Умножить числитель и знаменатель дроби на 2, в знаменателе будет формула квадрат разности корня из 5 и корня из трех. А дальше только упростить! 😊

let x = the answer. u = x/4. Then u^2 = 4+sqrt(15) and 1/u^2 = 4-sqrt(15). u^2+1/u^2 = 8 and then u+1/u=sqrt(10). u^2+1=u*sqrt(10). 5+sqrt(15)=u*sqrt(10). u=(5+sqrt(15))/sqrt(10). u=sqrt(2)*(sqrt(5) + sqrt(3))/2. x = 4u = 2*sqrt(2)*(sqrt(5) + sqrt(3)).

splendid!!!!

Çok güzel bir paylaşım.Muzik ve matematik öyle muhteşem bilim ki konuşmaları anlamasam da ne yaptığınızı anliyorum.Cok teşekkürler

Clear. Splendid and excellent.

Para no obtener un resultado como el que esperaba, propongo esta alternativa mas directa y con un resultado como el que tampoco me convence . . A partir de Sq(64 + 16 sq15) Sq( 16 ( 4 + sq15 )) 4sq( 4 + sq15)

= √[16 / (4 - √15)] = √[16.(4 + √15) / {(4 - √15).(4 + √15)} ] = √[16.(4 + √15) / {16 - 15} ] = √[16.(4 + √15)] = 4√(4 + √15) → you need to find a number x sush as x² = 4 + √15 Suppose that: x = √a + √b x = √a + √b x² = (√a + √b)² x² = (√a)² + 2.(√a).(√b) + (√b)² x² = a + 2.√(ab) + b x² = (a + b) + 2.√(ab) → by identification to (4 + √15) a + b = 4 2.√(ab) = √15 √(ab) = (1/2).√15 √(ab) = √[(1/4) * 15] ab = (1/4) * 15 ab = 15/4 Resume a + b = 4 ← this is the sum S ab = 15/4 ← this is the product P a & b are the solution of the equation: x² - Sx + P = 0 x² - 4x + (15/4) = 0 Δ = (- 4)² - [4 * (15/4)] = 16 - 15 = 1 x = (4 ± 1)/2 x = 5/2 ← this is a x = 3/2 ← this is b We can see that: [ √(3/2) + √(5/2) ]² = (3/2) + 2√[(3/2) * (5/2)] + (5/2) [ √(3/2) + √(5/2) ]² = (8/2) + 2√(15/4) [ √(3/2) + √(5/2) ]² = 4 + √15 Restart: = 4√(4 + √15) = 4√[ √(3/2) + √(5/2) ]² = 4.[√(3/2) + √(5/2)] = 4√(3/2) + 4√(5/2) = √(48/2) + √(80/2) = √24 + √40 = 2√6 + 2√10 = 2.(√6 + √10)

Умножить на 2 Sqrt (32/(8-2sqrt 15)) Таким образом 32=2*4^2 8-2sqrt 15=(sqrt 5-sqrt 3)^2 Извлечение квадратного корня 4 *sqr2 /(sqrt 5-sqrt 3) Избавиться от иррациональности в знаменателе 4 sqrt 2*(sqrt 5+sqrt3) /2=2 sqrt 10+2sqrt6 2 минуты, а не 8 как на видео

Бессмысленная задача, и никакой красоты в решении и ответа.Задача смотрится проще, чем ответ.

√[16/(4-√15)] =√[32/(8-2√15)] =√{32/[(√5)²-2√5•√3+(√3)²]} =√[32/(√5-√3)²] =4√2/(√5-√3) =4√2(√5+√3)/[(√5-√3)•(√5+√3)] =4√2(√5+√3)/2 =2√2(√5+√3)

Thank u ❤

that's funny, Harris begging for your hard earned cash at the beginning of this video, in an ad. I wouldn't show her the restroom if her hair was on fire.

Как же бесят переписывания по 100 раз одно и тоже

There is easier way to solve this bro U made it lengthy But nice try

also ich habe da 11 vor dem Komma, aber weil das natürlich zum Quadrat 121 ergibt, musste ich weiterrechnen, und kam auf 11,09. Wie ich darauf kam? Ich zog die Wurzel von 15 im Kopf, was mich zu 3,87 führte und subtrahierte und das brachte mich zu 13 / 100, wobei man ja dividiert, indem man mit dem Kehrwert multipliziert, sodass ich 1600 durch 13 hatte und das führt zu 123 und eben zu 11.09, so man die Wurzel zieht. Le p'tit Daniel

الجاواب النهائي مش مختصر نهائيا

7 minutes of my life just to see it wasn’t solved at all… go out and have a social life

Notnonly in your last Line but for example: SquareRoot of 4 could also be -2...so you lost some solutions...sorry