

@CornishMiner 6 ай бұрын

Always good to see Dr Peyam 👍

@drpeyam 6 ай бұрын

Awwwwwww!!!

@harikishan5690 6 ай бұрын

so nice to see a vid from you!!

@vokuheila 6 ай бұрын

Isn't this obvious lmao

@barteqw 6 ай бұрын

Good to see you again! 😊

@imauz1127 6 ай бұрын

but it works for the p-adic integers, right?

@koenth2359 6 ай бұрын

Also 3^(2/n)^n +4^(2/n)^n = 5^(2/n)^n etc.

@Linkedblade 4 ай бұрын

i didnt know that a=b was allowed

@Yes_I_c4n 6 ай бұрын

Hmn, I didn't get how that proves that it's not valid for the real numbers. I mean, firstly you made a=b, correct?

@carultch 5 ай бұрын

Fermat's last theorem is that it ISN'T possible for a^n + b^n to equal c^n, where a, b, and c are all whole numbers, when n is greater than 2. This isn't even close to a proof of this theorem. It took 200 years after Fermat's death to prove it. Fermat claimed to have a proof, but he didn't include it in his publication.

@alexmcmahon2810 6 ай бұрын

4 is a real number, did you mean irrational numbers or R\N? I'm confused!

@NaradaFox 6 ай бұрын

dr. Peyam is still alive!!!

@Kiwi-zz8ri 5 ай бұрын

Except a and b have to be positive INTEGERS

@Bemajster 5 ай бұрын

Do you even listen what he is saying?

@Kiwi-zz8ri 5 ай бұрын

@@Bemajster yes but that’s not Fermats* last theorem. Fermats last theorem is for positive integers

@Bemajster 5 ай бұрын

@@Kiwi-zz8ri no shit sherlock

@hectordomingotroncoso3047 6 ай бұрын

Good morning,Dr. Peyam,i'm Héctor Troncoso,FROM Argentina,Buenos Aires.,i'm the oldest pupil You have,i'm 69 years ,but my math 's soul is still alive,so thanks for teach me,and sorry because of My Bad English. Regards.

@nasseerkassim1771 6 ай бұрын

Dr piam I like ur vedio

@isjosh8064 6 ай бұрын

(1/n)^n is just equal to 1 though.

@muratatatoyran6419 6 ай бұрын

But Fermat says a,b,c € N+

@anuragkr3026 6 ай бұрын

You looking so weak ❤ Get well soon

@drpeyam 6 ай бұрын

Oh that was years ago, I’m feeling better 😂

@maxhagenauer24 6 ай бұрын

How does that show it doesn'twork for all real numbers? 2 is just 1 example.

@bjornfeuerbacher5514 6 ай бұрын

Fermat's theorem says that the equation a^n + b^n = c^n has _no_ solution for integer values > 2. The equivalent statement would be that the equation a^n + b^n = c^n has no solution for any real exponents n. He showed that at least one example exists which is a solution, hence he disproved the statement. That was the goal of the video.

@MichaelRothwell1 6 ай бұрын

@@bjornfeuerbacher5514Letting n be real was the extension to real numbers that I thought Dr Peyan was going to look at, but in fact he looked at the case where a, b and c are allowed to be real, with n still an integer >2.

@sepdronseptadron 6 ай бұрын

@@bjornfeuerbacher5514no, it was for any real a, b, and c, not for any real n because a and b is 2^(1/n), and c is 4^(1/n) in the video

@bjornfeuerbacher5514 6 ай бұрын

@@sepdronseptadron It was for a, b, c, n _all_ being real numbers.

@Yes_I_c4n 6 ай бұрын

Don't get it either.